Can't split commas out of list
I've got a similar list:
list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1']
I just want the number to the right of the comma, but when I try splitting:
newList = list.split(',')
I get:
AttributeError: 'list' object has no attribute 'split'
parsing split
edited Nov 14 '18 at 5:02
mrflash818
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
add a comment |
I've got a similar list:
list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1']
I just want the number to the right of the comma, but when I try splitting:
newList = list.split(',')
I get:
AttributeError: 'list' object has no attribute 'split'
parsing split
edited Nov 14 '18 at 5:02
mrflash818
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
add a comment |
I've got a similar list:
list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1']
I just want the number to the right of the comma, but when I try splitting:
newList = list.split(',')
I get:
AttributeError: 'list' object has no attribute 'split'
parsing split
edited Nov 14 '18 at 5:02
mrflash818
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
I've got a similar list:
list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1']
I just want the number to the right of the comma, but when I try splitting:
newList = list.split(',')
I get:
AttributeError: 'list' object has no attribute 'split'
parsing split
parsing split
edited Nov 14 '18 at 5:02
mrflash818
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
edited Nov 14 '18 at 5:02
mrflash818
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
edited Nov 14 '18 at 5:02
mrflash818
6841218
edited Nov 14 '18 at 5:02
mrflash818
6841218
edited Nov 14 '18 at 5:02
mrflash818
6841218
6841218
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
asked Nov 13 '18 at 17:16
anonymouselephant anonymouselephant
32
32
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
here split will not work because javascript method .split() is to convert string into array and but here list is an object. you can try console.log(typeof variable); to check type of any variable.
So here you can simply use jquery function .each() most common function used for traversing an javascript object.
Try below solution:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var new_list = ;
$(list).each(function( index, item )
var item_array = item.split(',');
$(item_array).each(function( i, num )
if(num && num != '' && typeof num != 'undefined')
new_list.push(num);
);
);
then use new_list instead of list as it will contain desired output:
["99", "48", "48", "44", "80", "82", "88", "90", "1", "1"]
OR can try alternate way:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var list_str = list.toString();
list = list_str.split(',');
list = list.filter(function(item)
if(!!item)
return item;
);
answered Nov 13 '18 at 18:08
sssurisssuri
329
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
here split will not work because javascript method .split() is to convert string into array and but here list is an object. you can try console.log(typeof variable); to check type of any variable.
So here you can simply use jquery function .each() most common function used for traversing an javascript object.
Try below solution:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var new_list = ;
$(list).each(function( index, item )
var item_array = item.split(',');
$(item_array).each(function( i, num )
if(num && num != '' && typeof num != 'undefined')
new_list.push(num);
);
);
then use new_list instead of list as it will contain desired output:
["99", "48", "48", "44", "80", "82", "88", "90", "1", "1"]
OR can try alternate way:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var list_str = list.toString();
list = list_str.split(',');
list = list.filter(function(item)
if(!!item)
return item;
);
answered Nov 13 '18 at 18:08
sssurisssuri
329
add a comment |
here split will not work because javascript method .split() is to convert string into array and but here list is an object. you can try console.log(typeof variable); to check type of any variable.
So here you can simply use jquery function .each() most common function used for traversing an javascript object.
Try below solution:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var new_list = ;
$(list).each(function( index, item )
var item_array = item.split(',');
$(item_array).each(function( i, num )
if(num && num != '' && typeof num != 'undefined')
new_list.push(num);
);
);
then use new_list instead of list as it will contain desired output:
["99", "48", "48", "44", "80", "82", "88", "90", "1", "1"]
OR can try alternate way:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var list_str = list.toString();
list = list_str.split(',');
list = list.filter(function(item)
if(!!item)
return item;
);
answered Nov 13 '18 at 18:08
sssurisssuri
329
add a comment |
here split will not work because javascript method .split() is to convert string into array and but here list is an object. you can try console.log(typeof variable); to check type of any variable.
So here you can simply use jquery function .each() most common function used for traversing an javascript object.
Try below solution:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var new_list = ;
$(list).each(function( index, item )
var item_array = item.split(',');
$(item_array).each(function( i, num )
if(num && num != '' && typeof num != 'undefined')
new_list.push(num);
);
);
then use new_list instead of list as it will contain desired output:
["99", "48", "48", "44", "80", "82", "88", "90", "1", "1"]
OR can try alternate way:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var list_str = list.toString();
list = list_str.split(',');
list = list.filter(function(item)
if(!!item)
return item;
);
answered Nov 13 '18 at 18:08
sssurisssuri
329
here split will not work because javascript method .split() is to convert string into array and but here list is an object. you can try console.log(typeof variable); to check type of any variable.
So here you can simply use jquery function .each() most common function used for traversing an javascript object.
Try below solution:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var new_list = ;
$(list).each(function( index, item )
var item_array = item.split(',');
$(item_array).each(function( i, num )
if(num && num != '' && typeof num != 'undefined')
new_list.push(num);
);
);
then use new_list instead of list as it will contain desired output:
["99", "48", "48", "44", "80", "82", "88", "90", "1", "1"]
OR can try alternate way:
var list = [',99', ',48', ',48', ',44', ',80', ',82', ',88', ',90', '1,1'];
var list_str = list.toString();
list = list_str.split(',');
list = list.filter(function(item)
if(!!item)
return item;
);
answered Nov 13 '18 at 18:08
sssurisssuri
329
edited Nov 14 '18 at 6:50
answered Nov 13 '18 at 18:08
sssurisssuri
329
answered Nov 13 '18 at 18:08
sssurisssuri
329
answered Nov 13 '18 at 18:08
sssurisssuri
329
329
add a comment |
add a comment |
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