C++, can I overload assignment operator of a point of a class?










2















It is ok to overload assignment operator of a Class A, but not sure if it is allowed to overload assignment operator of pointer type of class A.
is it legitimate question or not...? If yes, how?



For example, I would like to do ref_count++ whenever we have a pointer reference on it below.



class A
public:
A()
~A()
int ref_count0;


main()

A* a1 = new A(); //line 1
A* a2 = a1; //line 2



After execution of line 1, A.ref_count is 1
After execution of line 2, A.ref_count is 2










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  • 1





    There is no operator=() involved in the two lines in your main()

    – Swordfish
    Nov 13 '18 at 8:44






  • 1





    What you're doing is copy initialization, not assignment.

    – Some programmer dude
    Nov 13 '18 at 8:46












  • And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

    – Some programmer dude
    Nov 13 '18 at 8:47






  • 3





    Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

    – StoryTeller
    Nov 13 '18 at 8:47











  • If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

    – dave
    Nov 13 '18 at 8:49















2















It is ok to overload assignment operator of a Class A, but not sure if it is allowed to overload assignment operator of pointer type of class A.
is it legitimate question or not...? If yes, how?



For example, I would like to do ref_count++ whenever we have a pointer reference on it below.



class A
public:
A()
~A()
int ref_count0;


main()

A* a1 = new A(); //line 1
A* a2 = a1; //line 2



After execution of line 1, A.ref_count is 1
After execution of line 2, A.ref_count is 2










share|improve this question

















  • 1





    There is no operator=() involved in the two lines in your main()

    – Swordfish
    Nov 13 '18 at 8:44






  • 1





    What you're doing is copy initialization, not assignment.

    – Some programmer dude
    Nov 13 '18 at 8:46












  • And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

    – Some programmer dude
    Nov 13 '18 at 8:47






  • 3





    Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

    – StoryTeller
    Nov 13 '18 at 8:47











  • If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

    – dave
    Nov 13 '18 at 8:49













2












2








2








It is ok to overload assignment operator of a Class A, but not sure if it is allowed to overload assignment operator of pointer type of class A.
is it legitimate question or not...? If yes, how?



For example, I would like to do ref_count++ whenever we have a pointer reference on it below.



class A
public:
A()
~A()
int ref_count0;


main()

A* a1 = new A(); //line 1
A* a2 = a1; //line 2



After execution of line 1, A.ref_count is 1
After execution of line 2, A.ref_count is 2










share|improve this question














It is ok to overload assignment operator of a Class A, but not sure if it is allowed to overload assignment operator of pointer type of class A.
is it legitimate question or not...? If yes, how?



For example, I would like to do ref_count++ whenever we have a pointer reference on it below.



class A
public:
A()
~A()
int ref_count0;


main()

A* a1 = new A(); //line 1
A* a2 = a1; //line 2



After execution of line 1, A.ref_count is 1
After execution of line 2, A.ref_count is 2







c++ pointers operator-overloading






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 13 '18 at 8:42









Kelvin LaiKelvin Lai

344




344







  • 1





    There is no operator=() involved in the two lines in your main()

    – Swordfish
    Nov 13 '18 at 8:44






  • 1





    What you're doing is copy initialization, not assignment.

    – Some programmer dude
    Nov 13 '18 at 8:46












  • And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

    – Some programmer dude
    Nov 13 '18 at 8:47






  • 3





    Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

    – StoryTeller
    Nov 13 '18 at 8:47











  • If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

    – dave
    Nov 13 '18 at 8:49












  • 1





    There is no operator=() involved in the two lines in your main()

    – Swordfish
    Nov 13 '18 at 8:44






  • 1





    What you're doing is copy initialization, not assignment.

    – Some programmer dude
    Nov 13 '18 at 8:46












  • And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

    – Some programmer dude
    Nov 13 '18 at 8:47






  • 3





    Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

    – StoryTeller
    Nov 13 '18 at 8:47











  • If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

    – dave
    Nov 13 '18 at 8:49







1




1





There is no operator=() involved in the two lines in your main()

– Swordfish
Nov 13 '18 at 8:44





There is no operator=() involved in the two lines in your main()

– Swordfish
Nov 13 '18 at 8:44




1




1





What you're doing is copy initialization, not assignment.

– Some programmer dude
Nov 13 '18 at 8:46






What you're doing is copy initialization, not assignment.

– Some programmer dude
Nov 13 '18 at 8:46














And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

– Some programmer dude
Nov 13 '18 at 8:47





And no you can't overload pointer assignment. The assignment operator must be a member function, and when you assign to a pointer it will not be called.

– Some programmer dude
Nov 13 '18 at 8:47




3




3





Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

– StoryTeller
Nov 13 '18 at 8:47





Fortunately, you don't need to implement ref counting for pointers yourself, in C++ they are spelled std::shared_ptr<A>.

– StoryTeller
Nov 13 '18 at 8:47













If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

– dave
Nov 13 '18 at 8:49





If you want to add more custom code other than just ref-counting, you can write your own wrapper class and overload operator* and operator-> for access

– dave
Nov 13 '18 at 8:49












2 Answers
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oldest

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1














I believe you mean pointer assignment. Short answer: no, you can't.






share|improve this answer






























    2














    It looks like you wan't a reference counted pointer. First lets examine why your solution doesn't work:



    1. Here: A* a1 = new A(); you are doing pointer assignment, not class assignment. You cannot overload this operation.

    2. In your definition of Class A you implement reference counting. This is not a good solution, what if you want a new class (Class B) that also requires reference counting? You have to implement it all over again. This is not nice or re-usable.

    So, what can we do? Well, it depends on why you wan't reference counting. It seems like you wan't self managed memory. Fortunatley, c++ provides a construct for this already. It is std::shared_ptr. You can use it like this:




    std::shared_ptr<A> a1 = std::make_shared<A>(); // Reference count is set at 1

    std::shared_ptr<A> a2 = a1; // Reference count is incremented to 2
    // Reference count is decremented to 1
    // Reference count is decremented to 0 and the memory is released.





    share|improve this answer






















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      2 Answers
      2






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      oldest

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      2 Answers
      2






      active

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      active

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      active

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      1














      I believe you mean pointer assignment. Short answer: no, you can't.






      share|improve this answer



























        1














        I believe you mean pointer assignment. Short answer: no, you can't.






        share|improve this answer

























          1












          1








          1







          I believe you mean pointer assignment. Short answer: no, you can't.






          share|improve this answer













          I believe you mean pointer assignment. Short answer: no, you can't.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 8:49









          darunedarune

          1,339516




          1,339516























              2














              It looks like you wan't a reference counted pointer. First lets examine why your solution doesn't work:



              1. Here: A* a1 = new A(); you are doing pointer assignment, not class assignment. You cannot overload this operation.

              2. In your definition of Class A you implement reference counting. This is not a good solution, what if you want a new class (Class B) that also requires reference counting? You have to implement it all over again. This is not nice or re-usable.

              So, what can we do? Well, it depends on why you wan't reference counting. It seems like you wan't self managed memory. Fortunatley, c++ provides a construct for this already. It is std::shared_ptr. You can use it like this:




              std::shared_ptr<A> a1 = std::make_shared<A>(); // Reference count is set at 1

              std::shared_ptr<A> a2 = a1; // Reference count is incremented to 2
              // Reference count is decremented to 1
              // Reference count is decremented to 0 and the memory is released.





              share|improve this answer



























                2














                It looks like you wan't a reference counted pointer. First lets examine why your solution doesn't work:



                1. Here: A* a1 = new A(); you are doing pointer assignment, not class assignment. You cannot overload this operation.

                2. In your definition of Class A you implement reference counting. This is not a good solution, what if you want a new class (Class B) that also requires reference counting? You have to implement it all over again. This is not nice or re-usable.

                So, what can we do? Well, it depends on why you wan't reference counting. It seems like you wan't self managed memory. Fortunatley, c++ provides a construct for this already. It is std::shared_ptr. You can use it like this:




                std::shared_ptr<A> a1 = std::make_shared<A>(); // Reference count is set at 1

                std::shared_ptr<A> a2 = a1; // Reference count is incremented to 2
                // Reference count is decremented to 1
                // Reference count is decremented to 0 and the memory is released.





                share|improve this answer

























                  2












                  2








                  2







                  It looks like you wan't a reference counted pointer. First lets examine why your solution doesn't work:



                  1. Here: A* a1 = new A(); you are doing pointer assignment, not class assignment. You cannot overload this operation.

                  2. In your definition of Class A you implement reference counting. This is not a good solution, what if you want a new class (Class B) that also requires reference counting? You have to implement it all over again. This is not nice or re-usable.

                  So, what can we do? Well, it depends on why you wan't reference counting. It seems like you wan't self managed memory. Fortunatley, c++ provides a construct for this already. It is std::shared_ptr. You can use it like this:




                  std::shared_ptr<A> a1 = std::make_shared<A>(); // Reference count is set at 1

                  std::shared_ptr<A> a2 = a1; // Reference count is incremented to 2
                  // Reference count is decremented to 1
                  // Reference count is decremented to 0 and the memory is released.





                  share|improve this answer













                  It looks like you wan't a reference counted pointer. First lets examine why your solution doesn't work:



                  1. Here: A* a1 = new A(); you are doing pointer assignment, not class assignment. You cannot overload this operation.

                  2. In your definition of Class A you implement reference counting. This is not a good solution, what if you want a new class (Class B) that also requires reference counting? You have to implement it all over again. This is not nice or re-usable.

                  So, what can we do? Well, it depends on why you wan't reference counting. It seems like you wan't self managed memory. Fortunatley, c++ provides a construct for this already. It is std::shared_ptr. You can use it like this:




                  std::shared_ptr<A> a1 = std::make_shared<A>(); // Reference count is set at 1

                  std::shared_ptr<A> a2 = a1; // Reference count is incremented to 2
                  // Reference count is decremented to 1
                  // Reference count is decremented to 0 and the memory is released.






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 9:20









                  Fantastic Mr FoxFantastic Mr Fox

                  18.7k1967131




                  18.7k1967131



























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