How to have multidimensional array with different length in Julia









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I need to make a sequence of an array with different length by reading a dataset. I need to call each of them in a loop so probably I need some sort of indexing in order to call them. For example, how can I create the following sequence:



P[1]=[1 2 3 4]
P[2]=[1 4]
P[3]=[8 9 0 0 5 6]
.
.
.









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    up vote
    1
    down vote

    favorite












    I need to make a sequence of an array with different length by reading a dataset. I need to call each of them in a loop so probably I need some sort of indexing in order to call them. For example, how can I create the following sequence:



    P[1]=[1 2 3 4]
    P[2]=[1 4]
    P[3]=[8 9 0 0 5 6]
    .
    .
    .









    share|improve this question

























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I need to make a sequence of an array with different length by reading a dataset. I need to call each of them in a loop so probably I need some sort of indexing in order to call them. For example, how can I create the following sequence:



      P[1]=[1 2 3 4]
      P[2]=[1 4]
      P[3]=[8 9 0 0 5 6]
      .
      .
      .









      share|improve this question















      I need to make a sequence of an array with different length by reading a dataset. I need to call each of them in a loop so probably I need some sort of indexing in order to call them. For example, how can I create the following sequence:



      P[1]=[1 2 3 4]
      P[2]=[1 4]
      P[3]=[8 9 0 0 5 6]
      .
      .
      .






      arrays julia-lang






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 10 at 22:03









      marc_s

      569k12811001250




      569k12811001250










      asked Nov 10 at 21:59









      Reabo

      114




      114






















          1 Answer
          1






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          up vote
          2
          down vote













          Here it is:



          julia> P = VectorVectorInt64([[1,2,3,4],[1,4],[8,9,0,0,5,6]]) 
          3-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]

          julia> P[1]
          4-element ArrayInt64,1:
          1
          2
          3
          4

          julia> P[2]
          2-element ArrayInt64,1:
          1
          4

          julia> P[3]
          6-element ArrayInt64,1:
          8
          9
          0
          0
          5
          6


          If you want to add a new element use push!():



          julia> push!(P,[7,8,9])
          4-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]
          [7, 8, 9]





          share|improve this answer






















          • Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
            – Reabo
            Nov 10 at 22:12










          • I found this and seems it works, thanks V=VectorVectorFloat64(100)
            – Reabo
            Nov 10 at 22:18











          • no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
            – Przemyslaw Szufel
            Nov 10 at 22:18











          • if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
            – Przemyslaw Szufel
            Nov 10 at 22:21







          • 1




            Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
            – DNF
            Nov 11 at 15:56











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          2
          down vote













          Here it is:



          julia> P = VectorVectorInt64([[1,2,3,4],[1,4],[8,9,0,0,5,6]]) 
          3-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]

          julia> P[1]
          4-element ArrayInt64,1:
          1
          2
          3
          4

          julia> P[2]
          2-element ArrayInt64,1:
          1
          4

          julia> P[3]
          6-element ArrayInt64,1:
          8
          9
          0
          0
          5
          6


          If you want to add a new element use push!():



          julia> push!(P,[7,8,9])
          4-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]
          [7, 8, 9]





          share|improve this answer






















          • Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
            – Reabo
            Nov 10 at 22:12










          • I found this and seems it works, thanks V=VectorVectorFloat64(100)
            – Reabo
            Nov 10 at 22:18











          • no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
            – Przemyslaw Szufel
            Nov 10 at 22:18











          • if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
            – Przemyslaw Szufel
            Nov 10 at 22:21







          • 1




            Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
            – DNF
            Nov 11 at 15:56















          up vote
          2
          down vote













          Here it is:



          julia> P = VectorVectorInt64([[1,2,3,4],[1,4],[8,9,0,0,5,6]]) 
          3-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]

          julia> P[1]
          4-element ArrayInt64,1:
          1
          2
          3
          4

          julia> P[2]
          2-element ArrayInt64,1:
          1
          4

          julia> P[3]
          6-element ArrayInt64,1:
          8
          9
          0
          0
          5
          6


          If you want to add a new element use push!():



          julia> push!(P,[7,8,9])
          4-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]
          [7, 8, 9]





          share|improve this answer






















          • Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
            – Reabo
            Nov 10 at 22:12










          • I found this and seems it works, thanks V=VectorVectorFloat64(100)
            – Reabo
            Nov 10 at 22:18











          • no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
            – Przemyslaw Szufel
            Nov 10 at 22:18











          • if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
            – Przemyslaw Szufel
            Nov 10 at 22:21







          • 1




            Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
            – DNF
            Nov 11 at 15:56













          up vote
          2
          down vote










          up vote
          2
          down vote









          Here it is:



          julia> P = VectorVectorInt64([[1,2,3,4],[1,4],[8,9,0,0,5,6]]) 
          3-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]

          julia> P[1]
          4-element ArrayInt64,1:
          1
          2
          3
          4

          julia> P[2]
          2-element ArrayInt64,1:
          1
          4

          julia> P[3]
          6-element ArrayInt64,1:
          8
          9
          0
          0
          5
          6


          If you want to add a new element use push!():



          julia> push!(P,[7,8,9])
          4-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]
          [7, 8, 9]





          share|improve this answer














          Here it is:



          julia> P = VectorVectorInt64([[1,2,3,4],[1,4],[8,9,0,0,5,6]]) 
          3-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]

          julia> P[1]
          4-element ArrayInt64,1:
          1
          2
          3
          4

          julia> P[2]
          2-element ArrayInt64,1:
          1
          4

          julia> P[3]
          6-element ArrayInt64,1:
          8
          9
          0
          0
          5
          6


          If you want to add a new element use push!():



          julia> push!(P,[7,8,9])
          4-element ArrayArrayInt64,1,1:
          [1, 2, 3, 4]
          [1, 4]
          [8, 9, 0, 0, 5, 6]
          [7, 8, 9]






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 10 at 22:18

























          answered Nov 10 at 22:09









          Przemyslaw Szufel

          1,369110




          1,369110











          • Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
            – Reabo
            Nov 10 at 22:12










          • I found this and seems it works, thanks V=VectorVectorFloat64(100)
            – Reabo
            Nov 10 at 22:18











          • no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
            – Przemyslaw Szufel
            Nov 10 at 22:18











          • if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
            – Przemyslaw Szufel
            Nov 10 at 22:21







          • 1




            Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
            – DNF
            Nov 11 at 15:56

















          • Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
            – Reabo
            Nov 10 at 22:12










          • I found this and seems it works, thanks V=VectorVectorFloat64(100)
            – Reabo
            Nov 10 at 22:18











          • no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
            – Przemyslaw Szufel
            Nov 10 at 22:18











          • if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
            – Przemyslaw Szufel
            Nov 10 at 22:21







          • 1




            Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
            – DNF
            Nov 11 at 15:56
















          Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
          – Reabo
          Nov 10 at 22:12




          Thanks, but my problem is that this sequence is very long and I cannot do the first line of your code manually.
          – Reabo
          Nov 10 at 22:12












          I found this and seems it works, thanks V=VectorVectorFloat64(100)
          – Reabo
          Nov 10 at 22:18





          I found this and seems it works, thanks V=VectorVectorFloat64(100)
          – Reabo
          Nov 10 at 22:18













          no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
          – Przemyslaw Szufel
          Nov 10 at 22:18





          no problem - I edited my answer. You can create an empty Array by P = VectorVectorInt64() and then just push! to it.
          – Przemyslaw Szufel
          Nov 10 at 22:18













          if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
          – Przemyslaw Szufel
          Nov 10 at 22:21





          if you know the Array size VectorVectorInt64(undef, N) and then using P[n]=... is of course better (note the undef)
          – Przemyslaw Szufel
          Nov 10 at 22:21





          1




          1




          Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
          – DNF
          Nov 11 at 15:56





          Initialize empty: P = VectorInt. If you already know the entries: P = [[1,2,3,4],[1,4],[8,9,0,0,5,6]]. No need to specify the type in front of the literal.
          – DNF
          Nov 11 at 15:56


















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