How to write int to string in Mips









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I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word



Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)



The part for counting upercase letters in a word works (stored in $t5)



However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.



Here is my code:



.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main

main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall

li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall

la $t2, ($a0) # t2 - input string

word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter

word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', word_prereplace # We found end of word

addi $t1, $t1, 1 # Advance our counter (i++)

bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase

addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase

word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter

word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', exit # We found end of word

sb $t5, output($t1) # Overwrite this byte address in memory

addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace


exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall

li $v0, 4 # Print the output string!
la $a0, output
syscall

li $v0, 10 # exit()
syscall









share|improve this question























  • How is AaAA related to 3333?
    – wallyk
    Nov 10 at 18:22










  • There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
    – sswwqqaa
    Nov 10 at 18:23







  • 3




    the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
    – Ped7g
    Nov 10 at 19:09











  • Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
    – Peter Cordes
    Nov 10 at 19:18







  • 1




    well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
    – Ped7g
    Nov 10 at 19:21















up vote
1
down vote

favorite












I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word



Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)



The part for counting upercase letters in a word works (stored in $t5)



However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.



Here is my code:



.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main

main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall

li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall

la $t2, ($a0) # t2 - input string

word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter

word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', word_prereplace # We found end of word

addi $t1, $t1, 1 # Advance our counter (i++)

bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase

addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase

word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter

word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', exit # We found end of word

sb $t5, output($t1) # Overwrite this byte address in memory

addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace


exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall

li $v0, 4 # Print the output string!
la $a0, output
syscall

li $v0, 10 # exit()
syscall









share|improve this question























  • How is AaAA related to 3333?
    – wallyk
    Nov 10 at 18:22










  • There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
    – sswwqqaa
    Nov 10 at 18:23







  • 3




    the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
    – Ped7g
    Nov 10 at 19:09











  • Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
    – Peter Cordes
    Nov 10 at 19:18







  • 1




    well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
    – Ped7g
    Nov 10 at 19:21













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word



Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)



The part for counting upercase letters in a word works (stored in $t5)



However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.



Here is my code:



.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main

main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall

li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall

la $t2, ($a0) # t2 - input string

word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter

word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', word_prereplace # We found end of word

addi $t1, $t1, 1 # Advance our counter (i++)

bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase

addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase

word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter

word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', exit # We found end of word

sb $t5, output($t1) # Overwrite this byte address in memory

addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace


exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall

li $v0, 4 # Print the output string!
la $a0, output
syscall

li $v0, 10 # exit()
syscall









share|improve this question















I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word



Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)



The part for counting upercase letters in a word works (stored in $t5)



However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.



Here is my code:



.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main

main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall

li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall

la $t2, ($a0) # t2 - input string

word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter

word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', word_prereplace # We found end of word

addi $t1, $t1, 1 # Advance our counter (i++)

bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase

addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase

word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter

word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter

bltu $t4, ' ', exit # We found end of word

sb $t5, output($t1) # Overwrite this byte address in memory

addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace


exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall

li $v0, 4 # Print the output string!
la $a0, output
syscall

li $v0, 10 # exit()
syscall






assembly mips mars-simulator






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 20:34









Ped7g

13k21838




13k21838










asked Nov 10 at 18:21









sswwqqaa

5581314




5581314











  • How is AaAA related to 3333?
    – wallyk
    Nov 10 at 18:22










  • There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
    – sswwqqaa
    Nov 10 at 18:23







  • 3




    the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
    – Ped7g
    Nov 10 at 19:09











  • Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
    – Peter Cordes
    Nov 10 at 19:18







  • 1




    well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
    – Ped7g
    Nov 10 at 19:21

















  • How is AaAA related to 3333?
    – wallyk
    Nov 10 at 18:22










  • There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
    – sswwqqaa
    Nov 10 at 18:23







  • 3




    the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
    – Ped7g
    Nov 10 at 19:09











  • Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
    – Peter Cordes
    Nov 10 at 19:18







  • 1




    well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
    – Ped7g
    Nov 10 at 19:21
















How is AaAA related to 3333?
– wallyk
Nov 10 at 18:22




How is AaAA related to 3333?
– wallyk
Nov 10 at 18:22












There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23





There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23





3




3




the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
– Ped7g
Nov 10 at 19:09





the character "3" has ASCII code 0x33 (51 decimal), so you have to do addi $t5, $t5, '0' (or addi $t5, $t5, 48 if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':', etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
– Ped7g
Nov 10 at 19:09













Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
– Peter Cordes
Nov 10 at 19:18





Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with 1010101010... or something? If so then int->ASCII character is just addition or OR.
– Peter Cordes
Nov 10 at 19:18





1




1




well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
– Ped7g
Nov 10 at 19:21





well.. count mod 10 will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
– Ped7g
Nov 10 at 19:21


















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