Unique values count in a dataframe
2
I have data like this:
Date | Location | Item
-----------------------
1 | x | a
1 | x | b
1 | x | a
2 | b | a
and I'd like to extract unique values of rows and add a column for number of occurence
I tried this command but it failed:
p=df3.groupby(['date', 'location', 'item']).count()
Result=
Date | Location | Item | Occurences
------------------------------------
1 | x | a | 2
1 | x | b | 1
2 | b | a | 1
python dataframe pandas-groupby
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
add a comment |
2
I have data like this:
Date | Location | Item
-----------------------
1 | x | a
1 | x | b
1 | x | a
2 | b | a
and I'd like to extract unique values of rows and add a column for number of occurence
I tried this command but it failed:
p=df3.groupby(['date', 'location', 'item']).count()
Result=
Date | Location | Item | Occurences
------------------------------------
1 | x | a | 2
1 | x | b | 1
2 | b | a | 1
python dataframe pandas-groupby
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
perhaps.size()instead of.count()? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)
– Garrett
Nov 14 '18 at 13:45
add a comment |
2
2
2
I have data like this:
Date | Location | Item
-----------------------
1 | x | a
1 | x | b
1 | x | a
2 | b | a
and I'd like to extract unique values of rows and add a column for number of occurence
I tried this command but it failed:
p=df3.groupby(['date', 'location', 'item']).count()
Result=
Date | Location | Item | Occurences
------------------------------------
1 | x | a | 2
1 | x | b | 1
2 | b | a | 1
python dataframe pandas-groupby
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
I have data like this:
Date | Location | Item
-----------------------
1 | x | a
1 | x | b
1 | x | a
2 | b | a
and I'd like to extract unique values of rows and add a column for number of occurence
I tried this command but it failed:
p=df3.groupby(['date', 'location', 'item']).count()
Result=
Date | Location | Item | Occurences
------------------------------------
1 | x | a | 2
1 | x | b | 1
2 | b | a | 1
python dataframe pandas-groupby
python dataframe pandas-groupby
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
edited Nov 15 '18 at 10:38
Vadim Kotov
4,73163549
4,73163549
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
asked Nov 14 '18 at 11:57
Dr. knowDr. know
241
241
perhaps.size()instead of.count()? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)
– Garrett
Nov 14 '18 at 13:45
add a comment |
perhaps.size()instead of.count()? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)
– Garrett
Nov 14 '18 at 13:45
perhaps
.size() instead of .count() ? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)– Garrett
Nov 14 '18 at 13:45
perhaps
.size() instead of .count() ? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)– Garrett
Nov 14 '18 at 13:45
add a comment |
1 Answer
1
active
oldest
votes
0
Use .size():
df.groupby(['Date', 'Location', 'Item']).size().rename('Ocurrences').to_frame().reset_index()
Date Location Item Ocurrences
0 1 x a 2
1 1 x b 1
2 2 b a 1
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53299713%2funique-values-count-in-a-dataframe%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Use .size():
df.groupby(['Date', 'Location', 'Item']).size().rename('Ocurrences').to_frame().reset_index()
Date Location Item Ocurrences
0 1 x a 2
1 1 x b 1
2 2 b a 1
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
add a comment |
0
Use .size():
df.groupby(['Date', 'Location', 'Item']).size().rename('Ocurrences').to_frame().reset_index()
Date Location Item Ocurrences
0 1 x a 2
1 1 x b 1
2 2 b a 1
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
add a comment |
0
0
0
Use .size():
df.groupby(['Date', 'Location', 'Item']).size().rename('Ocurrences').to_frame().reset_index()
Date Location Item Ocurrences
0 1 x a 2
1 1 x b 1
2 2 b a 1
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
Use .size():
df.groupby(['Date', 'Location', 'Item']).size().rename('Ocurrences').to_frame().reset_index()
Date Location Item Ocurrences
0 1 x a 2
1 1 x b 1
2 2 b a 1
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
answered Nov 14 '18 at 15:29
Franco PiccoloFranco Piccolo
1,591716
1,591716
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53299713%2funique-values-count-in-a-dataframe%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
perhaps
.size()instead of.count()? (also, as a suggestion, including a small executable/code example would make it easier to follow what you've tried and what you're seeing.)– Garrett
Nov 14 '18 at 13:45