Unhandled promise rejection?









up vote
4
down vote

favorite












This example (repl.it) (from this answer) looks to me like it follows all the rules regarding promises. Yet running it logs an exception regarding an unhandled promise rejection with the associated console message. (This also happens in FF, Chrome, and Node v10.)



The try/catch block is clearly there and wraps the rejected promise, so what's going on and how would I fix it?





async function example() 
const start = Date.now()
let i = 0
function res(n)
const id = ++i
return new Promise((resolve, reject) =>
setTimeout(() =>
resolve()
console.log(`res #$id called after $n milliseconds`, Date.now() - start)
, n)
)


function rej(n)
const id = ++i
return new Promise((resolve, reject) =>
setTimeout(() =>
reject()
console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
, n)
)


try
const delay1 = res(3000)
const delay2 = res(2000)
const delay3 = rej(1000)

const data1 = await delay1
const data2 = await delay2
const data3 = await delay3
catch (error)
console.log(`await finished`, Date.now() - start)



example()









share|improve this question



























    up vote
    4
    down vote

    favorite












    This example (repl.it) (from this answer) looks to me like it follows all the rules regarding promises. Yet running it logs an exception regarding an unhandled promise rejection with the associated console message. (This also happens in FF, Chrome, and Node v10.)



    The try/catch block is clearly there and wraps the rejected promise, so what's going on and how would I fix it?





    async function example() 
    const start = Date.now()
    let i = 0
    function res(n)
    const id = ++i
    return new Promise((resolve, reject) =>
    setTimeout(() =>
    resolve()
    console.log(`res #$id called after $n milliseconds`, Date.now() - start)
    , n)
    )


    function rej(n)
    const id = ++i
    return new Promise((resolve, reject) =>
    setTimeout(() =>
    reject()
    console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
    , n)
    )


    try
    const delay1 = res(3000)
    const delay2 = res(2000)
    const delay3 = rej(1000)

    const data1 = await delay1
    const data2 = await delay2
    const data3 = await delay3
    catch (error)
    console.log(`await finished`, Date.now() - start)



    example()









    share|improve this question

























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      This example (repl.it) (from this answer) looks to me like it follows all the rules regarding promises. Yet running it logs an exception regarding an unhandled promise rejection with the associated console message. (This also happens in FF, Chrome, and Node v10.)



      The try/catch block is clearly there and wraps the rejected promise, so what's going on and how would I fix it?





      async function example() 
      const start = Date.now()
      let i = 0
      function res(n)
      const id = ++i
      return new Promise((resolve, reject) =>
      setTimeout(() =>
      resolve()
      console.log(`res #$id called after $n milliseconds`, Date.now() - start)
      , n)
      )


      function rej(n)
      const id = ++i
      return new Promise((resolve, reject) =>
      setTimeout(() =>
      reject()
      console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
      , n)
      )


      try
      const delay1 = res(3000)
      const delay2 = res(2000)
      const delay3 = rej(1000)

      const data1 = await delay1
      const data2 = await delay2
      const data3 = await delay3
      catch (error)
      console.log(`await finished`, Date.now() - start)



      example()









      share|improve this question















      This example (repl.it) (from this answer) looks to me like it follows all the rules regarding promises. Yet running it logs an exception regarding an unhandled promise rejection with the associated console message. (This also happens in FF, Chrome, and Node v10.)



      The try/catch block is clearly there and wraps the rejected promise, so what's going on and how would I fix it?





      async function example() 
      const start = Date.now()
      let i = 0
      function res(n)
      const id = ++i
      return new Promise((resolve, reject) =>
      setTimeout(() =>
      resolve()
      console.log(`res #$id called after $n milliseconds`, Date.now() - start)
      , n)
      )


      function rej(n)
      const id = ++i
      return new Promise((resolve, reject) =>
      setTimeout(() =>
      reject()
      console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
      , n)
      )


      try
      const delay1 = res(3000)
      const delay2 = res(2000)
      const delay3 = rej(1000)

      const data1 = await delay1
      const data2 = await delay2
      const data3 = await delay3
      catch (error)
      console.log(`await finished`, Date.now() - start)



      example()






      javascript promise async-await






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 3:44

























      asked Nov 10 at 21:57









      Ouroborus

      6,1821533




      6,1821533






















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          7
          down vote



          accepted










          The problem is that, at the point that the rej call rejects, the interpreter hasn't yet gotten to a line that awaits the promise created by rej, so the rejected Promise is just that, a rejected Promise, rather than a Promise that the current thread is awaiting:



          try improve this answer






















          • Separating the calls and the await like in the original example allows something to be done while the async stuff is working. It seems like you're saying that it's not possible to do this kind of separation without resorting to .catch()?
            – Ouroborus
            Nov 10 at 22:24







          • 1




            If you want to do additional things while still catching errors thrown by the three Promises, use the Promise.all method (plus a fourth non-Promise that does whatever other stuff you want to do), see edit. No need for .catch in addition to catch
            – CertainPerformance
            Nov 10 at 22:44











          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "1"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243811%2funhandled-promise-rejection%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          7
          down vote



          accepted










          The problem is that, at the point that the rej call rejects, the interpreter hasn't yet gotten to a line that awaits the promise created by rej, so the rejected Promise is just that, a rejected Promise, rather than a Promise that the current thread is awaiting:



          try improve this answer






















          • Separating the calls and the await like in the original example allows something to be done while the async stuff is working. It seems like you're saying that it's not possible to do this kind of separation without resorting to .catch()?
            – Ouroborus
            Nov 10 at 22:24







          • 1




            If you want to do additional things while still catching errors thrown by the three Promises, use the Promise.all method (plus a fourth non-Promise that does whatever other stuff you want to do), see edit. No need for .catch in addition to catch
            – CertainPerformance
            Nov 10 at 22:44















          up vote
          7
          down vote



          accepted










          The problem is that, at the point that the rej call rejects, the interpreter hasn't yet gotten to a line that awaits the promise created by rej, so the rejected Promise is just that, a rejected Promise, rather than a Promise that the current thread is awaiting:



          try improve this answer






















          • Separating the calls and the await like in the original example allows something to be done while the async stuff is working. It seems like you're saying that it's not possible to do this kind of separation without resorting to .catch()?
            – Ouroborus
            Nov 10 at 22:24







          • 1




            If you want to do additional things while still catching errors thrown by the three Promises, use the Promise.all method (plus a fourth non-Promise that does whatever other stuff you want to do), see edit. No need for .catch in addition to catch
            – CertainPerformance
            Nov 10 at 22:44













          up vote
          7
          down vote



          accepted







          up vote
          7
          down vote



          accepted






          The problem is that, at the point that the rej call rejects, the interpreter hasn't yet gotten to a line that awaits the promise created by rej, so the rejected Promise is just that, a rejected Promise, rather than a Promise that the current thread is awaiting:



          try improve this answer














          The problem is that, at the point that the rej call rejects, the interpreter hasn't yet gotten to a line that awaits the promise created by rej, so the rejected Promise is just that, a rejected Promise, rather than a Promise that the current thread is awaiting:



          try 
          const delay1 = res(3000)
          const delay2 = res(2000)
          const delay3 = rej(1000)

          const data1 = await delay1
          // The interpreter is paused on the line above when `rej` rejects
          const data2 = await delay2
          const data3 = await delay3


          So, the behavior is the same as if a rejected Promise is declared without a catch handler. (Errors thrown by Promises will only be caught in an async function if they're awaited at the point at which the Promise rejects - otherwise, it'll just result in an unhandled promise rejection.)



          I'd suggest either declaring Promises at the same point that you await them:



          const data1 = await res(3000)


          (note: the above method's timing won't be the same as the original code)



          or use await Promise.all for all Promises, which means that the Promise the interpreter is currently awaiting will throw (and thereby enter the catch block) as soon as one of the Promises rejects:



          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000)
          ]);





          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()





          To do additional work while the three Promises are ongoing, and catch errors from those Promises as well as from the main thread, pass a fourth item to the Promise.all, an IIFE that does the additional work you want to do:






          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          (() =>
          console.log('doing work...');
          )()
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()








          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()





          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()





          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          (() =>
          console.log('doing work...');
          )()
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()





          async function example() 
          const start = Date.now()
          let i = 0
          function res(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          resolve()
          console.log(`res #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          function rej(n)
          const id = ++i
          return new Promise((resolve, reject) =>
          setTimeout(() =>
          reject()
          console.log(`rej #$id called after $n milliseconds`, Date.now() - start)
          , n)
          )


          try
          const [data1, data2, data3] = await Promise.all([
          res(3000),
          res(2000),
          rej(1000),
          (() =>
          console.log('doing work...');
          )()
          ]);
          catch (error)
          console.log(`error caught: await finished`, Date.now() - start)



          example()






          share catch
          – CertainPerformance
          Nov 10 at 22:44























          Separating the calls and the await like in the original example allows something to be done while the async stuff is working. It seems like you're saying that it's not possible to do this kind of separation without resorting to .catch()?
          – Ouroborus
          Nov 10 at 22:24





          Separating the calls and the await like in the original example allows something to be done while the async stuff is working. It seems like you're saying that it's not possible to do this kind of separation without resorting to .catch()?
          – Ouroborus
          Nov 10 at 22:24





          1




          1




          If you want to do additional things while still catching errors thrown by the three Promises, use the Promise.all method (plus a fourth non-Promise that does whatever other stuff you want to do), see edit. No need for .catch in addition to } catch
          – CertainPerformance
          Nov 10 at 22:44





          If you want to do additional things while still catching errors thrown by the three Promises, use the Promise.all method (plus a fourth non-Promise that does whatever other stuff you want to do), see edit. No need for .catch in addition to } catch
          – CertainPerformance
          Nov 10 at 22:44


















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.





          Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


          Please pay close attention to the following guidance:


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243811%2funhandled-promise-rejection%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Use pre created SQLite database for Android project in kotlin

          Darth Vader #20

          Ondo