Data Not inserted in Database php, mysql
-1
Can't insert data into DB . When i remove user_id then data is inserted. Please check below my code and help me.
function adddata($data)
global $db;
if (is_array($data))
$stmt = $db->prepare('INSERT INTO `pay` (id, payment, status, itemid, time, user_id) VALUES(?, ?, ?, ?, ?, ?');
$userid = 2;
$stmt->bind_param(
'sdssss',
$data['txn_id'],
$data['payment_amount'],
$data['payment_status'],
$data['item_number'],
date('Y-m-d H:i:s'),
$userid
);
$stmt->execute();
$stmt->close();
return $db->insert_id;
return false;
php mysql api mysqli
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
add a comment |
-1
Can't insert data into DB . When i remove user_id then data is inserted. Please check below my code and help me.
function adddata($data)
global $db;
if (is_array($data))
$stmt = $db->prepare('INSERT INTO `pay` (id, payment, status, itemid, time, user_id) VALUES(?, ?, ?, ?, ?, ?');
$userid = 2;
$stmt->bind_param(
'sdssss',
$data['txn_id'],
$data['payment_amount'],
$data['payment_status'],
$data['item_number'],
date('Y-m-d H:i:s'),
$userid
);
$stmt->execute();
$stmt->close();
return $db->insert_id;
return false;
php mysql api mysqli
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
3
Think there is a missing)inVALUES(?, ?, ?, ?, ?, ?');
– Nigel Ren
Nov 14 '18 at 20:21
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
Is youridvalue always the same? Because if it's a primary key then you wouldn't insert.
– Michael O.
Nov 14 '18 at 20:42
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54
add a comment |
-1
-1
-1
Can't insert data into DB . When i remove user_id then data is inserted. Please check below my code and help me.
function adddata($data)
global $db;
if (is_array($data))
$stmt = $db->prepare('INSERT INTO `pay` (id, payment, status, itemid, time, user_id) VALUES(?, ?, ?, ?, ?, ?');
$userid = 2;
$stmt->bind_param(
'sdssss',
$data['txn_id'],
$data['payment_amount'],
$data['payment_status'],
$data['item_number'],
date('Y-m-d H:i:s'),
$userid
);
$stmt->execute();
$stmt->close();
return $db->insert_id;
return false;
php mysql api mysqli
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
Can't insert data into DB . When i remove user_id then data is inserted. Please check below my code and help me.
function adddata($data)
global $db;
if (is_array($data))
$stmt = $db->prepare('INSERT INTO `pay` (id, payment, status, itemid, time, user_id) VALUES(?, ?, ?, ?, ?, ?');
$userid = 2;
$stmt->bind_param(
'sdssss',
$data['txn_id'],
$data['payment_amount'],
$data['payment_status'],
$data['item_number'],
date('Y-m-d H:i:s'),
$userid
);
$stmt->execute();
$stmt->close();
return $db->insert_id;
return false;
php mysql api mysqli
php mysql api mysqli
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
edited Nov 14 '18 at 22:58
Roman Pokrovskij
4,413135184
4,413135184
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
asked Nov 14 '18 at 20:17
Arsalan khatriArsalan khatri
63
63
3
Think there is a missing)inVALUES(?, ?, ?, ?, ?, ?');
– Nigel Ren
Nov 14 '18 at 20:21
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
Is youridvalue always the same? Because if it's a primary key then you wouldn't insert.
– Michael O.
Nov 14 '18 at 20:42
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54
add a comment |
3
Think there is a missing)inVALUES(?, ?, ?, ?, ?, ?');
– Nigel Ren
Nov 14 '18 at 20:21
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
Is youridvalue always the same? Because if it's a primary key then you wouldn't insert.
– Michael O.
Nov 14 '18 at 20:42
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54
3
3
Think there is a missing
) in VALUES(?, ?, ?, ?, ?, ?');– Nigel Ren
Nov 14 '18 at 20:21
Think there is a missing
) in VALUES(?, ?, ?, ?, ?, ?');– Nigel Ren
Nov 14 '18 at 20:21
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
Is your
id value always the same? Because if it's a primary key then you wouldn't insert.– Michael O.
Nov 14 '18 at 20:42
Is your
id value always the same? Because if it's a primary key then you wouldn't insert.– Michael O.
Nov 14 '18 at 20:42
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54
add a comment |
1 Answer
1
active
oldest
votes
0
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
add a comment |
0
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
add a comment |
0
0
0
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
answered Nov 14 '18 at 20:53
tadmantadman
157k19179209
157k19179209
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
add a comment |
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute
– Arsalan khatri
Nov 14 '18 at 21:02
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
"Will not execute" is not sufficiently detailed. If you can be more specific, like the exact error text you're getting, it's worth opening this up as a new question where that problem can be addressed.
– tadman
Nov 14 '18 at 21:37
add a comment |
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3
Think there is a missing
)inVALUES(?, ?, ?, ?, ?, ?');– Nigel Ren
Nov 14 '18 at 20:21
This stands to be a typo-based issue for more than just the missing bracket. The "id" column, is that an string based column or integer?
– Funk Forty Niner
Nov 14 '18 at 20:30
sir this is a string column of my id.
– Arsalan khatri
Nov 14 '18 at 20:32
Is your
idvalue always the same? Because if it's a primary key then you wouldn't insert.– Michael O.
Nov 14 '18 at 20:42
yes got it, thanks nigel Ren. bracket missing in my query. having also one issue can you please solve ? want to pass $_SESSION[userid]; in to my $userid variable. when i hardcode value in to $userid variable then query run successfully. but when pass $_SESSION[userid] query not execute.
– Arsalan khatri
Nov 14 '18 at 20:54