Python Beautiful Soup print specific lines within multiline containing string
-1
How can I get/ print only the lines of a big multiline text within one <p> tag containing a certain string? On the website the lines are realized with <br> tags. There is no closing </p> tag.
Basic structure of the website:
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
...
Let's assume I want to get/ print only the lines containing the words "coffee and cookies". So, in this case only the first and third "line"/ sentence of this <p> should be printed.
I have Beautiful Soup 4.6.3 installed under Python 3.7.1.
findAll seems to be tag-orientated and return the whole <p>, right? So how can I realize it? Maybe with regex or other pattern?
python html web-scraping beautifulsoup screen-scraping
asked Nov 13 '18 at 11:07
user3087516user3087516
184
add a comment |
-1
How can I get/ print only the lines of a big multiline text within one <p> tag containing a certain string? On the website the lines are realized with <br> tags. There is no closing </p> tag.
Basic structure of the website:
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
...
Let's assume I want to get/ print only the lines containing the words "coffee and cookies". So, in this case only the first and third "line"/ sentence of this <p> should be printed.
I have Beautiful Soup 4.6.3 installed under Python 3.7.1.
findAll seems to be tag-orientated and return the whole <p>, right? So how can I realize it? Maybe with regex or other pattern?
python html web-scraping beautifulsoup screen-scraping
asked Nov 13 '18 at 11:07
user3087516user3087516
184
add a comment |
-1
-1
-1
How can I get/ print only the lines of a big multiline text within one <p> tag containing a certain string? On the website the lines are realized with <br> tags. There is no closing </p> tag.
Basic structure of the website:
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
...
Let's assume I want to get/ print only the lines containing the words "coffee and cookies". So, in this case only the first and third "line"/ sentence of this <p> should be printed.
I have Beautiful Soup 4.6.3 installed under Python 3.7.1.
findAll seems to be tag-orientated and return the whole <p>, right? So how can I realize it? Maybe with regex or other pattern?
python html web-scraping beautifulsoup screen-scraping
asked Nov 13 '18 at 11:07
user3087516user3087516
184
How can I get/ print only the lines of a big multiline text within one <p> tag containing a certain string? On the website the lines are realized with <br> tags. There is no closing </p> tag.
Basic structure of the website:
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
...
Let's assume I want to get/ print only the lines containing the words "coffee and cookies". So, in this case only the first and third "line"/ sentence of this <p> should be printed.
I have Beautiful Soup 4.6.3 installed under Python 3.7.1.
findAll seems to be tag-orientated and return the whole <p>, right? So how can I realize it? Maybe with regex or other pattern?
python html web-scraping beautifulsoup screen-scraping
python html web-scraping beautifulsoup screen-scraping
asked Nov 13 '18 at 11:07
user3087516user3087516
184
asked Nov 13 '18 at 11:07
user3087516user3087516
184
asked Nov 13 '18 at 11:07
user3087516user3087516
184
asked Nov 13 '18 at 11:07
user3087516user3087516
184
asked Nov 13 '18 at 11:07
user3087516user3087516
184
184
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
0
If I could understand your requirement correctly then the following snippet should get you there:
from bs4 import BeautifulSoup
htmlelem = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
if not "coffee and cookies" in paragraph.text:continue
print(paragraph.get_text(strip=True))
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
add a comment |
0
Can you split on n ?
from bs4 import BeautifulSoup
html = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
r1 = item.text.split('n')
for nextItem in r1:
if "coffee and cookies" in nextItem:
print(nextItem)
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
add a comment |
0
convert bs4.element to string using str() then you can compare it with "coffee and cookies"
from bs4 import BeautifulSoup
html_doc = """<p style="line-height: 150%">
I need a big cup of coffee and cookies. <a href="aaa">aa</a>
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>"""
soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')
for p in paragraph:
if 'coffee and cookies' in str(p):
next_is_a = p.find_next_sibling('a')
if next_is_a:
print(p.strip() + ' ' + str(next_is_a))
else:
print(p.strip())
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it returnI need a big cup of coffee and cookies.andI can't live without coffee and cookies.try it repl.it/repls/YouthfulRashInsurance
– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use.find_next_sibling()see above
– ewwink
Nov 20 '18 at 13:01
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
If I could understand your requirement correctly then the following snippet should get you there:
from bs4 import BeautifulSoup
htmlelem = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
if not "coffee and cookies" in paragraph.text:continue
print(paragraph.get_text(strip=True))
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
add a comment |
0
If I could understand your requirement correctly then the following snippet should get you there:
from bs4 import BeautifulSoup
htmlelem = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
if not "coffee and cookies" in paragraph.text:continue
print(paragraph.get_text(strip=True))
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
add a comment |
0
0
0
If I could understand your requirement correctly then the following snippet should get you there:
from bs4 import BeautifulSoup
htmlelem = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
if not "coffee and cookies" in paragraph.text:continue
print(paragraph.get_text(strip=True))
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
If I could understand your requirement correctly then the following snippet should get you there:
from bs4 import BeautifulSoup
htmlelem = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
if not "coffee and cookies" in paragraph.text:continue
print(paragraph.get_text(strip=True))
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
answered Nov 14 '18 at 13:10
SIMSIM
10.4k3743
10.4k3743
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
add a comment |
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
add a comment |
0
Can you split on n ?
from bs4 import BeautifulSoup
html = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
r1 = item.text.split('n')
for nextItem in r1:
if "coffee and cookies" in nextItem:
print(nextItem)
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
add a comment |
0
Can you split on n ?
from bs4 import BeautifulSoup
html = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
r1 = item.text.split('n')
for nextItem in r1:
if "coffee and cookies" in nextItem:
print(nextItem)
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
add a comment |
0
0
0
Can you split on n ?
from bs4 import BeautifulSoup
html = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
r1 = item.text.split('n')
for nextItem in r1:
if "coffee and cookies" in nextItem:
print(nextItem)
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
Can you split on n ?
from bs4 import BeautifulSoup
html = """
<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
"""
soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
r1 = item.text.split('n')
for nextItem in r1:
if "coffee and cookies" in nextItem:
print(nextItem)
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
answered Nov 14 '18 at 14:45
QHarrQHarr
32.1k82042
32.1k82042
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
add a comment |
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Thanks, for this example it also works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:55
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
Like soup.select('p,a') ? That would gather p and a tag elements.
– QHarr
Nov 20 '18 at 12:15
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
this prints only the text from a, right? What if I need also the href value?
– user3087516
Nov 20 '18 at 12:20
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
It will grab those elements then you would retrieve the href value from the a tag though it would be better to use soup.select('p, a[href]') stackoverflow.com/questions/1080411/…
– QHarr
Nov 20 '18 at 12:22
add a comment |
0
convert bs4.element to string using str() then you can compare it with "coffee and cookies"
from bs4 import BeautifulSoup
html_doc = """<p style="line-height: 150%">
I need a big cup of coffee and cookies. <a href="aaa">aa</a>
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>"""
soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')
for p in paragraph:
if 'coffee and cookies' in str(p):
next_is_a = p.find_next_sibling('a')
if next_is_a:
print(p.strip() + ' ' + str(next_is_a))
else:
print(p.strip())
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it returnI need a big cup of coffee and cookies.andI can't live without coffee and cookies.try it repl.it/repls/YouthfulRashInsurance
– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use.find_next_sibling()see above
– ewwink
Nov 20 '18 at 13:01
add a comment |
0
convert bs4.element to string using str() then you can compare it with "coffee and cookies"
from bs4 import BeautifulSoup
html_doc = """<p style="line-height: 150%">
I need a big cup of coffee and cookies. <a href="aaa">aa</a>
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>"""
soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')
for p in paragraph:
if 'coffee and cookies' in str(p):
next_is_a = p.find_next_sibling('a')
if next_is_a:
print(p.strip() + ' ' + str(next_is_a))
else:
print(p.strip())
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it returnI need a big cup of coffee and cookies.andI can't live without coffee and cookies.try it repl.it/repls/YouthfulRashInsurance
– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use.find_next_sibling()see above
– ewwink
Nov 20 '18 at 13:01
add a comment |
0
0
0
convert bs4.element to string using str() then you can compare it with "coffee and cookies"
from bs4 import BeautifulSoup
html_doc = """<p style="line-height: 150%">
I need a big cup of coffee and cookies. <a href="aaa">aa</a>
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>"""
soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')
for p in paragraph:
if 'coffee and cookies' in str(p):
next_is_a = p.find_next_sibling('a')
if next_is_a:
print(p.strip() + ' ' + str(next_is_a))
else:
print(p.strip())
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
convert bs4.element to string using str() then you can compare it with "coffee and cookies"
from bs4 import BeautifulSoup
html_doc = """<p style="line-height: 150%">
I need a big cup of coffee and cookies. <a href="aaa">aa</a>
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>"""
soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')
for p in paragraph:
if 'coffee and cookies' in str(p):
next_is_a = p.find_next_sibling('a')
if next_is_a:
print(p.strip() + ' ' + str(next_is_a))
else:
print(p.strip())
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
edited Nov 20 '18 at 13:00
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
answered Nov 13 '18 at 11:33
ewwinkewwink
11.8k22239
11.8k22239
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it returnI need a big cup of coffee and cookies.andI can't live without coffee and cookies.try it repl.it/repls/YouthfulRashInsurance
– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use.find_next_sibling()see above
– ewwink
Nov 20 '18 at 13:01
add a comment |
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it returnI need a big cup of coffee and cookies.andI can't live without coffee and cookies.try it repl.it/repls/YouthfulRashInsurance
– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use.find_next_sibling()see above
– ewwink
Nov 20 '18 at 13:01
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
I tried to use your code, the output is not the whole line but only: ) coffee and cookies
– user3087516
Nov 13 '18 at 12:58
it return
I need a big cup of coffee and cookies. and I can't live without coffee and cookies. try it repl.it/repls/YouthfulRashInsurance– ewwink
Nov 13 '18 at 13:28
it return
I need a big cup of coffee and cookies. and I can't live without coffee and cookies. try it repl.it/repls/YouthfulRashInsurance– ewwink
Nov 13 '18 at 13:28
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
Thanks, for this example it works. What if we also have an <a href="...">-tag in the same line and it should be also printed out?
– user3087516
Nov 20 '18 at 11:53
use
.find_next_sibling() see above– ewwink
Nov 20 '18 at 13:01
use
.find_next_sibling() see above– ewwink
Nov 20 '18 at 13:01
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