Conversion of single string to list of strings when new strings are added
I can't find an answer.
I read a dictionary from file, it has a string value for a key.
Then I check if a new value is already in the dictionary, if it isn't then I want
to append it to the previous string and to get a list of values for a given key.
For example if I have a dictionary
dict = "vehicles": "car", "animals": "cat"
and the following condition is true
if "dog" not in dict["animals"]:
I'd like to get the output
dict = "vehicles": "car", "animals": ["cat", "dog"]
python string
add a comment |
I can't find an answer.
I read a dictionary from file, it has a string value for a key.
Then I check if a new value is already in the dictionary, if it isn't then I want
to append it to the previous string and to get a list of values for a given key.
For example if I have a dictionary
dict = "vehicles": "car", "animals": "cat"
and the following condition is true
if "dog" not in dict["animals"]:
I'd like to get the output
dict = "vehicles": "car", "animals": ["cat", "dog"]
python string
6
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, usingdict
as a var name is a bad idea, sincedict
is the dict class.
– Qwerty
Nov 14 '18 at 15:02
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20
add a comment |
I can't find an answer.
I read a dictionary from file, it has a string value for a key.
Then I check if a new value is already in the dictionary, if it isn't then I want
to append it to the previous string and to get a list of values for a given key.
For example if I have a dictionary
dict = "vehicles": "car", "animals": "cat"
and the following condition is true
if "dog" not in dict["animals"]:
I'd like to get the output
dict = "vehicles": "car", "animals": ["cat", "dog"]
python string
I can't find an answer.
I read a dictionary from file, it has a string value for a key.
Then I check if a new value is already in the dictionary, if it isn't then I want
to append it to the previous string and to get a list of values for a given key.
For example if I have a dictionary
dict = "vehicles": "car", "animals": "cat"
and the following condition is true
if "dog" not in dict["animals"]:
I'd like to get the output
dict = "vehicles": "car", "animals": ["cat", "dog"]
python string
python string
asked Nov 14 '18 at 14:58
James FlashJames Flash
406
406
6
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, usingdict
as a var name is a bad idea, sincedict
is the dict class.
– Qwerty
Nov 14 '18 at 15:02
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20
add a comment |
6
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, usingdict
as a var name is a bad idea, sincedict
is the dict class.
– Qwerty
Nov 14 '18 at 15:02
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20
6
6
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, using
dict
as a var name is a bad idea, since dict
is the dict class.– Qwerty
Nov 14 '18 at 15:02
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, using
dict
as a var name is a bad idea, since dict
is the dict class.– Qwerty
Nov 14 '18 at 15:02
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20
add a comment |
5 Answers
5
active
oldest
votes
Another way is to try append the element to the list and if it fails make the dictionary value a list:
dic = "vehicles": "car", "animals": "cat"
if "dog" not in dic["animals"]:
try:
dic["animals"].append("dog")
except:
dic["animals"] = [dic["animals"], "dog"]
Gives output:
'vehicles': 'car', 'animals': ['cat', 'dog']
In this way if you have a single element the except
part will be executed, making the value a list of string. If you then try to add another element it will be appended to the list.
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.append
will not work on strings, it will give you an exception, hence thetry/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
add a comment |
start with a dictionary with values as set
of strings
d = "vehicles": "car", "animals": "cat"
Then adding twice a new value only adds it once (and lookup is fast since it uses hashes):
d["animals"].add('dog')
d["animals"].add('dog')
>>> d
'animals': 'dog', 'cat', 'vehicles': 'car'
If you have the dictionary as input like in your question, you can transform it easily with values as set with dictionary comprehension like this:
loaded_d = "vehicles": "car", "animals": "cat" # dict just loaded from file
d = key:value for key,value in loaded_d.items()
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
add a comment |
>>> if "dog" not in dict["animals"]:
... dict["animals"] = [dict["animals"], "dog"]
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
add a comment |
Should be the easies way I think
dict = "vehicles": "car", "animals": "cat"
if "dog" not in dict["animals"]:
dict["animals"].add("dog")
add a comment |
You just need to update
animals list by using append
method.
dict = "vehicles": "car", "animals": "cat"
def appendItem(item):
if item not in dict["animals"]:
if not isinstance(dict["animals"], list):
dict["animals"] = [dict["animals"]]
dict["animals"].append(item)
appendItem("dog")
appendItem("dog")
appendItem("rabbit")
appendItem("cat")
Output
=> 'vehicles': 'car', 'animals': ['cat', 'dog', 'rabbit']
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another way is to try append the element to the list and if it fails make the dictionary value a list:
dic = "vehicles": "car", "animals": "cat"
if "dog" not in dic["animals"]:
try:
dic["animals"].append("dog")
except:
dic["animals"] = [dic["animals"], "dog"]
Gives output:
'vehicles': 'car', 'animals': ['cat', 'dog']
In this way if you have a single element the except
part will be executed, making the value a list of string. If you then try to add another element it will be appended to the list.
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.append
will not work on strings, it will give you an exception, hence thetry/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
add a comment |
Another way is to try append the element to the list and if it fails make the dictionary value a list:
dic = "vehicles": "car", "animals": "cat"
if "dog" not in dic["animals"]:
try:
dic["animals"].append("dog")
except:
dic["animals"] = [dic["animals"], "dog"]
Gives output:
'vehicles': 'car', 'animals': ['cat', 'dog']
In this way if you have a single element the except
part will be executed, making the value a list of string. If you then try to add another element it will be appended to the list.
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.append
will not work on strings, it will give you an exception, hence thetry/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
add a comment |
Another way is to try append the element to the list and if it fails make the dictionary value a list:
dic = "vehicles": "car", "animals": "cat"
if "dog" not in dic["animals"]:
try:
dic["animals"].append("dog")
except:
dic["animals"] = [dic["animals"], "dog"]
Gives output:
'vehicles': 'car', 'animals': ['cat', 'dog']
In this way if you have a single element the except
part will be executed, making the value a list of string. If you then try to add another element it will be appended to the list.
Another way is to try append the element to the list and if it fails make the dictionary value a list:
dic = "vehicles": "car", "animals": "cat"
if "dog" not in dic["animals"]:
try:
dic["animals"].append("dog")
except:
dic["animals"] = [dic["animals"], "dog"]
Gives output:
'vehicles': 'car', 'animals': ['cat', 'dog']
In this way if you have a single element the except
part will be executed, making the value a list of string. If you then try to add another element it will be appended to the list.
edited Nov 14 '18 at 15:15
answered Nov 14 '18 at 15:05
toti08toti08
1,78941623
1,78941623
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.append
will not work on strings, it will give you an exception, hence thetry/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
add a comment |
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.append
will not work on strings, it will give you an exception, hence thetry/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Thanks, but for me It gives 'vehicles': 'car', 'animals': [['cat'], 'dog']
– James Flash
Nov 14 '18 at 15:23
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Are you sure? It works properly for me, both in python 2 and 3...
– toti08
Nov 14 '18 at 15:31
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
Yeah it works, what is the difference from Jonathan R answer? Is it due to exception? Why does append() work with string here?
– James Flash
Nov 14 '18 at 15:35
1
1
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.
append
will not work on strings, it will give you an exception, hence the try/except
– toti08
Nov 14 '18 at 15:41
Jonathan answer will produce nested lists in case you append more than one item. Here it will not.
append
will not work on strings, it will give you an exception, hence the try/except
– toti08
Nov 14 '18 at 15:41
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
It is a tricky way , thanks
– James Flash
Nov 14 '18 at 15:46
add a comment |
start with a dictionary with values as set
of strings
d = "vehicles": "car", "animals": "cat"
Then adding twice a new value only adds it once (and lookup is fast since it uses hashes):
d["animals"].add('dog')
d["animals"].add('dog')
>>> d
'animals': 'dog', 'cat', 'vehicles': 'car'
If you have the dictionary as input like in your question, you can transform it easily with values as set with dictionary comprehension like this:
loaded_d = "vehicles": "car", "animals": "cat" # dict just loaded from file
d = key:value for key,value in loaded_d.items()
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
add a comment |
start with a dictionary with values as set
of strings
d = "vehicles": "car", "animals": "cat"
Then adding twice a new value only adds it once (and lookup is fast since it uses hashes):
d["animals"].add('dog')
d["animals"].add('dog')
>>> d
'animals': 'dog', 'cat', 'vehicles': 'car'
If you have the dictionary as input like in your question, you can transform it easily with values as set with dictionary comprehension like this:
loaded_d = "vehicles": "car", "animals": "cat" # dict just loaded from file
d = key:value for key,value in loaded_d.items()
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
add a comment |
start with a dictionary with values as set
of strings
d = "vehicles": "car", "animals": "cat"
Then adding twice a new value only adds it once (and lookup is fast since it uses hashes):
d["animals"].add('dog')
d["animals"].add('dog')
>>> d
'animals': 'dog', 'cat', 'vehicles': 'car'
If you have the dictionary as input like in your question, you can transform it easily with values as set with dictionary comprehension like this:
loaded_d = "vehicles": "car", "animals": "cat" # dict just loaded from file
d = key:value for key,value in loaded_d.items()
start with a dictionary with values as set
of strings
d = "vehicles": "car", "animals": "cat"
Then adding twice a new value only adds it once (and lookup is fast since it uses hashes):
d["animals"].add('dog')
d["animals"].add('dog')
>>> d
'animals': 'dog', 'cat', 'vehicles': 'car'
If you have the dictionary as input like in your question, you can transform it easily with values as set with dictionary comprehension like this:
loaded_d = "vehicles": "car", "animals": "cat" # dict just loaded from file
d = key:value for key,value in loaded_d.items()
edited Nov 14 '18 at 15:14
answered Nov 14 '18 at 15:02
Jean-François FabreJean-François Fabre
106k956115
106k956115
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
add a comment |
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
Ok, should I convert values to sets when I read a dictionary from a file?
– James Flash
Nov 14 '18 at 15:10
1
1
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
yes. I'll provide the way to do it, let me edit.
– Jean-François Fabre
Nov 14 '18 at 15:12
add a comment |
>>> if "dog" not in dict["animals"]:
... dict["animals"] = [dict["animals"], "dog"]
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
add a comment |
>>> if "dog" not in dict["animals"]:
... dict["animals"] = [dict["animals"], "dog"]
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
add a comment |
>>> if "dog" not in dict["animals"]:
... dict["animals"] = [dict["animals"], "dog"]
>>> if "dog" not in dict["animals"]:
... dict["animals"] = [dict["animals"], "dog"]
answered Nov 14 '18 at 15:00
Jonathan RJonathan R
1,162512
1,162512
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
add a comment |
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
3
3
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
try to add a third animal that will nest your list once more.
– Jean-François Fabre
Nov 14 '18 at 15:03
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
that's not in the problem statement
– Jonathan R
Nov 14 '18 at 15:04
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
Thanks. Yeah it would be good to append more strings and get just a list of strings as @ Jean-François Fabre noticed
– James Flash
Nov 14 '18 at 15:06
add a comment |
Should be the easies way I think
dict = "vehicles": "car", "animals": "cat"
if "dog" not in dict["animals"]:
dict["animals"].add("dog")
add a comment |
Should be the easies way I think
dict = "vehicles": "car", "animals": "cat"
if "dog" not in dict["animals"]:
dict["animals"].add("dog")
add a comment |
Should be the easies way I think
dict = "vehicles": "car", "animals": "cat"
if "dog" not in dict["animals"]:
dict["animals"].add("dog")
Should be the easies way I think
dict = "vehicles": "car", "animals": "cat"
if "dog" not in dict["animals"]:
dict["animals"].add("dog")
edited Nov 14 '18 at 15:16
answered Nov 14 '18 at 15:07
user3744881user3744881
514
514
add a comment |
add a comment |
You just need to update
animals list by using append
method.
dict = "vehicles": "car", "animals": "cat"
def appendItem(item):
if item not in dict["animals"]:
if not isinstance(dict["animals"], list):
dict["animals"] = [dict["animals"]]
dict["animals"].append(item)
appendItem("dog")
appendItem("dog")
appendItem("rabbit")
appendItem("cat")
Output
=> 'vehicles': 'car', 'animals': ['cat', 'dog', 'rabbit']
add a comment |
You just need to update
animals list by using append
method.
dict = "vehicles": "car", "animals": "cat"
def appendItem(item):
if item not in dict["animals"]:
if not isinstance(dict["animals"], list):
dict["animals"] = [dict["animals"]]
dict["animals"].append(item)
appendItem("dog")
appendItem("dog")
appendItem("rabbit")
appendItem("cat")
Output
=> 'vehicles': 'car', 'animals': ['cat', 'dog', 'rabbit']
add a comment |
You just need to update
animals list by using append
method.
dict = "vehicles": "car", "animals": "cat"
def appendItem(item):
if item not in dict["animals"]:
if not isinstance(dict["animals"], list):
dict["animals"] = [dict["animals"]]
dict["animals"].append(item)
appendItem("dog")
appendItem("dog")
appendItem("rabbit")
appendItem("cat")
Output
=> 'vehicles': 'car', 'animals': ['cat', 'dog', 'rabbit']
You just need to update
animals list by using append
method.
dict = "vehicles": "car", "animals": "cat"
def appendItem(item):
if item not in dict["animals"]:
if not isinstance(dict["animals"], list):
dict["animals"] = [dict["animals"]]
dict["animals"].append(item)
appendItem("dog")
appendItem("dog")
appendItem("rabbit")
appendItem("cat")
Output
=> 'vehicles': 'car', 'animals': ['cat', 'dog', 'rabbit']
edited Nov 14 '18 at 15:29
answered Nov 14 '18 at 15:00
Mihai Alexandru-IonutMihai Alexandru-Ionut
30.5k64175
30.5k64175
add a comment |
add a comment |
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6
Heres a few tips to know. Dicts are unordered, meaning they don't store the positions of the keys. Also, using
dict
as a var name is a bad idea, sincedict
is the dict class.– Qwerty
Nov 14 '18 at 15:02
@Qwerty, Is it true for json type in python?
– James Flash
Nov 14 '18 at 15:12
If you want order, I believe you are looking for an ordered dict, which I believe is in the collections library.
– Qwerty
Nov 14 '18 at 15:13
It is valuable remark, thanks
– James Flash
Nov 14 '18 at 15:20