setting state with previous state and regex









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I don´t understand how this code works. How does it set the state using the regex? And most importantly, how does it know to set the state using the result variable?



handleClick(evt) 
const id = evt.target.id;
const result = evt.target.value;
this.setState(prevState => (
value: `$prevState.value$result`
.replace(/([/+-/*=])([/+-*=])/g, "$2")
.replace(/^0+(?=[1-9])/, "")
.replace(/^0+(?=.)/, "0")
.replace(/^0+B/, "")
));


}









share|improve this question



























    up vote
    0
    down vote

    favorite












    I don´t understand how this code works. How does it set the state using the regex? And most importantly, how does it know to set the state using the result variable?



    handleClick(evt) 
    const id = evt.target.id;
    const result = evt.target.value;
    this.setState(prevState => (
    value: `$prevState.value$result`
    .replace(/([/+-/*=])([/+-*=])/g, "$2")
    .replace(/^0+(?=[1-9])/, "")
    .replace(/^0+(?=.)/, "0")
    .replace(/^0+B/, "")
    ));


    }









    share|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I don´t understand how this code works. How does it set the state using the regex? And most importantly, how does it know to set the state using the result variable?



      handleClick(evt) 
      const id = evt.target.id;
      const result = evt.target.value;
      this.setState(prevState => (
      value: `$prevState.value$result`
      .replace(/([/+-/*=])([/+-*=])/g, "$2")
      .replace(/^0+(?=[1-9])/, "")
      .replace(/^0+(?=.)/, "0")
      .replace(/^0+B/, "")
      ));


      }









      share|improve this question















      I don´t understand how this code works. How does it set the state using the regex? And most importantly, how does it know to set the state using the result variable?



      handleClick(evt) 
      const id = evt.target.id;
      const result = evt.target.value;
      this.setState(prevState => (
      value: `$prevState.value$result`
      .replace(/([/+-/*=])([/+-*=])/g, "$2")
      .replace(/^0+(?=[1-9])/, "")
      .replace(/^0+(?=.)/, "0")
      .replace(/^0+B/, "")
      ));


      }






      javascript reactjs






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      edited Nov 20 at 12:05









      Martijn Pieters

      693k12924002237




      693k12924002237










      asked Nov 10 at 3:38







      user10564511





























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          So this code do the following:

          1. Concatenate prevState.value and evt.target.value into single string (learn more about ES6 Template literals)

          2. Replace all combinations like ++, +-, +*, +=, -+, --, -*, -=, *+, *-, **, *=, =+, =-, =*, == to it's second character (but I think there is error in the code, replace statement should be ([+-*=])([+-*=]), learn more about regex)

          3. Remove from string all number, that start with 0, like 0009, 01, etc.

          4. Remove all words, that start with 0, like 0a, 0000z, etc.

          5. Remove all 0 from string (learn more about B)

          6. Set result string to the state.value (learn more about React setState())






          share|improve this answer




















          • Thanks. Whats going me some trouble Is the concatenate bit.
            – user10564511
            Nov 10 at 5:14










          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          So this code do the following:

          1. Concatenate prevState.value and evt.target.value into single string (learn more about ES6 Template literals)

          2. Replace all combinations like ++, +-, +*, +=, -+, --, -*, -=, *+, *-, **, *=, =+, =-, =*, == to it's second character (but I think there is error in the code, replace statement should be ([+-*=])([+-*=]), learn more about regex)

          3. Remove from string all number, that start with 0, like 0009, 01, etc.

          4. Remove all words, that start with 0, like 0a, 0000z, etc.

          5. Remove all 0 from string (learn more about B)

          6. Set result string to the state.value (learn more about React setState())






          share|improve this answer




















          • Thanks. Whats going me some trouble Is the concatenate bit.
            – user10564511
            Nov 10 at 5:14














          up vote
          0
          down vote



          accepted










          So this code do the following:

          1. Concatenate prevState.value and evt.target.value into single string (learn more about ES6 Template literals)

          2. Replace all combinations like ++, +-, +*, +=, -+, --, -*, -=, *+, *-, **, *=, =+, =-, =*, == to it's second character (but I think there is error in the code, replace statement should be ([+-*=])([+-*=]), learn more about regex)

          3. Remove from string all number, that start with 0, like 0009, 01, etc.

          4. Remove all words, that start with 0, like 0a, 0000z, etc.

          5. Remove all 0 from string (learn more about B)

          6. Set result string to the state.value (learn more about React setState())






          share|improve this answer




















          • Thanks. Whats going me some trouble Is the concatenate bit.
            – user10564511
            Nov 10 at 5:14












          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          So this code do the following:

          1. Concatenate prevState.value and evt.target.value into single string (learn more about ES6 Template literals)

          2. Replace all combinations like ++, +-, +*, +=, -+, --, -*, -=, *+, *-, **, *=, =+, =-, =*, == to it's second character (but I think there is error in the code, replace statement should be ([+-*=])([+-*=]), learn more about regex)

          3. Remove from string all number, that start with 0, like 0009, 01, etc.

          4. Remove all words, that start with 0, like 0a, 0000z, etc.

          5. Remove all 0 from string (learn more about B)

          6. Set result string to the state.value (learn more about React setState())






          share|improve this answer












          So this code do the following:

          1. Concatenate prevState.value and evt.target.value into single string (learn more about ES6 Template literals)

          2. Replace all combinations like ++, +-, +*, +=, -+, --, -*, -=, *+, *-, **, *=, =+, =-, =*, == to it's second character (but I think there is error in the code, replace statement should be ([+-*=])([+-*=]), learn more about regex)

          3. Remove from string all number, that start with 0, like 0009, 01, etc.

          4. Remove all words, that start with 0, like 0a, 0000z, etc.

          5. Remove all 0 from string (learn more about B)

          6. Set result string to the state.value (learn more about React setState())







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 10 at 4:51









          baitun

          150110




          150110











          • Thanks. Whats going me some trouble Is the concatenate bit.
            – user10564511
            Nov 10 at 5:14
















          • Thanks. Whats going me some trouble Is the concatenate bit.
            – user10564511
            Nov 10 at 5:14















          Thanks. Whats going me some trouble Is the concatenate bit.
          – user10564511
          Nov 10 at 5:14




          Thanks. Whats going me some trouble Is the concatenate bit.
          – user10564511
          Nov 10 at 5:14

















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