Differences between two pages while scraping with Beautiful Soup










0















I'm beginning with Python and Beautiful Soup and I'm scraping Google PlayStore and applications metadata in a JSON file. Here is my code :



def createjson(app_link):
url = 'https://play.google.com/store/apps/details?id=' + app_link
response = get(url)
html_soup = BeautifulSoup(response.text, 'html.parser')
bs = BeautifulSoup(response.text,"lxml")
result = [e.text for e in bs.find_all("div","class":"hAyfc")]
apptype = [e.text for e in bs.find_all("div","class":"hrTbp R8zArc")]

data =
data['appdata'] =

data['appdata'].append(
'name': html_soup.find(class_="AHFaub").text,
'updated': result[1][7:],
'apkSize': result[2][4:],
'offeredBy': result[9][10:],
'currentVersion': result[4][15:]
)
jsonfile = "allappsdata.json" #Get all the appS infos in one JSON
with open(jsonfile, 'a+') as outfile:
json.dump(data, outfile)


My 'result' variable looks for a string in a specific app page the problem is that Google is changing the order between two different pages. Sometimes result[1] is the application name, sometimes it's result[2]; Same problems for other metadata I need ('updated', 'apkSize', etc...) How can I deal with these changes. Is it possible to scrape in a different way? Thank you










share|improve this question


























    0















    I'm beginning with Python and Beautiful Soup and I'm scraping Google PlayStore and applications metadata in a JSON file. Here is my code :



    def createjson(app_link):
    url = 'https://play.google.com/store/apps/details?id=' + app_link
    response = get(url)
    html_soup = BeautifulSoup(response.text, 'html.parser')
    bs = BeautifulSoup(response.text,"lxml")
    result = [e.text for e in bs.find_all("div","class":"hAyfc")]
    apptype = [e.text for e in bs.find_all("div","class":"hrTbp R8zArc")]

    data =
    data['appdata'] =

    data['appdata'].append(
    'name': html_soup.find(class_="AHFaub").text,
    'updated': result[1][7:],
    'apkSize': result[2][4:],
    'offeredBy': result[9][10:],
    'currentVersion': result[4][15:]
    )
    jsonfile = "allappsdata.json" #Get all the appS infos in one JSON
    with open(jsonfile, 'a+') as outfile:
    json.dump(data, outfile)


    My 'result' variable looks for a string in a specific app page the problem is that Google is changing the order between two different pages. Sometimes result[1] is the application name, sometimes it's result[2]; Same problems for other metadata I need ('updated', 'apkSize', etc...) How can I deal with these changes. Is it possible to scrape in a different way? Thank you










    share|improve this question
























      0












      0








      0








      I'm beginning with Python and Beautiful Soup and I'm scraping Google PlayStore and applications metadata in a JSON file. Here is my code :



      def createjson(app_link):
      url = 'https://play.google.com/store/apps/details?id=' + app_link
      response = get(url)
      html_soup = BeautifulSoup(response.text, 'html.parser')
      bs = BeautifulSoup(response.text,"lxml")
      result = [e.text for e in bs.find_all("div","class":"hAyfc")]
      apptype = [e.text for e in bs.find_all("div","class":"hrTbp R8zArc")]

      data =
      data['appdata'] =

      data['appdata'].append(
      'name': html_soup.find(class_="AHFaub").text,
      'updated': result[1][7:],
      'apkSize': result[2][4:],
      'offeredBy': result[9][10:],
      'currentVersion': result[4][15:]
      )
      jsonfile = "allappsdata.json" #Get all the appS infos in one JSON
      with open(jsonfile, 'a+') as outfile:
      json.dump(data, outfile)


      My 'result' variable looks for a string in a specific app page the problem is that Google is changing the order between two different pages. Sometimes result[1] is the application name, sometimes it's result[2]; Same problems for other metadata I need ('updated', 'apkSize', etc...) How can I deal with these changes. Is it possible to scrape in a different way? Thank you










      share|improve this question














      I'm beginning with Python and Beautiful Soup and I'm scraping Google PlayStore and applications metadata in a JSON file. Here is my code :



      def createjson(app_link):
      url = 'https://play.google.com/store/apps/details?id=' + app_link
      response = get(url)
      html_soup = BeautifulSoup(response.text, 'html.parser')
      bs = BeautifulSoup(response.text,"lxml")
      result = [e.text for e in bs.find_all("div","class":"hAyfc")]
      apptype = [e.text for e in bs.find_all("div","class":"hrTbp R8zArc")]

      data =
      data['appdata'] =

      data['appdata'].append(
      'name': html_soup.find(class_="AHFaub").text,
      'updated': result[1][7:],
      'apkSize': result[2][4:],
      'offeredBy': result[9][10:],
      'currentVersion': result[4][15:]
      )
      jsonfile = "allappsdata.json" #Get all the appS infos in one JSON
      with open(jsonfile, 'a+') as outfile:
      json.dump(data, outfile)


      My 'result' variable looks for a string in a specific app page the problem is that Google is changing the order between two different pages. Sometimes result[1] is the application name, sometimes it's result[2]; Same problems for other metadata I need ('updated', 'apkSize', etc...) How can I deal with these changes. Is it possible to scrape in a different way? Thank you







      python beautifulsoup google-play






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 13 '18 at 21:21









      userHGuserHG

      1319




      1319






















          1 Answer
          1






          active

          oldest

          votes


















          1














          the problem is python loop is not ordered, save it as dict not list. Change your result = [e....] with



          result = 
          details = bs.find_all("div","class":"hAyfc")
          for item in details:
          label = item.findChild('div', 'class' : 'BgcNfc')
          value = item.findChild('span', 'class' : 'htlgb')
          result[label.text] = value.text


          also data['appdata']... with



          data['appdata'].append({
          'name': html_soup.find(class_="AHFaub").text,
          'updated': result['Updated'],
          'apkSize': result['Size'],
          'offeredBy': result['Offered By'],
          'currentVersion': result['Current Version']





          share|improve this answer























          • Great answer, thank you !

            – userHG
            Nov 14 '18 at 20:37










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          the problem is python loop is not ordered, save it as dict not list. Change your result = [e....] with



          result = 
          details = bs.find_all("div","class":"hAyfc")
          for item in details:
          label = item.findChild('div', 'class' : 'BgcNfc')
          value = item.findChild('span', 'class' : 'htlgb')
          result[label.text] = value.text


          also data['appdata']... with



          data['appdata'].append({
          'name': html_soup.find(class_="AHFaub").text,
          'updated': result['Updated'],
          'apkSize': result['Size'],
          'offeredBy': result['Offered By'],
          'currentVersion': result['Current Version']





          share|improve this answer























          • Great answer, thank you !

            – userHG
            Nov 14 '18 at 20:37















          1














          the problem is python loop is not ordered, save it as dict not list. Change your result = [e....] with



          result = 
          details = bs.find_all("div","class":"hAyfc")
          for item in details:
          label = item.findChild('div', 'class' : 'BgcNfc')
          value = item.findChild('span', 'class' : 'htlgb')
          result[label.text] = value.text


          also data['appdata']... with



          data['appdata'].append({
          'name': html_soup.find(class_="AHFaub").text,
          'updated': result['Updated'],
          'apkSize': result['Size'],
          'offeredBy': result['Offered By'],
          'currentVersion': result['Current Version']





          share|improve this answer























          • Great answer, thank you !

            – userHG
            Nov 14 '18 at 20:37













          1












          1








          1







          the problem is python loop is not ordered, save it as dict not list. Change your result = [e....] with



          result = 
          details = bs.find_all("div","class":"hAyfc")
          for item in details:
          label = item.findChild('div', 'class' : 'BgcNfc')
          value = item.findChild('span', 'class' : 'htlgb')
          result[label.text] = value.text


          also data['appdata']... with



          data['appdata'].append({
          'name': html_soup.find(class_="AHFaub").text,
          'updated': result['Updated'],
          'apkSize': result['Size'],
          'offeredBy': result['Offered By'],
          'currentVersion': result['Current Version']





          share|improve this answer













          the problem is python loop is not ordered, save it as dict not list. Change your result = [e....] with



          result = 
          details = bs.find_all("div","class":"hAyfc")
          for item in details:
          label = item.findChild('div', 'class' : 'BgcNfc')
          value = item.findChild('span', 'class' : 'htlgb')
          result[label.text] = value.text


          also data['appdata']... with



          data['appdata'].append({
          'name': html_soup.find(class_="AHFaub").text,
          'updated': result['Updated'],
          'apkSize': result['Size'],
          'offeredBy': result['Offered By'],
          'currentVersion': result['Current Version']






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 10:31









          ewwinkewwink

          11.9k22239




          11.9k22239












          • Great answer, thank you !

            – userHG
            Nov 14 '18 at 20:37

















          • Great answer, thank you !

            – userHG
            Nov 14 '18 at 20:37
















          Great answer, thank you !

          – userHG
          Nov 14 '18 at 20:37





          Great answer, thank you !

          – userHG
          Nov 14 '18 at 20:37



















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