How to make CAST(datetime) SQL Server function using Python
I have an expression CAST(0x0000A95A00B97B34 AS DateTime) which is 2018-09-13 11:15:19.000. How to make this CAST manually with Python? I've figured out that first 8 digits in dec format is the number of days since 01.01.1900 but the time is wrong. Here is my cast function.
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16)
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(milliseconds=intTime)
return Date
print castDateTime('0x0000A95A00B97B34')
retrun: 2018-09-13 03:22:35.700000
actual value 2018-09-13 11:15:19.000
python
sql-server asked Nov 13 '18 at 23:13
KirillKirill
86
add a comment |
I have an expression CAST(0x0000A95A00B97B34 AS DateTime) which is 2018-09-13 11:15:19.000. How to make this CAST manually with Python? I've figured out that first 8 digits in dec format is the number of days since 01.01.1900 but the time is wrong. Here is my cast function.
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16)
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(milliseconds=intTime)
return Date
print castDateTime('0x0000A95A00B97B34')
retrun: 2018-09-13 03:22:35.700000
actual value 2018-09-13 11:15:19.000
python
sql-server asked Nov 13 '18 at 23:13
KirillKirill
86
add a comment |
I have an expression CAST(0x0000A95A00B97B34 AS DateTime) which is 2018-09-13 11:15:19.000. How to make this CAST manually with Python? I've figured out that first 8 digits in dec format is the number of days since 01.01.1900 but the time is wrong. Here is my cast function.
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16)
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(milliseconds=intTime)
return Date
print castDateTime('0x0000A95A00B97B34')
retrun: 2018-09-13 03:22:35.700000
actual value 2018-09-13 11:15:19.000
python
sql-server asked Nov 13 '18 at 23:13
KirillKirill
86
I have an expression CAST(0x0000A95A00B97B34 AS DateTime) which is 2018-09-13 11:15:19.000. How to make this CAST manually with Python? I've figured out that first 8 digits in dec format is the number of days since 01.01.1900 but the time is wrong. Here is my cast function.
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16)
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(milliseconds=intTime)
return Date
print castDateTime('0x0000A95A00B97B34')
retrun: 2018-09-13 03:22:35.700000
actual value 2018-09-13 11:15:19.000
python
sql-server python
sql-server asked Nov 13 '18 at 23:13
KirillKirill
86
asked Nov 13 '18 at 23:13
KirillKirill
86
asked Nov 13 '18 at 23:13
KirillKirill
86
asked Nov 13 '18 at 23:13
KirillKirill
86
asked Nov 13 '18 at 23:13
KirillKirill
86
86
add a comment |
add a comment |
1 Answer
1
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oldest
votes
As you've gathered, the first two bytes are the number of days since 1st Jan 1900; the last 2 bytes are then number of ticks since midnight, where 1 tick is equal to 1/300th of a second.
As such, the following should yield the correct result:
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16) / 300
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(seconds=intTime)
return Date
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
As you've gathered, the first two bytes are the number of days since 1st Jan 1900; the last 2 bytes are then number of ticks since midnight, where 1 tick is equal to 1/300th of a second.
As such, the following should yield the correct result:
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16) / 300
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(seconds=intTime)
return Date
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
add a comment |
As you've gathered, the first two bytes are the number of days since 1st Jan 1900; the last 2 bytes are then number of ticks since midnight, where 1 tick is equal to 1/300th of a second.
As such, the following should yield the correct result:
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16) / 300
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(seconds=intTime)
return Date
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
add a comment |
As you've gathered, the first two bytes are the number of days since 1st Jan 1900; the last 2 bytes are then number of ticks since midnight, where 1 tick is equal to 1/300th of a second.
As such, the following should yield the correct result:
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16) / 300
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(seconds=intTime)
return Date
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
As you've gathered, the first two bytes are the number of days since 1st Jan 1900; the last 2 bytes are then number of ticks since midnight, where 1 tick is equal to 1/300th of a second.
As such, the following should yield the correct result:
def castDateTime(hexVal):
hexDate = hexVal[2:10]
hexTime = hexVal[10:]
intDate = int(hexDate, 16)
intTime = int(hexTime, 16) / 300
Date = datetime.strptime("00:00:00", "%H:%M:%S") + timedelta(days=intDate) + timedelta(seconds=intTime)
return Date
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
answered Nov 13 '18 at 23:41
Lee MacLee Mac
4,56531541
4,56531541
add a comment |
add a comment |
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