Regex how to ignore multiple ( )?










1















I'm using this regex string:



/rfi .*?(.*) .*?((.*))/i


Group 1 finds the rfi number & group 2 returns the contents inside the ( ).
With test string: "New RFI 087 (Concrete Beam at Planter)" everything works fine,
but with test string "New RFI 087 (Concrete (Beam) at Planter)" it crashes.



Is there anyway to search inside the ( ) but ignore multiple ( ) inside of it ?






regex







share|improve this question






















  • Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:24












  • This requires a recursive regex, which engine ?

    – sln
    Nov 14 '18 at 20:25











  • @sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:31












  • if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

    – sln
    Nov 14 '18 at 20:33












  • search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

    – sln
    Nov 14 '18 at 20:40
















1















I'm using this regex string:



/rfi .*?(.*) .*?((.*))/i


Group 1 finds the rfi number & group 2 returns the contents inside the ( ).
With test string: "New RFI 087 (Concrete Beam at Planter)" everything works fine,
but with test string "New RFI 087 (Concrete (Beam) at Planter)" it crashes.



Is there anyway to search inside the ( ) but ignore multiple ( ) inside of it ?






regex







share|improve this question






















  • Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:24












  • This requires a recursive regex, which engine ?

    – sln
    Nov 14 '18 at 20:25











  • @sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:31












  • if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

    – sln
    Nov 14 '18 at 20:33












  • search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

    – sln
    Nov 14 '18 at 20:40














1












1








1








I'm using this regex string:



/rfi .*?(.*) .*?((.*))/i


Group 1 finds the rfi number & group 2 returns the contents inside the ( ).
With test string: "New RFI 087 (Concrete Beam at Planter)" everything works fine,
but with test string "New RFI 087 (Concrete (Beam) at Planter)" it crashes.



Is there anyway to search inside the ( ) but ignore multiple ( ) inside of it ?






regex







share|improve this question














I'm using this regex string:



/rfi .*?(.*) .*?((.*))/i


Group 1 finds the rfi number & group 2 returns the contents inside the ( ).
With test string: "New RFI 087 (Concrete Beam at Planter)" everything works fine,
but with test string "New RFI 087 (Concrete (Beam) at Planter)" it crashes.



Is there anyway to search inside the ( ) but ignore multiple ( ) inside of it ?






regex




regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 14 '18 at 20:18









Barry RalphsBarry Ralphs

446




446












  • Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:24












  • This requires a recursive regex, which engine ?

    – sln
    Nov 14 '18 at 20:25











  • @sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:31












  • if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

    – sln
    Nov 14 '18 at 20:33












  • search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

    – sln
    Nov 14 '18 at 20:40


















  • Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:24












  • This requires a recursive regex, which engine ?

    – sln
    Nov 14 '18 at 20:25











  • @sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

    – Wiktor Stribiżew
    Nov 14 '18 at 20:31












  • if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

    – sln
    Nov 14 '18 at 20:33












  • search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

    – sln
    Nov 14 '18 at 20:40

















Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

– Wiktor Stribiżew
Nov 14 '18 at 20:24






Use /rfi (.*?) .*?((.*))/i (demo), make your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.

– Wiktor Stribiżew
Nov 14 '18 at 20:24














This requires a recursive regex, which engine ?

– sln
Nov 14 '18 at 20:25





This requires a recursive regex, which engine ?

– sln
Nov 14 '18 at 20:25













@sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

– Wiktor Stribiżew
Nov 14 '18 at 20:31






@sln, reclose as a dupe of stackoverflow.com/questions/22444/…, the only thing OP needs is lazy quantifier with Group 1. No recursion required. No need to reopen evident duplicates.

– Wiktor Stribiżew
Nov 14 '18 at 20:31














if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

– sln
Nov 14 '18 at 20:33






if you have access to a PCRE or Perl style engine, use this ((((?:[^()]++|(?1))*))). if a Java style engine, use this (?=()(?:(?=.*?((?!.*?1)(.*)(?!.*2).*))(?=.*?)(?!.*?2)(.*)).)+?.*?(?=1)[^(]*(?=2$)

– sln
Nov 14 '18 at 20:33














search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

– sln
Nov 14 '18 at 20:40






search inside the ( ) but ignore multiple ( ) inside of it is a RECURSION question NOT a quantifier question. This is about balanced text !!

– sln
Nov 14 '18 at 20:40













1 Answer
1






active

oldest

votes


















2














You can match your strings by making your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.



Use 



/rfi (.*?) .*?((.*))/i


See the regex demo



@sln suggests using a regex with a subroutine, but these features are not quite popular with regex engines, Ruby Onigmo or PCRE support them, for example.



/rfi (.*?) .*?(((?:[^()]++|(?2))*))/i


Or a bit more "cross library" (since Onigmo supports g<X> recursive construct, same as PCRE)



/rfi (.*?) .*?(((?:[^()]++|g<2>)*))/i


See this demo.






share|improve this answer

























  • but these features are not quite popular with regex engines What does this mean ?

    – sln
    Nov 14 '18 at 21:06










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














You can match your strings by making your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.



Use 



/rfi (.*?) .*?((.*))/i


See the regex demo



@sln suggests using a regex with a subroutine, but these features are not quite popular with regex engines, Ruby Onigmo or PCRE support them, for example.



/rfi (.*?) .*?(((?:[^()]++|(?2))*))/i


Or a bit more "cross library" (since Onigmo supports g<X> recursive construct, same as PCRE)



/rfi (.*?) .*?(((?:[^()]++|g<2>)*))/i


See this demo.






share|improve this answer

























  • but these features are not quite popular with regex engines What does this mean ?

    – sln
    Nov 14 '18 at 21:06















2














You can match your strings by making your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.



Use 



/rfi (.*?) .*?((.*))/i


See the regex demo



@sln suggests using a regex with a subroutine, but these features are not quite popular with regex engines, Ruby Onigmo or PCRE support them, for example.



/rfi (.*?) .*?(((?:[^()]++|(?2))*))/i


Or a bit more "cross library" (since Onigmo supports g<X> recursive construct, same as PCRE)



/rfi (.*?) .*?(((?:[^()]++|g<2>)*))/i


See this demo.






share|improve this answer

























  • but these features are not quite popular with regex engines What does this mean ?

    – sln
    Nov 14 '18 at 21:06













2












2








2







You can match your strings by making your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.



Use 



/rfi (.*?) .*?((.*))/i


See the regex demo



@sln suggests using a regex with a subroutine, but these features are not quite popular with regex engines, Ruby Onigmo or PCRE support them, for example.



/rfi (.*?) .*?(((?:[^()]++|(?2))*))/i


Or a bit more "cross library" (since Onigmo supports g<X> recursive construct, same as PCRE)



/rfi (.*?) .*?(((?:[^()]++|g<2>)*))/i


See this demo.






share|improve this answer















You can match your strings by making your Group 1 pattern lazy. Also, the first .*? is redundant, remove it.



Use 



/rfi (.*?) .*?((.*))/i


See the regex demo



@sln suggests using a regex with a subroutine, but these features are not quite popular with regex engines, Ruby Onigmo or PCRE support them, for example.



/rfi (.*?) .*?(((?:[^()]++|(?2))*))/i


Or a bit more "cross library" (since Onigmo supports g<X> recursive construct, same as PCRE)



/rfi (.*?) .*?(((?:[^()]++|g<2>)*))/i


See this demo.







share|improve this answer














share|improve this answer



share|improve this answer








answered Nov 14 '18 at 20:40


























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Wiktor Stribiżew













  • but these features are not quite popular with regex engines What does this mean ?

    – sln
    Nov 14 '18 at 21:06

















  • but these features are not quite popular with regex engines What does this mean ?

    – sln
    Nov 14 '18 at 21:06
















but these features are not quite popular with regex engines What does this mean ?

– sln
Nov 14 '18 at 21:06





but these features are not quite popular with regex engines What does this mean ?

– sln
Nov 14 '18 at 21:06



















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