Zsh: source scripts recursively









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I have ~/scripts/ folder that contains multiple subfolders with arbitrary directory levels.



This folder only for scripts that need to be sourced when start zsh, how to recursively source all files under its folder and its subfolders in an short and effective way?










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    up vote
    5
    down vote

    favorite
    1












    I have ~/scripts/ folder that contains multiple subfolders with arbitrary directory levels.



    This folder only for scripts that need to be sourced when start zsh, how to recursively source all files under its folder and its subfolders in an short and effective way?










    share|improve this question























      up vote
      5
      down vote

      favorite
      1









      up vote
      5
      down vote

      favorite
      1






      1





      I have ~/scripts/ folder that contains multiple subfolders with arbitrary directory levels.



      This folder only for scripts that need to be sourced when start zsh, how to recursively source all files under its folder and its subfolders in an short and effective way?










      share|improve this question













      I have ~/scripts/ folder that contains multiple subfolders with arbitrary directory levels.



      This folder only for scripts that need to be sourced when start zsh, how to recursively source all files under its folder and its subfolders in an short and effective way?







      scripting zsh






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      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 9 at 14:12









      Tuyen Pham

      418111




      418111




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          7
          down vote



          accepted










          Sourcing all non-hidden regular files in there, in collation order:



          for f (~/scripts/**/*(N.)) . $f


          I would suggest however that you name those files using a specific template like with a .zsh extension (and use *.zsh instead of * above) to avoid problems if there are backup files lying about in there for instance.



          Or you could at least exclude some common ones like file~, file.dpkg-dist, file.back...:



          set -o extendedglob
          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak))(N.)) . $f


          etc.






          share|improve this answer






















          • for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
            – Tuyen Pham
            Nov 9 at 15:19






          • 3




            @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
            – JoL
            Nov 9 at 16:38











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          7
          down vote



          accepted










          Sourcing all non-hidden regular files in there, in collation order:



          for f (~/scripts/**/*(N.)) . $f


          I would suggest however that you name those files using a specific template like with a .zsh extension (and use *.zsh instead of * above) to avoid problems if there are backup files lying about in there for instance.



          Or you could at least exclude some common ones like file~, file.dpkg-dist, file.back...:



          set -o extendedglob
          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak))(N.)) . $f


          etc.






          share|improve this answer






















          • for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
            – Tuyen Pham
            Nov 9 at 15:19






          • 3




            @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
            – JoL
            Nov 9 at 16:38















          up vote
          7
          down vote



          accepted










          Sourcing all non-hidden regular files in there, in collation order:



          for f (~/scripts/**/*(N.)) . $f


          I would suggest however that you name those files using a specific template like with a .zsh extension (and use *.zsh instead of * above) to avoid problems if there are backup files lying about in there for instance.



          Or you could at least exclude some common ones like file~, file.dpkg-dist, file.back...:



          set -o extendedglob
          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak))(N.)) . $f


          etc.






          share|improve this answer






















          • for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
            – Tuyen Pham
            Nov 9 at 15:19






          • 3




            @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
            – JoL
            Nov 9 at 16:38













          up vote
          7
          down vote



          accepted







          up vote
          7
          down vote



          accepted






          Sourcing all non-hidden regular files in there, in collation order:



          for f (~/scripts/**/*(N.)) . $f


          I would suggest however that you name those files using a specific template like with a .zsh extension (and use *.zsh instead of * above) to avoid problems if there are backup files lying about in there for instance.



          Or you could at least exclude some common ones like file~, file.dpkg-dist, file.back...:



          set -o extendedglob
          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak))(N.)) . $f


          etc.






          share|improve this answer














          Sourcing all non-hidden regular files in there, in collation order:



          for f (~/scripts/**/*(N.)) . $f


          I would suggest however that you name those files using a specific template like with a .zsh extension (and use *.zsh instead of * above) to avoid problems if there are backup files lying about in there for instance.



          Or you could at least exclude some common ones like file~, file.dpkg-dist, file.back...:



          set -o extendedglob
          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak))(N.)) . $f


          etc.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 9 at 16:12

























          answered Nov 9 at 14:30









          Stéphane Chazelas

          293k54548889




          293k54548889











          • for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
            – Tuyen Pham
            Nov 9 at 15:19






          • 3




            @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
            – JoL
            Nov 9 at 16:38

















          • for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
            – Tuyen Pham
            Nov 9 at 15:19






          • 3




            @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
            – JoL
            Nov 9 at 16:38
















          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
          – Tuyen Pham
          Nov 9 at 15:19




          for f (~/scripts/**/^*("~"|dpkg-(dist|old|new)|.(tmp|back|bak)))(N.)) . $f. With .zsh means <..>s/**/^*.zsh("~"|dpkg<...>?
          – Tuyen Pham
          Nov 9 at 15:19




          3




          3




          @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
          – JoL
          Nov 9 at 16:38





          @TuyenPham No, there is no sense in combining them like that. It's about using a whitelist vs a blacklist. The whitelist is /*.zsh, and the blacklist is /^*("~"|dpkg<...>). It's safer to use a whitelist, but if you have naming requirements that don't allow for requiring files to end in .zsh, then you could at least opt for using a blacklist.
          – JoL
          Nov 9 at 16:38


















           

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