How can I sum multiple columns in a spark dataframe in pyspark?
I've got a list of column names i want to sum
columns = ['col1','col2','col3']
How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)
Dataframe with result i want:
col1 col2 col3 result
1 2 3 6
Thanks !
python apache-spark pyspark
add a comment |
I've got a list of column names i want to sum
columns = ['col1','col2','col3']
How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)
Dataframe with result i want:
col1 col2 col3 result
1 2 3 6
Thanks !
python apache-spark pyspark
Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33
add a comment |
I've got a list of column names i want to sum
columns = ['col1','col2','col3']
How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)
Dataframe with result i want:
col1 col2 col3 result
1 2 3 6
Thanks !
python apache-spark pyspark
I've got a list of column names i want to sum
columns = ['col1','col2','col3']
How can i add the three and put it in a new column ? (in an automatic way, so that i can change the column list and have new results)
Dataframe with result i want:
col1 col2 col3 result
1 2 3 6
Thanks !
python apache-spark pyspark
python apache-spark pyspark
edited Nov 14 '18 at 17:24
Manrique
asked Nov 14 '18 at 10:21
ManriqueManrique
522315
522315
Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33
add a comment |
Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33
Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33
add a comment |
2 Answers
2
active
oldest
votes
Try this:
df = df.withColumn('result', sum(df[col] for col in df.columns))
df.columns
will be list of columns from df.
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
add a comment |
[Editing to explain each step]
If you have static list of columns, you can do this:
df.withColumn("result", col("col1") + col("col2") + col("col3"))
But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3")
iteratively. For this, you can use the reduce
method with add
function to get this:
reduce(add, [col(x) for x in df.columns])
The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3")
instead of col("col1") + col("col2") + col("col3")
. But the effect would be same.
The col(x)
ensures that you are getting col(col("col1") + col("col2")) + col("col3")
instead of a simple string concat (which generates (col1col2col3
).
[TL;DR,]
Combining the above steps, you can do this:
from functools import reduce
from operator import add
from pyspark.sql.functions import col
df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
The df.na.fill(0)
portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:
df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this:
df = df.withColumn('result', sum(df[col] for col in df.columns))
df.columns
will be list of columns from df.
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
add a comment |
Try this:
df = df.withColumn('result', sum(df[col] for col in df.columns))
df.columns
will be list of columns from df.
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
add a comment |
Try this:
df = df.withColumn('result', sum(df[col] for col in df.columns))
df.columns
will be list of columns from df.
Try this:
df = df.withColumn('result', sum(df[col] for col in df.columns))
df.columns
will be list of columns from df.
answered Nov 14 '18 at 10:25
Mayank PorwalMayank Porwal
4,9702724
4,9702724
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
add a comment |
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
I have replicate the same with below dataframe and getting an error: listA = [(10,20,40,60),(10,10,10,40)] df = spark.createDataFrame(listA, ['M1','M2','M3','M4']) newdf = df.withColumn('result', sum(df[col] for col in df.columns)) Please see below error. TypeError: 'Column' object is not callable. Am I missing something??
– vikrant rana
Dec 4 '18 at 14:38
add a comment |
[Editing to explain each step]
If you have static list of columns, you can do this:
df.withColumn("result", col("col1") + col("col2") + col("col3"))
But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3")
iteratively. For this, you can use the reduce
method with add
function to get this:
reduce(add, [col(x) for x in df.columns])
The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3")
instead of col("col1") + col("col2") + col("col3")
. But the effect would be same.
The col(x)
ensures that you are getting col(col("col1") + col("col2")) + col("col3")
instead of a simple string concat (which generates (col1col2col3
).
[TL;DR,]
Combining the above steps, you can do this:
from functools import reduce
from operator import add
from pyspark.sql.functions import col
df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
The df.na.fill(0)
portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:
df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
add a comment |
[Editing to explain each step]
If you have static list of columns, you can do this:
df.withColumn("result", col("col1") + col("col2") + col("col3"))
But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3")
iteratively. For this, you can use the reduce
method with add
function to get this:
reduce(add, [col(x) for x in df.columns])
The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3")
instead of col("col1") + col("col2") + col("col3")
. But the effect would be same.
The col(x)
ensures that you are getting col(col("col1") + col("col2")) + col("col3")
instead of a simple string concat (which generates (col1col2col3
).
[TL;DR,]
Combining the above steps, you can do this:
from functools import reduce
from operator import add
from pyspark.sql.functions import col
df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
The df.na.fill(0)
portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:
df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
add a comment |
[Editing to explain each step]
If you have static list of columns, you can do this:
df.withColumn("result", col("col1") + col("col2") + col("col3"))
But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3")
iteratively. For this, you can use the reduce
method with add
function to get this:
reduce(add, [col(x) for x in df.columns])
The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3")
instead of col("col1") + col("col2") + col("col3")
. But the effect would be same.
The col(x)
ensures that you are getting col(col("col1") + col("col2")) + col("col3")
instead of a simple string concat (which generates (col1col2col3
).
[TL;DR,]
Combining the above steps, you can do this:
from functools import reduce
from operator import add
from pyspark.sql.functions import col
df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
The df.na.fill(0)
portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:
df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
[Editing to explain each step]
If you have static list of columns, you can do this:
df.withColumn("result", col("col1") + col("col2") + col("col3"))
But if you don't want to type the whole columns list, you need to generate the phrase col("col1") + col("col2") + col("col3")
iteratively. For this, you can use the reduce
method with add
function to get this:
reduce(add, [col(x) for x in df.columns])
The columns are added two at a time, so you would get col(col("col1") + col("col2")) + col("col3")
instead of col("col1") + col("col2") + col("col3")
. But the effect would be same.
The col(x)
ensures that you are getting col(col("col1") + col("col2")) + col("col3")
instead of a simple string concat (which generates (col1col2col3
).
[TL;DR,]
Combining the above steps, you can do this:
from functools import reduce
from operator import add
from pyspark.sql.functions import col
df.na.fill(0).withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
The df.na.fill(0)
portion is to handle nulls in your data. If you don't have any nulls, you can skip that and do this instead:
df.withColumn("result" ,reduce(add, [col(x) for x in df.columns]))
edited Jan 22 at 5:45
answered Jan 21 at 5:36
Dileep Kumar PatchigollaDileep Kumar Patchigolla
404620
404620
add a comment |
add a comment |
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Possible duplicate of How do I add a new column to a Spark DataFrame (using PySpark)?
– Prasad Khode
Nov 14 '18 at 10:23
Thanks for answering ! I know how to add columns, i just want an efficient way to add them based on a list with column names.
– Manrique
Nov 14 '18 at 10:33