CvInvoke.MinAreaRect(contour) returns the wrong angle










0















I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour) but it always returns the angle == -90 even when the plate is obviously tilted, you can see the contour I draw in the picture below.



return values



contour draw



original image



Does anyone know what happened and solution for my problem?



Here is the code:



Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));

VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);

double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();

for (int i = 0; i < contours.Size; i++)

double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)

max_area = temp;
max_contour = contours[i];



VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);

CvInvoke.Imshow("plate", gray);

RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);

CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();









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  • 1





    Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

    – dymanoid
    Nov 12 '18 at 9:24











  • I've just updated the code.

    – Ha Bom
    Nov 12 '18 at 9:41















0















I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour) but it always returns the angle == -90 even when the plate is obviously tilted, you can see the contour I draw in the picture below.



return values



contour draw



original image



Does anyone know what happened and solution for my problem?



Here is the code:



Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));

VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);

double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();

for (int i = 0; i < contours.Size; i++)

double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)

max_area = temp;
max_contour = contours[i];



VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);

CvInvoke.Imshow("plate", gray);

RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);

CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();









share|improve this question



















  • 1





    Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

    – dymanoid
    Nov 12 '18 at 9:24











  • I've just updated the code.

    – Ha Bom
    Nov 12 '18 at 9:41













0












0








0








I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour) but it always returns the angle == -90 even when the plate is obviously tilted, you can see the contour I draw in the picture below.



return values



contour draw



original image



Does anyone know what happened and solution for my problem?



Here is the code:



Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));

VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);

double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();

for (int i = 0; i < contours.Size; i++)

double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)

max_area = temp;
max_contour = contours[i];



VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);

CvInvoke.Imshow("plate", gray);

RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);

CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();









share|improve this question
















I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour) but it always returns the angle == -90 even when the plate is obviously tilted, you can see the contour I draw in the picture below.



return values



contour draw



original image



Does anyone know what happened and solution for my problem?



Here is the code:



Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));

VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);

double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();

for (int i = 0; i < contours.Size; i++)

double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)

max_area = temp;
max_contour = contours[i];



VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);

CvInvoke.Imshow("plate", gray);

RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);

CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();






c# emgucv contour angle






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edited Nov 12 '18 at 10:25









Rob

1,0091022




1,0091022










asked Nov 12 '18 at 9:16









Ha BomHa Bom

7352418




7352418







  • 1





    Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

    – dymanoid
    Nov 12 '18 at 9:24











  • I've just updated the code.

    – Ha Bom
    Nov 12 '18 at 9:41












  • 1





    Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

    – dymanoid
    Nov 12 '18 at 9:24











  • I've just updated the code.

    – Ha Bom
    Nov 12 '18 at 9:41







1




1





Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

– dymanoid
Nov 12 '18 at 9:24





Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).

– dymanoid
Nov 12 '18 at 9:24













I've just updated the code.

– Ha Bom
Nov 12 '18 at 9:41





I've just updated the code.

– Ha Bom
Nov 12 '18 at 9:41












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Try CvInvoke.threshold() instead of gray.ThresholdAdaptive(). Set proper threshold and you'll get better contour than before.






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    Try CvInvoke.threshold() instead of gray.ThresholdAdaptive(). Set proper threshold and you'll get better contour than before.






    share|improve this answer



























      0














      Try CvInvoke.threshold() instead of gray.ThresholdAdaptive(). Set proper threshold and you'll get better contour than before.






      share|improve this answer

























        0












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        0







        Try CvInvoke.threshold() instead of gray.ThresholdAdaptive(). Set proper threshold and you'll get better contour than before.






        share|improve this answer













        Try CvInvoke.threshold() instead of gray.ThresholdAdaptive(). Set proper threshold and you'll get better contour than before.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 17 '18 at 1:33







        user10665551


































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