How can I sum multiple columns in a spark dataframe in pyspark?










1















I've got a list of column names i want to sum



columns = ['col1','col2','col3']


How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)



Dataframe with result i want:



col1 col2 col3 result
1 2 3 6


Thanks !










share|improve this question
























  • Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

    – Prasad Khode
    Nov 14 '18 at 10:23











  • Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

    – Manrique
    Nov 14 '18 at 10:33















1















I've got a list of column names i want to sum



columns = ['col1','col2','col3']


How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)



Dataframe with result i want:



col1 col2 col3 result
1 2 3 6


Thanks !










share|improve this question
























  • Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

    – Prasad Khode
    Nov 14 '18 at 10:23











  • Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

    – Manrique
    Nov 14 '18 at 10:33













1












1








1


1






I've got a list of column names i want to sum



columns = ['col1','col2','col3']


How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)



Dataframe with result i want:



col1 col2 col3 result
1 2 3 6


Thanks !










share|improve this question
















I've got a list of column names i want to sum



columns = ['col1','col2','col3']


How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)



Dataframe with result i want:



col1 col2 col3 result
1 2 3 6


Thanks !







python apache-spark pyspark






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 17:24







Manrique

















asked Nov 14 '18 at 10:21









ManriqueManrique

522315




522315












  • Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

    – Prasad Khode
    Nov 14 '18 at 10:23











  • Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

    – Manrique
    Nov 14 '18 at 10:33

















  • Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

    – Prasad Khode
    Nov 14 '18 at 10:23











  • Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

    – Manrique
    Nov 14 '18 at 10:33
















Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

– Prasad Khode
Nov 14 '18 at 10:23





Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?

– Prasad Khode
Nov 14 '18 at 10:23













Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

– Manrique
Nov 14 '18 at 10:33





Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.

– Manrique
Nov 14 '18 at 10:33












2 Answers
2






active

oldest

votes


















1














Try this:



df = df.withColumn('result', sum(df[col] for col in df.columns))


df.columns will be list of columns from df.






share|improve this answer























  • I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

    – vikrant rana
    Dec 4 '18 at 14:38


















0














[Editing to explain each step]



If you have static list of columns, you can do this:



df.withColumn("result", col("col1") + col("col2") + col("col3"))



But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3") iteratively. For this, you can use the reduce method with add function to get this:



reduce(add, [col(x) for x in df.columns])



The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3") instead of col("col1") + col("col2") + col("col3"). But the effect would be same.



The col(x) ensures that you are getting col(col("col1") + col("col2")) + col("col3") instead of a simple string concat (which generates (col1col2col3).



[TL;DR,]



Combining the above steps, you can do this:



from functools import reduce
from operator import add
from pyspark.sql.functions import col

df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))


The df.na.fill(0) portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:



df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))






share|improve this answer
























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Try this:



    df = df.withColumn('result', sum(df[col] for col in df.columns))


    df.columns will be list of columns from df.






    share|improve this answer























    • I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

      – vikrant rana
      Dec 4 '18 at 14:38















    1














    Try this:



    df = df.withColumn('result', sum(df[col] for col in df.columns))


    df.columns will be list of columns from df.






    share|improve this answer























    • I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

      – vikrant rana
      Dec 4 '18 at 14:38













    1












    1








    1







    Try this:



    df = df.withColumn('result', sum(df[col] for col in df.columns))


    df.columns will be list of columns from df.






    share|improve this answer













    Try this:



    df = df.withColumn('result', sum(df[col] for col in df.columns))


    df.columns will be list of columns from df.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 14 '18 at 10:25









    Mayank PorwalMayank Porwal

    4,9702724




    4,9702724












    • I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

      – vikrant rana
      Dec 4 '18 at 14:38

















    • I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

      – vikrant rana
      Dec 4 '18 at 14:38
















    I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

    – vikrant rana
    Dec 4 '18 at 14:38





    I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??

    – vikrant rana
    Dec 4 '18 at 14:38













    0














    [Editing to explain each step]



    If you have static list of columns, you can do this:



    df.withColumn("result", col("col1") + col("col2") + col("col3"))



    But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3") iteratively. For this, you can use the reduce method with add function to get this:



    reduce(add, [col(x) for x in df.columns])



    The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3") instead of col("col1") + col("col2") + col("col3"). But the effect would be same.



    The col(x) ensures that you are getting col(col("col1") + col("col2")) + col("col3") instead of a simple string concat (which generates (col1col2col3).



    [TL;DR,]



    Combining the above steps, you can do this:



    from functools import reduce
    from operator import add
    from pyspark.sql.functions import col

    df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))


    The df.na.fill(0) portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:



    df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))






    share|improve this answer





























      0














      [Editing to explain each step]



      If you have static list of columns, you can do this:



      df.withColumn("result", col("col1") + col("col2") + col("col3"))



      But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3") iteratively. For this, you can use the reduce method with add function to get this:



      reduce(add, [col(x) for x in df.columns])



      The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3") instead of col("col1") + col("col2") + col("col3"). But the effect would be same.



      The col(x) ensures that you are getting col(col("col1") + col("col2")) + col("col3") instead of a simple string concat (which generates (col1col2col3).



      [TL;DR,]



      Combining the above steps, you can do this:



      from functools import reduce
      from operator import add
      from pyspark.sql.functions import col

      df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))


      The df.na.fill(0) portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:



      df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))






      share|improve this answer



























        0












        0








        0







        [Editing to explain each step]



        If you have static list of columns, you can do this:



        df.withColumn("result", col("col1") + col("col2") + col("col3"))



        But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3") iteratively. For this, you can use the reduce method with add function to get this:



        reduce(add, [col(x) for x in df.columns])



        The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3") instead of col("col1") + col("col2") + col("col3"). But the effect would be same.



        The col(x) ensures that you are getting col(col("col1") + col("col2")) + col("col3") instead of a simple string concat (which generates (col1col2col3).



        [TL;DR,]



        Combining the above steps, you can do this:



        from functools import reduce
        from operator import add
        from pyspark.sql.functions import col

        df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))


        The df.na.fill(0) portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:



        df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))






        share|improve this answer















        [Editing to explain each step]



        If you have static list of columns, you can do this:



        df.withColumn("result", col("col1") + col("col2") + col("col3"))



        But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3") iteratively. For this, you can use the reduce method with add function to get this:



        reduce(add, [col(x) for x in df.columns])



        The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3") instead of col("col1") + col("col2") + col("col3"). But the effect would be same.



        The col(x) ensures that you are getting col(col("col1") + col("col2")) + col("col3") instead of a simple string concat (which generates (col1col2col3).



        [TL;DR,]



        Combining the above steps, you can do this:



        from functools import reduce
        from operator import add
        from pyspark.sql.functions import col

        df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))


        The df.na.fill(0) portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:



        df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Jan 22 at 5:45

























        answered Jan 21 at 5:36









        Dileep Kumar PatchigollaDileep Kumar Patchigolla

        404620




        404620



























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