Picking the smallest value in a list using recursion









up vote
1
down vote

favorite












This is a function I defined in order to find the smallest value in a list using recursion.However,I called the function twice within itself, which I think it's a bit weird.
Is there a way around the function append()?. We haven't studied it yet so I'm asking whether there could be a simpler way to get the same solution by not using append()?



def minimum(lst):
"""
parameters : lst of type list
return : the value of the smallest element in the lst
"""
if len(lst) == 1:
return lst[0]

if lst[0] < lst[1]:
lst.append(lst[0])
return(minimum(lst[1:]))
return(minimum(lst[1:]))









share|improve this question























  • It is not proper at all for a function like minimum to alter its argument...
    – Antti Haapala
    Nov 10 at 21:59










  • Just do the append and don't do the return
    – Peter Wood
    Nov 10 at 21:59














up vote
1
down vote

favorite












This is a function I defined in order to find the smallest value in a list using recursion.However,I called the function twice within itself, which I think it's a bit weird.
Is there a way around the function append()?. We haven't studied it yet so I'm asking whether there could be a simpler way to get the same solution by not using append()?



def minimum(lst):
"""
parameters : lst of type list
return : the value of the smallest element in the lst
"""
if len(lst) == 1:
return lst[0]

if lst[0] < lst[1]:
lst.append(lst[0])
return(minimum(lst[1:]))
return(minimum(lst[1:]))









share|improve this question























  • It is not proper at all for a function like minimum to alter its argument...
    – Antti Haapala
    Nov 10 at 21:59










  • Just do the append and don't do the return
    – Peter Wood
    Nov 10 at 21:59












up vote
1
down vote

favorite









up vote
1
down vote

favorite











This is a function I defined in order to find the smallest value in a list using recursion.However,I called the function twice within itself, which I think it's a bit weird.
Is there a way around the function append()?. We haven't studied it yet so I'm asking whether there could be a simpler way to get the same solution by not using append()?



def minimum(lst):
"""
parameters : lst of type list
return : the value of the smallest element in the lst
"""
if len(lst) == 1:
return lst[0]

if lst[0] < lst[1]:
lst.append(lst[0])
return(minimum(lst[1:]))
return(minimum(lst[1:]))









share|improve this question















This is a function I defined in order to find the smallest value in a list using recursion.However,I called the function twice within itself, which I think it's a bit weird.
Is there a way around the function append()?. We haven't studied it yet so I'm asking whether there could be a simpler way to get the same solution by not using append()?



def minimum(lst):
"""
parameters : lst of type list
return : the value of the smallest element in the lst
"""
if len(lst) == 1:
return lst[0]

if lst[0] < lst[1]:
lst.append(lst[0])
return(minimum(lst[1:]))
return(minimum(lst[1:]))






python list recursion






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 21:58

























asked Nov 10 at 21:52







user10158754


















  • It is not proper at all for a function like minimum to alter its argument...
    – Antti Haapala
    Nov 10 at 21:59










  • Just do the append and don't do the return
    – Peter Wood
    Nov 10 at 21:59
















  • It is not proper at all for a function like minimum to alter its argument...
    – Antti Haapala
    Nov 10 at 21:59










  • Just do the append and don't do the return
    – Peter Wood
    Nov 10 at 21:59















It is not proper at all for a function like minimum to alter its argument...
– Antti Haapala
Nov 10 at 21:59




It is not proper at all for a function like minimum to alter its argument...
– Antti Haapala
Nov 10 at 21:59












Just do the append and don't do the return
– Peter Wood
Nov 10 at 21:59




Just do the append and don't do the return
– Peter Wood
Nov 10 at 21:59












5 Answers
5






active

oldest

votes

















up vote
3
down vote



accepted










I guess you could do this to avoid append:



def minimum(lst):

if len(lst)==1:
return lst[0]

if lst[0] < lst[1]:
return minimum(lst[0:1]+ lst[2:])
else:
return minimum(lst[1:])


but i think this one is better with only one call to minimum:



def minimum(lst): 
if len(lst) == 1:
return lst[0]
s = minimum(lst[1:])

return s if s < lst[0] else lst[0]





share|improve this answer






















  • return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
    – user10158754
    Nov 10 at 22:13










  • no, they are not
    – Christian Sloper
    Nov 10 at 22:13






  • 1




    one is a list of one integer ex: [1], the other an integer ex: 1
    – Christian Sloper
    Nov 10 at 22:14










  • important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
    – Christian Sloper
    Nov 10 at 22:15

















up vote
1
down vote













Use an additional variable?



def minimum(lst, current_min=None):
if not lst:
return current_min
if current_min is None:
current_min = lst[0]
elif lst[0] < current_min:
current_min = lst[0]
return minimum(lst[1:], current_min)





share|improve this answer



























    up vote
    1
    down vote













    Here's a very explicit version that should be easy to read due to comments and variable names.



    def minimum(lst):
    # base case
    if len(lst) == 1:
    return lst[0]

    # get first element and minimum of remaining list
    first = lst[0]
    rest = lst[1:]
    min_of_rest = minimum(rest)

    # return the smaller one of those two values
    if first < min_of_rest:
    return first
    else:
    return min_of_rest





    share|improve this answer



























      up vote
      -1
      down vote













      You can use the following program:



      def minimum(lst):
      """
      parameters : lst of type list
      return : the value of the smallest element in the lst
      """
      if len(lst) == 1:
      return lst[0]
      temp_min = minimum(lst[1:])
      if lst[0] < temp_min:
      return lst[0]
      else:
      return temp_min





      share|improve this answer






















      • I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
        – Christian Sloper
        Nov 10 at 22:01











      • @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
        – ask
        Nov 10 at 22:03


















      up vote
      -1
      down vote













      If your task is simply to find the smallest value in a list with any given length, I don't exactly know why you are using recursion. There are more efficient ways to do this such as built-in functions of Python. For example:



      def smallest(list):
      return min(list)
      list_of_ints = [4,2,7,6,8,1,5,9,2]
      print(smallest(list_of_ints))


      This will print out 1.






      share|improve this answer






















      • the min function is better than sorting? so if you want to use built in functions go with min(list)
        – Christian Sloper
        Nov 10 at 22:16










      • sorting is O(n log n) , min function is O(n)
        – Christian Sloper
        Nov 10 at 22:16










      Your Answer






      StackExchange.ifUsing("editor", function ()
      StackExchange.using("externalEditor", function ()
      StackExchange.using("snippets", function ()
      StackExchange.snippets.init();
      );
      );
      , "code-snippets");

      StackExchange.ready(function()
      var channelOptions =
      tags: "".split(" "),
      id: "1"
      ;
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function()
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled)
      StackExchange.using("snippets", function()
      createEditor();
      );

      else
      createEditor();

      );

      function createEditor()
      StackExchange.prepareEditor(
      heartbeatType: 'answer',
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader:
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      ,
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      );



      );













      draft saved

      draft discarded


















      StackExchange.ready(
      function ()
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243766%2fpicking-the-smallest-value-in-a-list-using-recursion%23new-answer', 'question_page');

      );

      Post as a guest















      Required, but never shown
























      5 Answers
      5






      active

      oldest

      votes








      5 Answers
      5






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      I guess you could do this to avoid append:



      def minimum(lst):

      if len(lst)==1:
      return lst[0]

      if lst[0] < lst[1]:
      return minimum(lst[0:1]+ lst[2:])
      else:
      return minimum(lst[1:])


      but i think this one is better with only one call to minimum:



      def minimum(lst): 
      if len(lst) == 1:
      return lst[0]
      s = minimum(lst[1:])

      return s if s < lst[0] else lst[0]





      share|improve this answer






















      • return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
        – user10158754
        Nov 10 at 22:13










      • no, they are not
        – Christian Sloper
        Nov 10 at 22:13






      • 1




        one is a list of one integer ex: [1], the other an integer ex: 1
        – Christian Sloper
        Nov 10 at 22:14










      • important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
        – Christian Sloper
        Nov 10 at 22:15














      up vote
      3
      down vote



      accepted










      I guess you could do this to avoid append:



      def minimum(lst):

      if len(lst)==1:
      return lst[0]

      if lst[0] < lst[1]:
      return minimum(lst[0:1]+ lst[2:])
      else:
      return minimum(lst[1:])


      but i think this one is better with only one call to minimum:



      def minimum(lst): 
      if len(lst) == 1:
      return lst[0]
      s = minimum(lst[1:])

      return s if s < lst[0] else lst[0]





      share|improve this answer






















      • return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
        – user10158754
        Nov 10 at 22:13










      • no, they are not
        – Christian Sloper
        Nov 10 at 22:13






      • 1




        one is a list of one integer ex: [1], the other an integer ex: 1
        – Christian Sloper
        Nov 10 at 22:14










      • important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
        – Christian Sloper
        Nov 10 at 22:15












      up vote
      3
      down vote



      accepted







      up vote
      3
      down vote



      accepted






      I guess you could do this to avoid append:



      def minimum(lst):

      if len(lst)==1:
      return lst[0]

      if lst[0] < lst[1]:
      return minimum(lst[0:1]+ lst[2:])
      else:
      return minimum(lst[1:])


      but i think this one is better with only one call to minimum:



      def minimum(lst): 
      if len(lst) == 1:
      return lst[0]
      s = minimum(lst[1:])

      return s if s < lst[0] else lst[0]





      share|improve this answer














      I guess you could do this to avoid append:



      def minimum(lst):

      if len(lst)==1:
      return lst[0]

      if lst[0] < lst[1]:
      return minimum(lst[0:1]+ lst[2:])
      else:
      return minimum(lst[1:])


      but i think this one is better with only one call to minimum:



      def minimum(lst): 
      if len(lst) == 1:
      return lst[0]
      s = minimum(lst[1:])

      return s if s < lst[0] else lst[0]






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 10 at 22:07









      coldspeed

      115k18105182




      115k18105182










      answered Nov 10 at 21:55









      Christian Sloper

      1,058213




      1,058213











      • return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
        – user10158754
        Nov 10 at 22:13










      • no, they are not
        – Christian Sloper
        Nov 10 at 22:13






      • 1




        one is a list of one integer ex: [1], the other an integer ex: 1
        – Christian Sloper
        Nov 10 at 22:14










      • important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
        – Christian Sloper
        Nov 10 at 22:15
















      • return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
        – user10158754
        Nov 10 at 22:13










      • no, they are not
        – Christian Sloper
        Nov 10 at 22:13






      • 1




        one is a list of one integer ex: [1], the other an integer ex: 1
        – Christian Sloper
        Nov 10 at 22:14










      • important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
        – Christian Sloper
        Nov 10 at 22:15















      return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
      – user10158754
      Nov 10 at 22:13




      return minimum(lst[0:1]+ lst[2:]) isn't lst[0:1] and lst[0] one and the same ?
      – user10158754
      Nov 10 at 22:13












      no, they are not
      – Christian Sloper
      Nov 10 at 22:13




      no, they are not
      – Christian Sloper
      Nov 10 at 22:13




      1




      1




      one is a list of one integer ex: [1], the other an integer ex: 1
      – Christian Sloper
      Nov 10 at 22:14




      one is a list of one integer ex: [1], the other an integer ex: 1
      – Christian Sloper
      Nov 10 at 22:14












      important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
      – Christian Sloper
      Nov 10 at 22:15




      important here as [1] + 2 is not allowed, while [1] + [2] gives [1,2]
      – Christian Sloper
      Nov 10 at 22:15












      up vote
      1
      down vote













      Use an additional variable?



      def minimum(lst, current_min=None):
      if not lst:
      return current_min
      if current_min is None:
      current_min = lst[0]
      elif lst[0] < current_min:
      current_min = lst[0]
      return minimum(lst[1:], current_min)





      share|improve this answer
























        up vote
        1
        down vote













        Use an additional variable?



        def minimum(lst, current_min=None):
        if not lst:
        return current_min
        if current_min is None:
        current_min = lst[0]
        elif lst[0] < current_min:
        current_min = lst[0]
        return minimum(lst[1:], current_min)





        share|improve this answer






















          up vote
          1
          down vote










          up vote
          1
          down vote









          Use an additional variable?



          def minimum(lst, current_min=None):
          if not lst:
          return current_min
          if current_min is None:
          current_min = lst[0]
          elif lst[0] < current_min:
          current_min = lst[0]
          return minimum(lst[1:], current_min)





          share|improve this answer












          Use an additional variable?



          def minimum(lst, current_min=None):
          if not lst:
          return current_min
          if current_min is None:
          current_min = lst[0]
          elif lst[0] < current_min:
          current_min = lst[0]
          return minimum(lst[1:], current_min)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 10 at 22:02









          roeen30

          43629




          43629




















              up vote
              1
              down vote













              Here's a very explicit version that should be easy to read due to comments and variable names.



              def minimum(lst):
              # base case
              if len(lst) == 1:
              return lst[0]

              # get first element and minimum of remaining list
              first = lst[0]
              rest = lst[1:]
              min_of_rest = minimum(rest)

              # return the smaller one of those two values
              if first < min_of_rest:
              return first
              else:
              return min_of_rest





              share|improve this answer
























                up vote
                1
                down vote













                Here's a very explicit version that should be easy to read due to comments and variable names.



                def minimum(lst):
                # base case
                if len(lst) == 1:
                return lst[0]

                # get first element and minimum of remaining list
                first = lst[0]
                rest = lst[1:]
                min_of_rest = minimum(rest)

                # return the smaller one of those two values
                if first < min_of_rest:
                return first
                else:
                return min_of_rest





                share|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Here's a very explicit version that should be easy to read due to comments and variable names.



                  def minimum(lst):
                  # base case
                  if len(lst) == 1:
                  return lst[0]

                  # get first element and minimum of remaining list
                  first = lst[0]
                  rest = lst[1:]
                  min_of_rest = minimum(rest)

                  # return the smaller one of those two values
                  if first < min_of_rest:
                  return first
                  else:
                  return min_of_rest





                  share|improve this answer












                  Here's a very explicit version that should be easy to read due to comments and variable names.



                  def minimum(lst):
                  # base case
                  if len(lst) == 1:
                  return lst[0]

                  # get first element and minimum of remaining list
                  first = lst[0]
                  rest = lst[1:]
                  min_of_rest = minimum(rest)

                  # return the smaller one of those two values
                  if first < min_of_rest:
                  return first
                  else:
                  return min_of_rest






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 10 at 22:05









                  timgeb

                  48.1k116390




                  48.1k116390




















                      up vote
                      -1
                      down vote













                      You can use the following program:



                      def minimum(lst):
                      """
                      parameters : lst of type list
                      return : the value of the smallest element in the lst
                      """
                      if len(lst) == 1:
                      return lst[0]
                      temp_min = minimum(lst[1:])
                      if lst[0] < temp_min:
                      return lst[0]
                      else:
                      return temp_min





                      share|improve this answer






















                      • I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                        – Christian Sloper
                        Nov 10 at 22:01











                      • @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                        – ask
                        Nov 10 at 22:03















                      up vote
                      -1
                      down vote













                      You can use the following program:



                      def minimum(lst):
                      """
                      parameters : lst of type list
                      return : the value of the smallest element in the lst
                      """
                      if len(lst) == 1:
                      return lst[0]
                      temp_min = minimum(lst[1:])
                      if lst[0] < temp_min:
                      return lst[0]
                      else:
                      return temp_min





                      share|improve this answer






















                      • I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                        – Christian Sloper
                        Nov 10 at 22:01











                      • @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                        – ask
                        Nov 10 at 22:03













                      up vote
                      -1
                      down vote










                      up vote
                      -1
                      down vote









                      You can use the following program:



                      def minimum(lst):
                      """
                      parameters : lst of type list
                      return : the value of the smallest element in the lst
                      """
                      if len(lst) == 1:
                      return lst[0]
                      temp_min = minimum(lst[1:])
                      if lst[0] < temp_min:
                      return lst[0]
                      else:
                      return temp_min





                      share|improve this answer














                      You can use the following program:



                      def minimum(lst):
                      """
                      parameters : lst of type list
                      return : the value of the smallest element in the lst
                      """
                      if len(lst) == 1:
                      return lst[0]
                      temp_min = minimum(lst[1:])
                      if lst[0] < temp_min:
                      return lst[0]
                      else:
                      return temp_min






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Nov 10 at 22:12

























                      answered Nov 10 at 21:59









                      ask

                      727




                      727











                      • I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                        – Christian Sloper
                        Nov 10 at 22:01











                      • @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                        – ask
                        Nov 10 at 22:03

















                      • I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                        – Christian Sloper
                        Nov 10 at 22:01











                      • @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                        – ask
                        Nov 10 at 22:03
















                      I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                      – Christian Sloper
                      Nov 10 at 22:01





                      I struggled if it was ok to use "min" or not :-) return min(lst) is awfully tempting then :-) (not me that downvoted)
                      – Christian Sloper
                      Nov 10 at 22:01













                      @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                      – ask
                      Nov 10 at 22:03





                      @ChristianSloper You are right sir. I missed that, I should have used if condition. And yes, Sorry I did not see that you have answered correct while I was writing my answer. :-(
                      – ask
                      Nov 10 at 22:03











                      up vote
                      -1
                      down vote













                      If your task is simply to find the smallest value in a list with any given length, I don't exactly know why you are using recursion. There are more efficient ways to do this such as built-in functions of Python. For example:



                      def smallest(list):
                      return min(list)
                      list_of_ints = [4,2,7,6,8,1,5,9,2]
                      print(smallest(list_of_ints))


                      This will print out 1.






                      share|improve this answer






















                      • the min function is better than sorting? so if you want to use built in functions go with min(list)
                        – Christian Sloper
                        Nov 10 at 22:16










                      • sorting is O(n log n) , min function is O(n)
                        – Christian Sloper
                        Nov 10 at 22:16














                      up vote
                      -1
                      down vote













                      If your task is simply to find the smallest value in a list with any given length, I don't exactly know why you are using recursion. There are more efficient ways to do this such as built-in functions of Python. For example:



                      def smallest(list):
                      return min(list)
                      list_of_ints = [4,2,7,6,8,1,5,9,2]
                      print(smallest(list_of_ints))


                      This will print out 1.






                      share|improve this answer






















                      • the min function is better than sorting? so if you want to use built in functions go with min(list)
                        – Christian Sloper
                        Nov 10 at 22:16










                      • sorting is O(n log n) , min function is O(n)
                        – Christian Sloper
                        Nov 10 at 22:16












                      up vote
                      -1
                      down vote










                      up vote
                      -1
                      down vote









                      If your task is simply to find the smallest value in a list with any given length, I don't exactly know why you are using recursion. There are more efficient ways to do this such as built-in functions of Python. For example:



                      def smallest(list):
                      return min(list)
                      list_of_ints = [4,2,7,6,8,1,5,9,2]
                      print(smallest(list_of_ints))


                      This will print out 1.






                      share|improve this answer














                      If your task is simply to find the smallest value in a list with any given length, I don't exactly know why you are using recursion. There are more efficient ways to do this such as built-in functions of Python. For example:



                      def smallest(list):
                      return min(list)
                      list_of_ints = [4,2,7,6,8,1,5,9,2]
                      print(smallest(list_of_ints))


                      This will print out 1.







                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Nov 10 at 22:37

























                      answered Nov 10 at 22:10









                      john doe

                      14




                      14











                      • the min function is better than sorting? so if you want to use built in functions go with min(list)
                        – Christian Sloper
                        Nov 10 at 22:16










                      • sorting is O(n log n) , min function is O(n)
                        – Christian Sloper
                        Nov 10 at 22:16
















                      • the min function is better than sorting? so if you want to use built in functions go with min(list)
                        – Christian Sloper
                        Nov 10 at 22:16










                      • sorting is O(n log n) , min function is O(n)
                        – Christian Sloper
                        Nov 10 at 22:16















                      the min function is better than sorting? so if you want to use built in functions go with min(list)
                      – Christian Sloper
                      Nov 10 at 22:16




                      the min function is better than sorting? so if you want to use built in functions go with min(list)
                      – Christian Sloper
                      Nov 10 at 22:16












                      sorting is O(n log n) , min function is O(n)
                      – Christian Sloper
                      Nov 10 at 22:16




                      sorting is O(n log n) , min function is O(n)
                      – Christian Sloper
                      Nov 10 at 22:16

















                      draft saved

                      draft discarded
















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid


                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.

                      To learn more, see our tips on writing great answers.





                      Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                      Please pay close attention to the following guidance:


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid


                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.

                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function ()
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243766%2fpicking-the-smallest-value-in-a-list-using-recursion%23new-answer', 'question_page');

                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Darth Vader #20

                      How to how show current date and time by default on contact form 7 in WordPress without taking input from user in datetimepicker

                      Ondo