My Jquery only works when the page is refreshed?
0
This code only works when I refresh, however I want this to work live
add_action( 'wp_footer', 'conditionally_hid' );
function conditionally_hid()
jQuery(function($)
$("#customer_login").each(function()
if ($(this).css("display") == "none")
// handle non visible state
$('.steps').insertAfter( $('.actions') );
else
// handle visible state
$('.actions').insertAfter( $('.steps') );
);
);
jquery
edited Nov 13 '18 at 13:10
demo
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
add a comment |
0
This code only works when I refresh, however I want this to work live
add_action( 'wp_footer', 'conditionally_hid' );
function conditionally_hid()
jQuery(function($)
$("#customer_login").each(function()
if ($(this).css("display") == "none")
// handle non visible state
$('.steps').insertAfter( $('.actions') );
else
// handle visible state
$('.actions').insertAfter( $('.steps') );
);
);
jquery
edited Nov 13 '18 at 13:10
demo
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
You cannot do this$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.
– Ivelfan
Nov 13 '18 at 13:16
1
Or just use a class$('.customer_login');
– Jean-Marc Zimmer
Nov 13 '18 at 13:20
add a comment |
0
0
0
This code only works when I refresh, however I want this to work live
add_action( 'wp_footer', 'conditionally_hid' );
function conditionally_hid()
jQuery(function($)
$("#customer_login").each(function()
if ($(this).css("display") == "none")
// handle non visible state
$('.steps').insertAfter( $('.actions') );
else
// handle visible state
$('.actions').insertAfter( $('.steps') );
);
);
jquery
edited Nov 13 '18 at 13:10
demo
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
This code only works when I refresh, however I want this to work live
add_action( 'wp_footer', 'conditionally_hid' );
function conditionally_hid()
jQuery(function($)
$("#customer_login").each(function()
if ($(this).css("display") == "none")
// handle non visible state
$('.steps').insertAfter( $('.actions') );
else
// handle visible state
$('.actions').insertAfter( $('.steps') );
);
);
jquery
jquery
edited Nov 13 '18 at 13:10
demo
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
edited Nov 13 '18 at 13:10
demo
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
edited Nov 13 '18 at 13:10
demo
2,32033878
edited Nov 13 '18 at 13:10
demo
2,32033878
edited Nov 13 '18 at 13:10
demo
2,32033878
2,32033878
asked Nov 13 '18 at 13:02
OxeemOxeem
164
asked Nov 13 '18 at 13:02
OxeemOxeem
164
asked Nov 13 '18 at 13:02
OxeemOxeem
164
164
You cannot do this$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.
– Ivelfan
Nov 13 '18 at 13:16
1
Or just use a class$('.customer_login');
– Jean-Marc Zimmer
Nov 13 '18 at 13:20
add a comment |
You cannot do this$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.
– Ivelfan
Nov 13 '18 at 13:16
1
Or just use a class$('.customer_login');
– Jean-Marc Zimmer
Nov 13 '18 at 13:20
You cannot do this
$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.– Ivelfan
Nov 13 '18 at 13:16
You cannot do this
$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.– Ivelfan
Nov 13 '18 at 13:16
1
1
Or just use a class
$('.customer_login');– Jean-Marc Zimmer
Nov 13 '18 at 13:20
Or just use a class
$('.customer_login');– Jean-Marc Zimmer
Nov 13 '18 at 13:20
add a comment |
0
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You cannot do this
$("#customer_login").each. Identifier must be unique. If each time you insert a "customer_login" block, you want insert something after. You can add an event listener on "DOMNodeInserted" event.– Ivelfan
Nov 13 '18 at 13:16
1
Or just use a class
$('.customer_login');– Jean-Marc Zimmer
Nov 13 '18 at 13:20