How can I ask for n and type the n numbers in only one line
up vote
1
down vote
favorite
The usual way to input n numbers is to first ask for n and then type n numbers in different lines.
n = int(input())
for i in range(n):
x = int(input())
How can I ask for n and type the n numbers in only one line.
Something like this:
>> 4 1 2 3 4
python string python-3.x input
add a comment |
up vote
1
down vote
favorite
The usual way to input n numbers is to first ask for n and then type n numbers in different lines.
n = int(input())
for i in range(n):
x = int(input())
How can I ask for n and type the n numbers in only one line.
Something like this:
>> 4 1 2 3 4
python string python-3.x input
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
The usual way to input n numbers is to first ask for n and then type n numbers in different lines.
n = int(input())
for i in range(n):
x = int(input())
How can I ask for n and type the n numbers in only one line.
Something like this:
>> 4 1 2 3 4
python string python-3.x input
The usual way to input n numbers is to first ask for n and then type n numbers in different lines.
n = int(input())
for i in range(n):
x = int(input())
How can I ask for n and type the n numbers in only one line.
Something like this:
>> 4 1 2 3 4
python string python-3.x input
python string python-3.x input
edited Nov 10 at 22:16
jpp
88.6k195199
88.6k195199
asked Nov 10 at 22:01
Miguel
103
103
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
up vote
2
down vote
accepted
How can I ask for n and type the n numbers in only one line.
You don't need to ask for n if it's obvious from the whitespace-separated input how many integers you have.
However, if the input string format is non-negotiable, you can split via sequence unpacking:
n, *num_list = map(int, input().split())
For example, with input '4 1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
To understand the above logic:
input().split()
splits a string input by whitespace into a list.map(int, X)
returns an iterable ofint
applied to each element inX
.n, *num_list = map(...)
iterates themap
object and separates into the first and the rest.
More idiomatic would be to calculate n
yourself:
num_list = list(map(int, input().split()))
n = len(num_list)
For example, with input '1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
The only purpose of entering the number of numbers explicitly is to provide a check. This is possible via an assert
statement:
n, *num_list = map(int, input().split())
assert n == len(num_list), f'Check failed: n vs len(num_list) provided does not match'
What does thismap(int, input().split())
do?
– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)
– Adam Smith
Nov 10 at 22:33
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
@jpp wait does that work? I had no idea you could handassert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman
– Adam Smith
Nov 10 at 22:51
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think theassert
syntax is standard in Python3.
– jpp
Nov 10 at 23:37
|
show 1 more comment
up vote
0
down vote
Perhaps you can try processing the entire input as a string. Then convert them to integers. In that case, you won't need to specify the value of n too.
>>> x = [int(y) for y in input().split()]
1 2 3 4
>>> x
[1, 2, 3, 4]
You can then work with the values by iterating through the list. If you need the value of n, just get the length of the list.
>>> n = len(x)
>>> n
4
add a comment |
up vote
0
down vote
space_separated_numbers = input()
num_list = [int(x) for x in space_separated_numbers.split()]
The trick is to take the whole input as a string at once, and then split it yourself.
EDIT: If you are only concerned with getting the first number, just get the first value instead.
space_separated_numbers = input()
num = space_separated_numbers.split()[0]
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
How can I ask for n and type the n numbers in only one line.
You don't need to ask for n if it's obvious from the whitespace-separated input how many integers you have.
However, if the input string format is non-negotiable, you can split via sequence unpacking:
n, *num_list = map(int, input().split())
For example, with input '4 1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
To understand the above logic:
input().split()
splits a string input by whitespace into a list.map(int, X)
returns an iterable ofint
applied to each element inX
.n, *num_list = map(...)
iterates themap
object and separates into the first and the rest.
More idiomatic would be to calculate n
yourself:
num_list = list(map(int, input().split()))
n = len(num_list)
For example, with input '1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
The only purpose of entering the number of numbers explicitly is to provide a check. This is possible via an assert
statement:
n, *num_list = map(int, input().split())
assert n == len(num_list), f'Check failed: n vs len(num_list) provided does not match'
What does thismap(int, input().split())
do?
– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)
– Adam Smith
Nov 10 at 22:33
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
@jpp wait does that work? I had no idea you could handassert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman
– Adam Smith
Nov 10 at 22:51
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think theassert
syntax is standard in Python3.
– jpp
Nov 10 at 23:37
|
show 1 more comment
up vote
2
down vote
accepted
How can I ask for n and type the n numbers in only one line.
You don't need to ask for n if it's obvious from the whitespace-separated input how many integers you have.
However, if the input string format is non-negotiable, you can split via sequence unpacking:
n, *num_list = map(int, input().split())
For example, with input '4 1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
To understand the above logic:
input().split()
splits a string input by whitespace into a list.map(int, X)
returns an iterable ofint
applied to each element inX
.n, *num_list = map(...)
iterates themap
object and separates into the first and the rest.
More idiomatic would be to calculate n
yourself:
num_list = list(map(int, input().split()))
n = len(num_list)
For example, with input '1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
The only purpose of entering the number of numbers explicitly is to provide a check. This is possible via an assert
statement:
n, *num_list = map(int, input().split())
assert n == len(num_list), f'Check failed: n vs len(num_list) provided does not match'
What does thismap(int, input().split())
do?
– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)
– Adam Smith
Nov 10 at 22:33
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
@jpp wait does that work? I had no idea you could handassert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman
– Adam Smith
Nov 10 at 22:51
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think theassert
syntax is standard in Python3.
– jpp
Nov 10 at 23:37
|
show 1 more comment
up vote
2
down vote
accepted
up vote
2
down vote
accepted
How can I ask for n and type the n numbers in only one line.
You don't need to ask for n if it's obvious from the whitespace-separated input how many integers you have.
However, if the input string format is non-negotiable, you can split via sequence unpacking:
n, *num_list = map(int, input().split())
For example, with input '4 1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
To understand the above logic:
input().split()
splits a string input by whitespace into a list.map(int, X)
returns an iterable ofint
applied to each element inX
.n, *num_list = map(...)
iterates themap
object and separates into the first and the rest.
More idiomatic would be to calculate n
yourself:
num_list = list(map(int, input().split()))
n = len(num_list)
For example, with input '1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
The only purpose of entering the number of numbers explicitly is to provide a check. This is possible via an assert
statement:
n, *num_list = map(int, input().split())
assert n == len(num_list), f'Check failed: n vs len(num_list) provided does not match'
How can I ask for n and type the n numbers in only one line.
You don't need to ask for n if it's obvious from the whitespace-separated input how many integers you have.
However, if the input string format is non-negotiable, you can split via sequence unpacking:
n, *num_list = map(int, input().split())
For example, with input '4 1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
To understand the above logic:
input().split()
splits a string input by whitespace into a list.map(int, X)
returns an iterable ofint
applied to each element inX
.n, *num_list = map(...)
iterates themap
object and separates into the first and the rest.
More idiomatic would be to calculate n
yourself:
num_list = list(map(int, input().split()))
n = len(num_list)
For example, with input '1 2 3 4'
, you will have the following result:
print(n, num_list)
4 [1, 2, 3, 4]
The only purpose of entering the number of numbers explicitly is to provide a check. This is possible via an assert
statement:
n, *num_list = map(int, input().split())
assert n == len(num_list), f'Check failed: n vs len(num_list) provided does not match'
edited Nov 10 at 23:37
answered Nov 10 at 22:14
jpp
88.6k195199
88.6k195199
What does thismap(int, input().split())
do?
– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)
– Adam Smith
Nov 10 at 22:33
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
@jpp wait does that work? I had no idea you could handassert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman
– Adam Smith
Nov 10 at 22:51
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think theassert
syntax is standard in Python3.
– jpp
Nov 10 at 23:37
|
show 1 more comment
What does thismap(int, input().split())
do?
– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)
– Adam Smith
Nov 10 at 22:33
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
@jpp wait does that work? I had no idea you could handassert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman
– Adam Smith
Nov 10 at 22:51
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think theassert
syntax is standard in Python3.
– jpp
Nov 10 at 23:37
What does this
map(int, input().split())
do?– Miguel
Nov 10 at 22:22
What does this
map(int, input().split())
do?– Miguel
Nov 10 at 22:22
Note for OP that an equally valid result would be
4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)– Adam Smith
Nov 10 at 22:33
Note for OP that an equally valid result would be
4 1 2 3 4 5
. The first number does not validate the rest (you'll have to implement that logic yourself)– Adam Smith
Nov 10 at 22:33
1
1
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
@AdamSmith, Agreed, I've added the only possible use I can see of having the initial count, some kind of explicit check on the subsequent input.
– jpp
Nov 10 at 22:47
1
1
@jpp wait does that work? I had no idea you could hand
assert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman– Adam Smith
Nov 10 at 22:51
@jpp wait does that work? I had no idea you could hand
assert
a tuple with an error message attached. Man, I've been writing Python for a decade or more and am still learning core language features. Feelsbadman– Adam Smith
Nov 10 at 22:51
1
1
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think the
assert
syntax is standard in Python3.– jpp
Nov 10 at 23:37
@AdamSmith, Formatted string literals (f-strings) were only introduced in Python 3.6, see PEP498. But otherwise, I think the
assert
syntax is standard in Python3.– jpp
Nov 10 at 23:37
|
show 1 more comment
up vote
0
down vote
Perhaps you can try processing the entire input as a string. Then convert them to integers. In that case, you won't need to specify the value of n too.
>>> x = [int(y) for y in input().split()]
1 2 3 4
>>> x
[1, 2, 3, 4]
You can then work with the values by iterating through the list. If you need the value of n, just get the length of the list.
>>> n = len(x)
>>> n
4
add a comment |
up vote
0
down vote
Perhaps you can try processing the entire input as a string. Then convert them to integers. In that case, you won't need to specify the value of n too.
>>> x = [int(y) for y in input().split()]
1 2 3 4
>>> x
[1, 2, 3, 4]
You can then work with the values by iterating through the list. If you need the value of n, just get the length of the list.
>>> n = len(x)
>>> n
4
add a comment |
up vote
0
down vote
up vote
0
down vote
Perhaps you can try processing the entire input as a string. Then convert them to integers. In that case, you won't need to specify the value of n too.
>>> x = [int(y) for y in input().split()]
1 2 3 4
>>> x
[1, 2, 3, 4]
You can then work with the values by iterating through the list. If you need the value of n, just get the length of the list.
>>> n = len(x)
>>> n
4
Perhaps you can try processing the entire input as a string. Then convert them to integers. In that case, you won't need to specify the value of n too.
>>> x = [int(y) for y in input().split()]
1 2 3 4
>>> x
[1, 2, 3, 4]
You can then work with the values by iterating through the list. If you need the value of n, just get the length of the list.
>>> n = len(x)
>>> n
4
answered Nov 10 at 22:10
boonwj
2189
2189
add a comment |
add a comment |
up vote
0
down vote
space_separated_numbers = input()
num_list = [int(x) for x in space_separated_numbers.split()]
The trick is to take the whole input as a string at once, and then split it yourself.
EDIT: If you are only concerned with getting the first number, just get the first value instead.
space_separated_numbers = input()
num = space_separated_numbers.split()[0]
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
add a comment |
up vote
0
down vote
space_separated_numbers = input()
num_list = [int(x) for x in space_separated_numbers.split()]
The trick is to take the whole input as a string at once, and then split it yourself.
EDIT: If you are only concerned with getting the first number, just get the first value instead.
space_separated_numbers = input()
num = space_separated_numbers.split()[0]
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
add a comment |
up vote
0
down vote
up vote
0
down vote
space_separated_numbers = input()
num_list = [int(x) for x in space_separated_numbers.split()]
The trick is to take the whole input as a string at once, and then split it yourself.
EDIT: If you are only concerned with getting the first number, just get the first value instead.
space_separated_numbers = input()
num = space_separated_numbers.split()[0]
space_separated_numbers = input()
num_list = [int(x) for x in space_separated_numbers.split()]
The trick is to take the whole input as a string at once, and then split it yourself.
EDIT: If you are only concerned with getting the first number, just get the first value instead.
space_separated_numbers = input()
num = space_separated_numbers.split()[0]
edited Nov 10 at 22:13
answered Nov 10 at 22:05
Paritosh Singh
72612
72612
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
add a comment |
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
Thank you for your response but it just adds all numbers into a list.
– Miguel
Nov 10 at 22:09
1
1
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
what would you like it to do instead? @Miguel
– Paritosh Singh
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
Hmmm. I would only need to pop the front element.
– Miguel
Nov 10 at 22:10
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
I think it's good but I'll wait to see some more responses.
– Miguel
Nov 10 at 22:12
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
Updated @Miguel , though i think you have all choices as you see fit once you get them all in a list.
– Paritosh Singh
Nov 10 at 22:14
add a comment |
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Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown