Time complexity regarding O(LogN)
Let's say we have the following code.
def problem(n):
list =
for i in range(n):
list.append(i)
length = len(list)
return list
The program has time complexity of O(n) if we don't calculate len(list). But if we do, will the time complexity be O(n * log(n)) or O(n^2)? .
python time-complexity
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
add a comment |
Let's say we have the following code.
def problem(n):
list =
for i in range(n):
list.append(i)
length = len(list)
return list
The program has time complexity of O(n) if we don't calculate len(list). But if we do, will the time complexity be O(n * log(n)) or O(n^2)? .
python time-complexity
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
len(list)is O(1).
– Warren Weckesser
Nov 15 '18 at 5:55
1
Why on earth would it be O(n log n) or O(n^2)? Even iflenwas not O(1), the "worst implementation possible" would still be at most O(n)...
– Julien
Nov 15 '18 at 6:07
add a comment |
Let's say we have the following code.
def problem(n):
list =
for i in range(n):
list.append(i)
length = len(list)
return list
The program has time complexity of O(n) if we don't calculate len(list). But if we do, will the time complexity be O(n * log(n)) or O(n^2)? .
python time-complexity
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
Let's say we have the following code.
def problem(n):
list =
for i in range(n):
list.append(i)
length = len(list)
return list
The program has time complexity of O(n) if we don't calculate len(list). But if we do, will the time complexity be O(n * log(n)) or O(n^2)? .
python time-complexity
python time-complexity
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
edited Nov 15 '18 at 5:55
Clock Slave
2,38062664
2,38062664
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
asked Nov 15 '18 at 5:51
Nick SunNick Sun
1
1
len(list)is O(1).
– Warren Weckesser
Nov 15 '18 at 5:55
1
Why on earth would it be O(n log n) or O(n^2)? Even iflenwas not O(1), the "worst implementation possible" would still be at most O(n)...
– Julien
Nov 15 '18 at 6:07
add a comment |
len(list)is O(1).
– Warren Weckesser
Nov 15 '18 at 5:55
1
Why on earth would it be O(n log n) or O(n^2)? Even iflenwas not O(1), the "worst implementation possible" would still be at most O(n)...
– Julien
Nov 15 '18 at 6:07
len(list) is O(1).– Warren Weckesser
Nov 15 '18 at 5:55
len(list) is O(1).– Warren Weckesser
Nov 15 '18 at 5:55
1
1
Why on earth would it be O(n log n) or O(n^2)? Even if
len was not O(1), the "worst implementation possible" would still be at most O(n)...– Julien
Nov 15 '18 at 6:07
Why on earth would it be O(n log n) or O(n^2)? Even if
len was not O(1), the "worst implementation possible" would still be at most O(n)...– Julien
Nov 15 '18 at 6:07
add a comment |
1 Answer
1
active
oldest
votes
No, the len() function has constant time in python and it is not dependent on the length of the element, your time complexity for the above code would remain O(N) governed by your for i in range(n) loop. Here is the time complexity for many CPython functions, like len()! (Get Length in table)
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
No, the len() function has constant time in python and it is not dependent on the length of the element, your time complexity for the above code would remain O(N) governed by your for i in range(n) loop. Here is the time complexity for many CPython functions, like len()! (Get Length in table)
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
add a comment |
No, the len() function has constant time in python and it is not dependent on the length of the element, your time complexity for the above code would remain O(N) governed by your for i in range(n) loop. Here is the time complexity for many CPython functions, like len()! (Get Length in table)
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
add a comment |
No, the len() function has constant time in python and it is not dependent on the length of the element, your time complexity for the above code would remain O(N) governed by your for i in range(n) loop. Here is the time complexity for many CPython functions, like len()! (Get Length in table)
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
No, the len() function has constant time in python and it is not dependent on the length of the element, your time complexity for the above code would remain O(N) governed by your for i in range(n) loop. Here is the time complexity for many CPython functions, like len()! (Get Length in table)
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
answered Nov 15 '18 at 5:56
d_kennetzd_kennetz
2,2633927
2,2633927
add a comment |
add a comment |
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len(list)is O(1).– Warren Weckesser
Nov 15 '18 at 5:55
1
Why on earth would it be O(n log n) or O(n^2)? Even if
lenwas not O(1), the "worst implementation possible" would still be at most O(n)...– Julien
Nov 15 '18 at 6:07