find the the value of given bit in javascript
I have a test which I don't understand what I have to do maybe because I didn't work a lot with bits.
the test is this:
it('you should be able to find the value of a given bit', function()
expect(answers.valueAtBit(128, 8)).to.eql(1);
expect(answers.valueAtBit(65, 1)).to.eql(1);
expect(answers.valueAtBit(65, 7)).to.eql(1);
expect(answers.valueAtBit(128, 1)).to.eql(0);
);
and this is the function that they gave to me:
valueAtBit: function(num, bit)
,
In that function I have to return the value which has to match with the tests.
javascript testing bit
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
add a comment |
I have a test which I don't understand what I have to do maybe because I didn't work a lot with bits.
the test is this:
it('you should be able to find the value of a given bit', function()
expect(answers.valueAtBit(128, 8)).to.eql(1);
expect(answers.valueAtBit(65, 1)).to.eql(1);
expect(answers.valueAtBit(65, 7)).to.eql(1);
expect(answers.valueAtBit(128, 1)).to.eql(0);
);
and this is the function that they gave to me:
valueAtBit: function(num, bit)
,
In that function I have to return the value which has to match with the tests.
javascript testing bit
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
add a comment |
I have a test which I don't understand what I have to do maybe because I didn't work a lot with bits.
the test is this:
it('you should be able to find the value of a given bit', function()
expect(answers.valueAtBit(128, 8)).to.eql(1);
expect(answers.valueAtBit(65, 1)).to.eql(1);
expect(answers.valueAtBit(65, 7)).to.eql(1);
expect(answers.valueAtBit(128, 1)).to.eql(0);
);
and this is the function that they gave to me:
valueAtBit: function(num, bit)
,
In that function I have to return the value which has to match with the tests.
javascript testing bit
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
I have a test which I don't understand what I have to do maybe because I didn't work a lot with bits.
the test is this:
it('you should be able to find the value of a given bit', function()
expect(answers.valueAtBit(128, 8)).to.eql(1);
expect(answers.valueAtBit(65, 1)).to.eql(1);
expect(answers.valueAtBit(65, 7)).to.eql(1);
expect(answers.valueAtBit(128, 1)).to.eql(0);
);
and this is the function that they gave to me:
valueAtBit: function(num, bit)
,
In that function I have to return the value which has to match with the tests.
javascript testing bit
javascript testing bit
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
asked Nov 14 '18 at 1:30
promodominuspromodominus
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can convert integers to binary strings like:
let n = 11
let bin = n.toString(2)
console.log(bin)With that you just need to get the correct character. Assuming your counting from the right (and starting at 1) you can do:
function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisAnother option if you want to do the math is to divide by the number by 2**bit and take the mod:
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can convert integers to binary strings like:
let n = 11
let bin = n.toString(2)
console.log(bin)With that you just need to get the correct character. Assuming your counting from the right (and starting at 1) you can do:
function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisAnother option if you want to do the math is to divide by the number by 2**bit and take the mod:
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
add a comment |
You can convert integers to binary strings like:
let n = 11
let bin = n.toString(2)
console.log(bin)With that you just need to get the correct character. Assuming your counting from the right (and starting at 1) you can do:
function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisAnother option if you want to do the math is to divide by the number by 2**bit and take the mod:
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
add a comment |
You can convert integers to binary strings like:
let n = 11
let bin = n.toString(2)
console.log(bin)With that you just need to get the correct character. Assuming your counting from the right (and starting at 1) you can do:
function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisAnother option if you want to do the math is to divide by the number by 2**bit and take the mod:
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
You can convert integers to binary strings like:
let n = 11
let bin = n.toString(2)
console.log(bin)With that you just need to get the correct character. Assuming your counting from the right (and starting at 1) you can do:
function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisAnother option if you want to do the math is to divide by the number by 2**bit and take the mod:
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
let n = 11
let bin = n.toString(2)
console.log(bin)let n = 11
let bin = n.toString(2)
console.log(bin)function valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisfunction valueAtBit(num, bit)
n = num.toString(2)
return bit > n.length
? 0
: n.toString(2)[n.length - bit]
console.log(valueAtBit(11, 1))
console.log(valueAtBit(11, 2))
console.log(valueAtBit(11, 3))
console.log(valueAtBit(11, 4))
console.log(valueAtBit(11, 5)) // all zero after thisfunction valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
function valueAtBit(num, bit)
return Math.floor(num / (2 ** bit)) % 2
let num = 523
console.log("number in binary:", num.toString(2))
for (let i = 0; i < 10; i++)
console.log("bit: ", i, valueAtBit(num, i))
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
edited Nov 14 '18 at 3:35
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
answered Nov 14 '18 at 1:43
Mark MeyerMark Meyer
38.7k33159
38.7k33159
add a comment |
add a comment |
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