How to add a bunch of defaults to python/django logging










0















I would like to add in the following for every log entry:



user
request_method
status


The only way I've seen to be able to do this is a bit of a hackish way, which is to pass them as args, because that's picked up by the django formatter (I don't see any place where you can pass kwargs -- https://docs.python.org/3/library/logging.html#formatter-objects). Here's an example:



log.info("hi", "user": str(request.user))


And the following formatter:



'format': '"message": "%(message)s", "extra": "%(args)s"',


When I parse the log I do something like this:



info = 
'message': message

data = ast.literal_eval(extra)
for k,v in extra.items():
info[k] = v


It seems pretty ghetto -- is there a better way to do this, for example, a way to get the kwargs in the formatter? When I try doing something like:



log.info("hi", extra = "user": str(request.user))


It either errors, or doesn't pass in the args (obviously).










share|improve this question


























    0















    I would like to add in the following for every log entry:



    user
    request_method
    status


    The only way I've seen to be able to do this is a bit of a hackish way, which is to pass them as args, because that's picked up by the django formatter (I don't see any place where you can pass kwargs -- https://docs.python.org/3/library/logging.html#formatter-objects). Here's an example:



    log.info("hi", "user": str(request.user))


    And the following formatter:



    'format': '"message": "%(message)s", "extra": "%(args)s"',


    When I parse the log I do something like this:



    info = 
    'message': message

    data = ast.literal_eval(extra)
    for k,v in extra.items():
    info[k] = v


    It seems pretty ghetto -- is there a better way to do this, for example, a way to get the kwargs in the formatter? When I try doing something like:



    log.info("hi", extra = "user": str(request.user))


    It either errors, or doesn't pass in the args (obviously).










    share|improve this question
























      0












      0








      0








      I would like to add in the following for every log entry:



      user
      request_method
      status


      The only way I've seen to be able to do this is a bit of a hackish way, which is to pass them as args, because that's picked up by the django formatter (I don't see any place where you can pass kwargs -- https://docs.python.org/3/library/logging.html#formatter-objects). Here's an example:



      log.info("hi", "user": str(request.user))


      And the following formatter:



      'format': '"message": "%(message)s", "extra": "%(args)s"',


      When I parse the log I do something like this:



      info = 
      'message': message

      data = ast.literal_eval(extra)
      for k,v in extra.items():
      info[k] = v


      It seems pretty ghetto -- is there a better way to do this, for example, a way to get the kwargs in the formatter? When I try doing something like:



      log.info("hi", extra = "user": str(request.user))


      It either errors, or doesn't pass in the args (obviously).










      share|improve this question














      I would like to add in the following for every log entry:



      user
      request_method
      status


      The only way I've seen to be able to do this is a bit of a hackish way, which is to pass them as args, because that's picked up by the django formatter (I don't see any place where you can pass kwargs -- https://docs.python.org/3/library/logging.html#formatter-objects). Here's an example:



      log.info("hi", "user": str(request.user))


      And the following formatter:



      'format': '"message": "%(message)s", "extra": "%(args)s"',


      When I parse the log I do something like this:



      info = 
      'message': message

      data = ast.literal_eval(extra)
      for k,v in extra.items():
      info[k] = v


      It seems pretty ghetto -- is there a better way to do this, for example, a way to get the kwargs in the formatter? When I try doing something like:



      log.info("hi", extra = "user": str(request.user))


      It either errors, or doesn't pass in the args (obviously).







      python django logging






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 21:50









      David LDavid L

      10616




      10616






















          1 Answer
          1






          active

          oldest

          votes


















          0














          I would do it by linking the request to the current thread of execution. Here's an example of how to do this:



          https://nedbatchelder.com/blog/201008/global_django_requests.html



          Then you can use get_request() in your logging handler to get the request, from which you can get the user. (I'm not sure what you mean by "status")






          share|improve this answer






















            Your Answer






            StackExchange.ifUsing("editor", function ()
            StackExchange.using("externalEditor", function ()
            StackExchange.using("snippets", function ()
            StackExchange.snippets.init();
            );
            );
            , "code-snippets");

            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "1"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290037%2fhow-to-add-a-bunch-of-defaults-to-python-django-logging%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            I would do it by linking the request to the current thread of execution. Here's an example of how to do this:



            https://nedbatchelder.com/blog/201008/global_django_requests.html



            Then you can use get_request() in your logging handler to get the request, from which you can get the user. (I'm not sure what you mean by "status")






            share|improve this answer



























              0














              I would do it by linking the request to the current thread of execution. Here's an example of how to do this:



              https://nedbatchelder.com/blog/201008/global_django_requests.html



              Then you can use get_request() in your logging handler to get the request, from which you can get the user. (I'm not sure what you mean by "status")






              share|improve this answer

























                0












                0








                0







                I would do it by linking the request to the current thread of execution. Here's an example of how to do this:



                https://nedbatchelder.com/blog/201008/global_django_requests.html



                Then you can use get_request() in your logging handler to get the request, from which you can get the user. (I'm not sure what you mean by "status")






                share|improve this answer













                I would do it by linking the request to the current thread of execution. Here's an example of how to do this:



                https://nedbatchelder.com/blog/201008/global_django_requests.html



                Then you can use get_request() in your logging handler to get the request, from which you can get the user. (I'm not sure what you mean by "status")







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 0:46









                Chris CurveyChris Curvey

                3,06642843




                3,06642843





























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290037%2fhow-to-add-a-bunch-of-defaults-to-python-django-logging%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Use pre created SQLite database for Android project in kotlin

                    Darth Vader #20

                    Ondo