How add and remove array without re-index array key in JQuery
4
I have a list of the checkbox when clicking on any checkbox than new array append (push) in the main array. If uncheck than remove but not change any index for the current array.
explain:-
Like:- When I click on the first checkbox than array like
0: ["2"]
Like:- When I click on the second checkbox than array like
0: ["2"]
1: ["3"]
Like :- When I click on four checkbox than array like
0: ["2"]
1: ["3"]
2: ["5"]
after than uncheck checkbox if I uncheck first tthe han I needed array
1: ["3"]
2: ["5"]
again I click on first checkbox than need array link
1: ["3"]
2: ["5"]
3: ["2"]
Not need to change any array index key
https://jsfiddle.net/tx63yjhg/
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script>How I can remove array and add again??
javascript jquery html arrays
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
add a comment |
4
I have a list of the checkbox when clicking on any checkbox than new array append (push) in the main array. If uncheck than remove but not change any index for the current array.
explain:-
Like:- When I click on the first checkbox than array like
0: ["2"]
Like:- When I click on the second checkbox than array like
0: ["2"]
1: ["3"]
Like :- When I click on four checkbox than array like
0: ["2"]
1: ["3"]
2: ["5"]
after than uncheck checkbox if I uncheck first tthe han I needed array
1: ["3"]
2: ["5"]
again I click on first checkbox than need array link
1: ["3"]
2: ["5"]
3: ["2"]
Not need to change any array index key
https://jsfiddle.net/tx63yjhg/
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script>How I can remove array and add again??
javascript jquery html arrays
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
2
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,1: ["3"], 2: ["5"]. What shall be the value ofnew_value[0]
– Nikhil Aggarwal
Nov 14 '18 at 9:10
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
Look at this example -let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.
– Nikhil Aggarwal
Nov 14 '18 at 9:15
add a comment |
4
4
4
I have a list of the checkbox when clicking on any checkbox than new array append (push) in the main array. If uncheck than remove but not change any index for the current array.
explain:-
Like:- When I click on the first checkbox than array like
0: ["2"]
Like:- When I click on the second checkbox than array like
0: ["2"]
1: ["3"]
Like :- When I click on four checkbox than array like
0: ["2"]
1: ["3"]
2: ["5"]
after than uncheck checkbox if I uncheck first tthe han I needed array
1: ["3"]
2: ["5"]
again I click on first checkbox than need array link
1: ["3"]
2: ["5"]
3: ["2"]
Not need to change any array index key
https://jsfiddle.net/tx63yjhg/
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script>How I can remove array and add again??
javascript jquery html arrays
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
I have a list of the checkbox when clicking on any checkbox than new array append (push) in the main array. If uncheck than remove but not change any index for the current array.
explain:-
Like:- When I click on the first checkbox than array like
0: ["2"]
Like:- When I click on the second checkbox than array like
0: ["2"]
1: ["3"]
Like :- When I click on four checkbox than array like
0: ["2"]
1: ["3"]
2: ["5"]
after than uncheck checkbox if I uncheck first tthe han I needed array
1: ["3"]
2: ["5"]
again I click on first checkbox than need array link
1: ["3"]
2: ["5"]
3: ["2"]
Not need to change any array index key
https://jsfiddle.net/tx63yjhg/
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script>How I can remove array and add again??
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script><script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
else
//remove array when uncheck checkbox
console.log('new_value',new_value);
);
</script>javascript jquery html arrays
javascript jquery html arrays
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
asked Nov 14 '18 at 9:02
Praveen KumarPraveen Kumar
389315
389315
Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
2
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,1: ["3"], 2: ["5"]. What shall be the value ofnew_value[0]
– Nikhil Aggarwal
Nov 14 '18 at 9:10
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
Look at this example -let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.
– Nikhil Aggarwal
Nov 14 '18 at 9:15
add a comment |
Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
2
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,1: ["3"], 2: ["5"]. What shall be the value ofnew_value[0]
– Nikhil Aggarwal
Nov 14 '18 at 9:10
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
Look at this example -let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.
– Nikhil Aggarwal
Nov 14 '18 at 9:15
Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
2
2
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,
1: ["3"], 2: ["5"]. What shall be the value of new_value[0]– Nikhil Aggarwal
Nov 14 '18 at 9:10
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,
1: ["3"], 2: ["5"]. What shall be the value of new_value[0]– Nikhil Aggarwal
Nov 14 '18 at 9:10
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
Look at this example -
let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.– Nikhil Aggarwal
Nov 14 '18 at 9:15
Look at this example -
let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.– Nikhil Aggarwal
Nov 14 '18 at 9:15
add a comment |
2 Answers
2
active
oldest
votes
1
I am not sure whether you achieve the same using an array of arrays or not. You can instead try use an object like following.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>EDIT
For add
new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":474; // e.g. object
For remove
let valueToBeRemoved = 234; // e.g. value to be removed
Object.entries(new_value).forEach(([k,v]) =>
if(v.value === valueToBeRemoved) delete new_value[k];
)
EDIT 2
for (var k in new_value)
if(new_value[k].value === valueToBeRemoved) delete new_value[k];
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
|
show 4 more comments
-1
It easy:
var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
I am not sure whether you achieve the same using an array of arrays or not. You can instead try use an object like following.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>EDIT
For add
new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":474; // e.g. object
For remove
let valueToBeRemoved = 234; // e.g. value to be removed
Object.entries(new_value).forEach(([k,v]) =>
if(v.value === valueToBeRemoved) delete new_value[k];
)
EDIT 2
for (var k in new_value)
if(new_value[k].value === valueToBeRemoved) delete new_value[k];
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
|
show 4 more comments
1
I am not sure whether you achieve the same using an array of arrays or not. You can instead try use an object like following.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>EDIT
For add
new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":474; // e.g. object
For remove
let valueToBeRemoved = 234; // e.g. value to be removed
Object.entries(new_value).forEach(([k,v]) =>
if(v.value === valueToBeRemoved) delete new_value[k];
)
EDIT 2
for (var k in new_value)
if(new_value[k].value === valueToBeRemoved) delete new_value[k];
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
|
show 4 more comments
1
1
1
I am not sure whether you achieve the same using an array of arrays or not. You can instead try use an object like following.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>EDIT
For add
new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":474; // e.g. object
For remove
let valueToBeRemoved = 234; // e.g. value to be removed
Object.entries(new_value).forEach(([k,v]) =>
if(v.value === valueToBeRemoved) delete new_value[k];
)
EDIT 2
for (var k in new_value)
if(new_value[k].value === valueToBeRemoved) delete new_value[k];
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
I am not sure whether you achieve the same using an array of arrays or not. You can instead try use an object like following.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>EDIT
For add
new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":474; // e.g. object
For remove
let valueToBeRemoved = 234; // e.g. value to be removed
Object.entries(new_value).forEach(([k,v]) =>
if(v.value === valueToBeRemoved) delete new_value[k];
)
EDIT 2
for (var k in new_value)
if(new_value[k].value === valueToBeRemoved) delete new_value[k];
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script><script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" value="1" />
<input type="checkbox" value="2" />
<input type="checkbox" value="3" />
<input type="checkbox" value="4" />
<input type="checkbox" value="5" />
<input type="checkbox" value="6" />
<input type="checkbox" value="7" />
<script type="text/javascript">
var values = ;
var new_value = ;
var counter = 0;
$("input").on("change", function()
var $this = $(this);
if ($this.is(":checked"))
new_value[counter++] = [$this.val()];
else
Object.entries(new_value).forEach(([k,v]) =>
if(v.includes($this.val())) delete new_value[k];
);
console.log('new_value',new_value);
);
</script>answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
edited Dec 4 '18 at 18:07
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
answered Nov 14 '18 at 9:05
Nikhil AggarwalNikhil Aggarwal
24.1k32748
24.1k32748
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
|
show 4 more comments
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
If array value like this than ?? new_value[counter++] = id1: 100, id2: 200, "id3": 300,"value":value474;
– Praveen Kumar
Nov 14 '18 at 10:11
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
@PraveenKumar - You can do it. However, we will need to update our delete code. Which property of the object defines the uniqueness of the object?
– Nikhil Aggarwal
Nov 14 '18 at 10:14
1
1
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
@PraveenKumar - I have updated my answer with add / edit block. Can you please check
– Nikhil Aggarwal
Nov 14 '18 at 10:22
1
1
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
Nikhil Aggarwal :- Thank you for the update answer
– Praveen Kumar
Nov 14 '18 at 10:25
1
1
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
@PraveenKumar - Glad to help you :)
– Nikhil Aggarwal
Nov 14 '18 at 10:26
|
show 4 more comments
-1
It easy:
var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
add a comment |
-1
It easy:
var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
add a comment |
-1
-1
-1
It easy:
var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
It easy:
var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);var values = ;
$("input").on("change", function()
var $this = $(this);
var new_value = ;
if ($this.is(":checked"))
var new_data = [$this.val()];
new_value.push(new_data);
console.log('new_value',new_value);
);answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
answered Nov 14 '18 at 9:07
Ramas WinRamas Win
71
71
add a comment |
add a comment |
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Why are you having array of arrays? Why not a simple flattened array instead?
– Nikhil Aggarwal
Nov 14 '18 at 9:04
@NikhilAggarwal :- I have multiple values in the array so I need array inside array
– Praveen Kumar
Nov 14 '18 at 9:05
2
Okay. Can you post the realistic array then. In the example posted above after removing value you expect array to be,
1: ["3"], 2: ["5"]. What shall be the value ofnew_value[0]– Nikhil Aggarwal
Nov 14 '18 at 9:10
@NikhilAggarwal : If remove 0 index than 0 index is removed and this key does not assign any array index
– Praveen Kumar
Nov 14 '18 at 9:13
Look at this example -
let arr = [1,2]; delete arr[0]; console.log(arr);. See the array index is still there with an empty value.– Nikhil Aggarwal
Nov 14 '18 at 9:15