How would I programmatically call an object method? Like MyObject.XVariable(//some function)

I have an object, that takes input from an API call to fill it up.

let MyDog = 
Name: 'Dog',

let arrayFunctions;
fetchDogsFunctions(dogAPIUrl).then(res => 
//results is an array that has a list of functions the dog has, like //getStats(), or walkDog()
arrayFunctions = res;
)

Now I want to map through the array results and call the function on my dog like...

arrayFunctions.map(item => 
 await MyDog.item(//Params)
)

How can I do this??

Where MyDog is set up from a file, and then depending on the array functions, for each function it programmatically fills in the call to the new function like MyDog.item where item is a variable in an array called "Walk()"

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

it is not clear what you want, why you are waiting to MyDog with await if it's object ?

– Artyom Amiryan
Nov 13 '18 at 7:52

add a comment |

I have an object, that takes input from an API call to fill it up.

let MyDog = 
Name: 'Dog',

let arrayFunctions;
fetchDogsFunctions(dogAPIUrl).then(res => 
//results is an array that has a list of functions the dog has, like //getStats(), or walkDog()
arrayFunctions = res;
)

Now I want to map through the array results and call the function on my dog like...

arrayFunctions.map(item => 
 await MyDog.item(//Params)
)

How can I do this??

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

it is not clear what you want, why you are waiting to MyDog with await if it's object ?

– Artyom Amiryan
Nov 13 '18 at 7:52

add a comment |

I have an object, that takes input from an API call to fill it up.

let MyDog = 
Name: 'Dog',

let arrayFunctions;
fetchDogsFunctions(dogAPIUrl).then(res => 
//results is an array that has a list of functions the dog has, like //getStats(), or walkDog()
arrayFunctions = res;
)

Now I want to map through the array results and call the function on my dog like...

arrayFunctions.map(item => 
 await MyDog.item(//Params)
)

How can I do this??

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

I have an object, that takes input from an API call to fill it up.

let MyDog = 
Name: 'Dog',

let arrayFunctions;
fetchDogsFunctions(dogAPIUrl).then(res => 
//results is an array that has a list of functions the dog has, like //getStats(), or walkDog()
arrayFunctions = res;
)

Now I want to map through the array results and call the function on my dog like...

arrayFunctions.map(item => 
 await MyDog.item(//Params)
)

How can I do this??

javascript arrays reactjs

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

edited Nov 13 '18 at 14:03

asked Nov 13 '18 at 7:41

Zach

204

asked Nov 13 '18 at 7:41

Zach

204

asked Nov 13 '18 at 7:41

Zach

204

it is not clear what you want, why you are waiting to MyDog with await if it's object ?

– Artyom Amiryan
Nov 13 '18 at 7:52

add a comment |

it is not clear what you want, why you are waiting to MyDog with await if it's object ?

– Artyom Amiryan
Nov 13 '18 at 7:52

it is not clear what you want, why you are waiting to MyDog with await if it's object ?

– Artyom Amiryan
Nov 13 '18 at 7:52

add a comment |

3 Answers
3

active

oldest

votes

I assumed how your data might have structured. Pls take a look below and you might get the idea of how to call functions dynamically using "await"

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

add a comment |

I can't see any property name "item" in your MyDog Object

answered Nov 13 '18 at 7:56

Haris

679

add a comment |

The answer is to do :

MyDog[item]()

within the loop.

I was asking the correct syntax to perform this operation

answered Nov 14 '18 at 5:51

Zach

204

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

I assumed how your data might have structured. Pls take a look below and you might get the idea of how to call functions dynamically using "await"

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

add a comment |

I assumed how your data might have structured. Pls take a look below and you might get the idea of how to call functions dynamically using "await"

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

add a comment |

I assumed how your data might have structured. Pls take a look below and you might get the idea of how to call functions dynamically using "await"

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

I assumed how your data might have structured. Pls take a look below and you might get the idea of how to call functions dynamically using "await"

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

const MyDog = 
 funA(a) return Promise.resolve('Function A called with parameter ' + a) 
 , funB(b) return Promise.resolve('Function B called with parameter ' + b) 


const arrayFunctions = ['funA', 'funB']

Promise.all(arrayFunctions.map(async (item, i) => 
 await MyDog[item](++i))
 )
.then(console.log)

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

answered Nov 13 '18 at 7:56

Nitish Narang

2,9601815

add a comment |

I can't see any property name "item" in your MyDog Object

answered Nov 13 '18 at 7:56

Haris

679

add a comment |

I can't see any property name "item" in your MyDog Object

answered Nov 13 '18 at 7:56

Haris

679

add a comment |

I can't see any property name "item" in your MyDog Object

answered Nov 13 '18 at 7:56

Haris

679

I can't see any property name "item" in your MyDog Object

answered Nov 13 '18 at 7:56

Haris

679

answered Nov 13 '18 at 7:56

Haris

679

answered Nov 13 '18 at 7:56

Haris

679

answered Nov 13 '18 at 7:56

Haris

679

add a comment |

The answer is to do :

MyDog[item]()

within the loop.

I was asking the correct syntax to perform this operation

answered Nov 14 '18 at 5:51

Zach

204

add a comment |

The answer is to do :

MyDog[item]()

within the loop.

I was asking the correct syntax to perform this operation

answered Nov 14 '18 at 5:51

Zach

204

add a comment |

The answer is to do :

MyDog[item]()

within the loop.

I was asking the correct syntax to perform this operation

answered Nov 14 '18 at 5:51

Zach

204

The answer is to do :

MyDog[item]()

within the loop.

I was asking the correct syntax to perform this operation

answered Nov 14 '18 at 5:51

Zach

204

answered Nov 14 '18 at 5:51

Zach

204

answered Nov 14 '18 at 5:51

Zach

204

answered Nov 14 '18 at 5:51

Zach

204

add a comment |

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