CvInvoke.MinAreaRect(contour) returns the wrong angle
I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour)
but it always returns the angle == -90
even when the plate is obviously tilted, you can see the contour I draw in the picture below.
Does anyone know what happened and solution for my problem?
Here is the code:
Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));
VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);
double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();
for (int i = 0; i < contours.Size; i++)
double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)
max_area = temp;
max_contour = contours[i];
VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);
CvInvoke.Imshow("plate", gray);
RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);
CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();
c# emgucv contour angle
add a comment |
I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour)
but it always returns the angle == -90
even when the plate is obviously tilted, you can see the contour I draw in the picture below.
Does anyone know what happened and solution for my problem?
Here is the code:
Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));
VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);
double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();
for (int i = 0; i < contours.Size; i++)
double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)
max_area = temp;
max_contour = contours[i];
VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);
CvInvoke.Imshow("plate", gray);
RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);
CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();
c# emgucv contour angle
1
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41
add a comment |
I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour)
but it always returns the angle == -90
even when the plate is obviously tilted, you can see the contour I draw in the picture below.
Does anyone know what happened and solution for my problem?
Here is the code:
Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));
VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);
double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();
for (int i = 0; i < contours.Size; i++)
double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)
max_area = temp;
max_contour = contours[i];
VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);
CvInvoke.Imshow("plate", gray);
RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);
CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();
c# emgucv contour angle
I have a contour of a number plate and I want to check if it's tilted or not. I used CvInvoke.MinAreaRect(contour)
but it always returns the angle == -90
even when the plate is obviously tilted, you can see the contour I draw in the picture below.
Does anyone know what happened and solution for my problem?
Here is the code:
Image<Gray, byte> gray = new Image<Gray, byte>("2.PNG");
Image<Gray, byte> adaptive_threshold_img = gray.ThresholdAdaptive(new Gray(255), AdaptiveThresholdType.GaussianC, ThresholdType.BinaryInv, 11, new Gray(2));
VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Mat hier = new Mat();
CvInvoke.FindContours(adaptive_threshold_img, contours, hier, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);
double max_area = 0;
VectorOfPoint max_contour = new VectorOfPoint();
for (int i = 0; i < contours.Size; i++)
double temp = CvInvoke.ContourArea(contours[i]);
if (temp > max_area)
max_area = temp;
max_contour = contours[i];
VectorOfVectorOfPoint contour_to_draw = new VectorOfVectorOfPoint(max_contour);
CvInvoke.DrawContours(gray, contour_to_draw, 0, new MCvScalar(255), 2);
CvInvoke.Imshow("plate", gray);
RotatedRect plate_feature = CvInvoke.MinAreaRect(max_contour);
CvInvoke.WaitKey();
CvInvoke.DestroyAllWindows();
c# emgucv contour angle
c# emgucv contour angle
edited Nov 12 '18 at 10:25
Rob
1,0091022
1,0091022
asked Nov 12 '18 at 9:16
Ha BomHa Bom
7352418
7352418
1
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41
add a comment |
1
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41
1
1
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41
add a comment |
1 Answer
1
active
oldest
votes
Try CvInvoke.threshold()
instead of gray.ThresholdAdaptive()
. Set proper threshold and you'll get better contour than before.
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try CvInvoke.threshold()
instead of gray.ThresholdAdaptive()
. Set proper threshold and you'll get better contour than before.
add a comment |
Try CvInvoke.threshold()
instead of gray.ThresholdAdaptive()
. Set proper threshold and you'll get better contour than before.
add a comment |
Try CvInvoke.threshold()
instead of gray.ThresholdAdaptive()
. Set proper threshold and you'll get better contour than before.
Try CvInvoke.threshold()
instead of gray.ThresholdAdaptive()
. Set proper threshold and you'll get better contour than before.
answered Nov 17 '18 at 1:33
user10665551
add a comment |
add a comment |
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1
Please provide us with an Minimal, Complete, and Verifiable example of your code. It's impossible to say whether there's a problem in EmguCV (less likely) or your code (more likely).
– dymanoid
Nov 12 '18 at 9:24
I've just updated the code.
– Ha Bom
Nov 12 '18 at 9:41