How do I zip a list and skip next in Kotlin?
I hope a list like [1,2,3,4,5]
would be [(1,2),(3,4),(5,0 or null)].
What operation should I use in Kotlin or Java.
And I tried zipWithNext, it will be [(1,2),(2,3),(3,4),(4,5)]
java kotlin
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
add a comment |
I hope a list like [1,2,3,4,5]
would be [(1,2),(3,4),(5,0 or null)].
What operation should I use in Kotlin or Java.
And I tried zipWithNext, it will be [(1,2),(2,3),(3,4),(4,5)]
java kotlin
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
add a comment |
I hope a list like [1,2,3,4,5]
would be [(1,2),(3,4),(5,0 or null)].
What operation should I use in Kotlin or Java.
And I tried zipWithNext, it will be [(1,2),(2,3),(3,4),(4,5)]
java kotlin
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
I hope a list like [1,2,3,4,5]
would be [(1,2),(3,4),(5,0 or null)].
What operation should I use in Kotlin or Java.
And I tried zipWithNext, it will be [(1,2),(2,3),(3,4),(4,5)]
java kotlin
java kotlin
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
edited Nov 14 '18 at 7:05
RainFool
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
asked Nov 14 '18 at 6:58
RainFoolRainFool
102110
102110
add a comment |
add a comment |
1 Answer
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chunked is the closest standard library function for this:
val list = listOf(1, 2, 3, 4, 5)
list.chunked(2) // [[1, 2], [3, 4], [5]]
If you need a 0 or null in the last chunk, I'd just pad the list accordingly before calling this function:
val list = listOf(1, 2, 3, 4, 5)
val paddedList = if (list.size % 2 == 0) list else (list + 0) // [1, 2, 3, 4, 5, 0]
paddedList.chunked(2) // [[1, 2], [3, 4], [5, 0]]
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
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chunked is the closest standard library function for this:
val list = listOf(1, 2, 3, 4, 5)
list.chunked(2) // [[1, 2], [3, 4], [5]]
If you need a 0 or null in the last chunk, I'd just pad the list accordingly before calling this function:
val list = listOf(1, 2, 3, 4, 5)
val paddedList = if (list.size % 2 == 0) list else (list + 0) // [1, 2, 3, 4, 5, 0]
paddedList.chunked(2) // [[1, 2], [3, 4], [5, 0]]
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
add a comment |
chunked is the closest standard library function for this:
val list = listOf(1, 2, 3, 4, 5)
list.chunked(2) // [[1, 2], [3, 4], [5]]
If you need a 0 or null in the last chunk, I'd just pad the list accordingly before calling this function:
val list = listOf(1, 2, 3, 4, 5)
val paddedList = if (list.size % 2 == 0) list else (list + 0) // [1, 2, 3, 4, 5, 0]
paddedList.chunked(2) // [[1, 2], [3, 4], [5, 0]]
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
add a comment |
chunked is the closest standard library function for this:
val list = listOf(1, 2, 3, 4, 5)
list.chunked(2) // [[1, 2], [3, 4], [5]]
If you need a 0 or null in the last chunk, I'd just pad the list accordingly before calling this function:
val list = listOf(1, 2, 3, 4, 5)
val paddedList = if (list.size % 2 == 0) list else (list + 0) // [1, 2, 3, 4, 5, 0]
paddedList.chunked(2) // [[1, 2], [3, 4], [5, 0]]
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
chunked is the closest standard library function for this:
val list = listOf(1, 2, 3, 4, 5)
list.chunked(2) // [[1, 2], [3, 4], [5]]
If you need a 0 or null in the last chunk, I'd just pad the list accordingly before calling this function:
val list = listOf(1, 2, 3, 4, 5)
val paddedList = if (list.size % 2 == 0) list else (list + 0) // [1, 2, 3, 4, 5, 0]
paddedList.chunked(2) // [[1, 2], [3, 4], [5, 0]]
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
answered Nov 14 '18 at 7:20
zsmb13zsmb13
40.4k78198
40.4k78198
add a comment |
add a comment |
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