How to write int to string in Mips
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1
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I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word
Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)
The part for counting upercase letters in a word works (stored in $t5)
However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.
Here is my code:
.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main
main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall
li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall
la $t2, ($a0) # t2 - input string
word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter
word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', word_prereplace # We found end of word
addi $t1, $t1, 1 # Advance our counter (i++)
bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase
addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase
word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter
word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', exit # We found end of word
sb $t5, output($t1) # Overwrite this byte address in memory
addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace
exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall
li $v0, 4 # Print the output string!
la $a0, output
syscall
li $v0, 10 # exit()
syscall
assembly mips mars-simulator
|
show 4 more comments
up vote
1
down vote
favorite
I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word
Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)
The part for counting upercase letters in a word works (stored in $t5)
However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.
Here is my code:
.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main
main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall
li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall
la $t2, ($a0) # t2 - input string
word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter
word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', word_prereplace # We found end of word
addi $t1, $t1, 1 # Advance our counter (i++)
bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase
addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase
word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter
word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', exit # We found end of word
sb $t5, output($t1) # Overwrite this byte address in memory
addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace
exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall
li $v0, 4 # Print the output string!
la $a0, output
syscall
li $v0, 10 # exit()
syscall
assembly mips mars-simulator
How isAaAA
related to3333
?
– wallyk
Nov 10 at 18:22
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
3
the character "3" has ASCII code 0x33 (51 decimal), so you have to doaddi $t5, $t5, '0'
(oraddi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
– Ped7g
Nov 10 at 19:09
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with1010101010...
or something? If so then int->ASCII character is just addition or OR.
– Peter Cordes
Nov 10 at 19:18
1
well..count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
– Ped7g
Nov 10 at 19:21
|
show 4 more comments
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word
Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)
The part for counting upercase letters in a word works (stored in $t5)
However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.
Here is my code:
.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main
main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall
li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall
la $t2, ($a0) # t2 - input string
word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter
word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', word_prereplace # We found end of word
addi $t1, $t1, 1 # Advance our counter (i++)
bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase
addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase
word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter
word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', exit # We found end of word
sb $t5, output($t1) # Overwrite this byte address in memory
addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace
exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall
li $v0, 4 # Print the output string!
la $a0, output
syscall
li $v0, 10 # exit()
syscall
assembly mips mars-simulator
I'm asking a user for input and I want to replace each character of the word by the number of uppercase characters in this word
Example:
Input: AaAA
output: 3333 (4 letters - 3 uppercase)
The part for counting upercase letters in a word works (stored in $t5)
However I cannot replace e.g "3333" with "AaAA". I'm trying to do it using sb in word_replace section. In my output I can see boxes instead of numbers.
Here is my code:
.data
prompt: .asciiz "Enter a string: "
msgout: .asciiz "Output string: "
input: .space 256
output: .space 256
.text
.globl main
main:
li $v0, 4 # Print enter a string prompt
la $a0, prompt
syscall
li $v0, 8 # Ask the user for the string they want to reverse
la $a0, input # We'll store it in 'input'
li $a1, 256 # Only 256 chars/bytes allowed
syscall
la $t2, ($a0) # t2 - input string
word:
li $t1, 0 # Normal counter
li $t5, 0 # Uppercase counter
word_countUppercase:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', word_prereplace # We found end of word
addi $t1, $t1, 1 # Advance our counter (i++)
bltu $t4, 'A', word_countUppercase
bgtu $t4, 'Z', word_countUppercase
addi $t5, $t5, 1 # Advance our counter (i++)
j word_countUppercase
word_prereplace:
la $t2, ($a0) # t2 - input string
li $t1, 0 # Normal counter
word_replace:
add $t3, $t2, $t1 # $t2 is the base address for our 'input' array, add loop index
lb $t4, 0($t3) # load a byte at a time according to counter
bltu $t4, ' ', exit # We found end of word
sb $t5, output($t1) # Overwrite this byte address in memory
addi $t1, $t1, 1 # Advance our counter (i++)
j word_replace
exit:
li $v0, 4 # Print msgout
la $a0, msgout
syscall
li $v0, 4 # Print the output string!
la $a0, output
syscall
li $v0, 10 # exit()
syscall
assembly mips mars-simulator
assembly mips mars-simulator
edited Nov 10 at 20:34
Ped7g
13k21838
13k21838
asked Nov 10 at 18:21
sswwqqaa
5581314
5581314
How isAaAA
related to3333
?
– wallyk
Nov 10 at 18:22
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
3
the character "3" has ASCII code 0x33 (51 decimal), so you have to doaddi $t5, $t5, '0'
(oraddi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
– Ped7g
Nov 10 at 19:09
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with1010101010...
or something? If so then int->ASCII character is just addition or OR.
– Peter Cordes
Nov 10 at 19:18
1
well..count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
– Ped7g
Nov 10 at 19:21
|
show 4 more comments
How isAaAA
related to3333
?
– wallyk
Nov 10 at 18:22
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
3
the character "3" has ASCII code 0x33 (51 decimal), so you have to doaddi $t5, $t5, '0'
(oraddi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.
– Ped7g
Nov 10 at 19:09
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with1010101010...
or something? If so then int->ASCII character is just addition or OR.
– Peter Cordes
Nov 10 at 19:18
1
well..count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)
– Ped7g
Nov 10 at 19:21
How is
AaAA
related to 3333
?– wallyk
Nov 10 at 18:22
How is
AaAA
related to 3333
?– wallyk
Nov 10 at 18:22
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
3
3
the character "3" has ASCII code 0x33 (51 decimal), so you have to do
addi $t5, $t5, '0'
(or addi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.– Ped7g
Nov 10 at 19:09
the character "3" has ASCII code 0x33 (51 decimal), so you have to do
addi $t5, $t5, '0'
(or addi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character ':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.– Ped7g
Nov 10 at 19:09
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with
1010101010...
or something? If so then int->ASCII character is just addition or OR.– Peter Cordes
Nov 10 at 19:18
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with
1010101010...
or something? If so then int->ASCII character is just addition or OR.– Peter Cordes
Nov 10 at 19:18
1
1
well..
count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)– Ped7g
Nov 10 at 19:21
well..
count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)– Ped7g
Nov 10 at 19:21
|
show 4 more comments
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How is
AaAA
related to3333
?– wallyk
Nov 10 at 18:22
There are 3 uppercase letters so 3 and there are 4 of them so 3333. Added more details in description.
– sswwqqaa
Nov 10 at 18:23
3
the character "3" has ASCII code 0x33 (51 decimal), so you have to do
addi $t5, $t5, '0'
(oraddi $t5, $t5, 48
if your assembler does not support parsing ASCII characters in single quotes) before overwriting the word letters. Also this will work only up to count 9, for count 10 the +48 will produce value 58, which in ASCII encoding encodes character':'
, etc... The "boxes" you see are "non-printable" (although it does print a box, so it's sort of printable) character mapped to value 3.– Ped7g
Nov 10 at 19:09
Are you supposed to assume that the result will always be a single-digit number? So you never have to fill a long word with
1010101010...
or something? If so then int->ASCII character is just addition or OR.– Peter Cordes
Nov 10 at 19:18
1
well..
count mod 10
will always produce value in range 0..9, so that one will work with the trivial number->ASCII conversion by doing add/or 0x30. (i.e. for ABCDEFGHIJ it will produce 0000000000)– Ped7g
Nov 10 at 19:21