Read File and store in a array of chars - c++









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0
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I'm trying to open a file and save the information there in an array of chars, however I'm not getting it. To save in a string use this:



int main()
string line1;
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(getline(myfile,line1))
ReadFile(myfile);





And It works.
When I use an array of chars, I code like this:



int main()
int size=100;
char line1[size];
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(myfile.peek()!EOF)
line1[size]->ReadFile();





The function ReadFile is this:



void ReadFile(ifstream &is)
char aux[100];
is.getline(aux,100);










share|improve this question























  • myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
    – Quimby
    Nov 10 at 18:09







  • 1




    Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
    – Neil Butterworth
    Nov 10 at 18:10











  • I've used it in other programs and it worked. Do you have any suggestions? @Quimby
    – Alice
    Nov 10 at 18:10











  • @NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
    – Alice
    Nov 10 at 18:11










  • Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
    – Quimby
    Nov 10 at 18:12














up vote
0
down vote

favorite












I'm trying to open a file and save the information there in an array of chars, however I'm not getting it. To save in a string use this:



int main()
string line1;
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(getline(myfile,line1))
ReadFile(myfile);





And It works.
When I use an array of chars, I code like this:



int main()
int size=100;
char line1[size];
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(myfile.peek()!EOF)
line1[size]->ReadFile();





The function ReadFile is this:



void ReadFile(ifstream &is)
char aux[100];
is.getline(aux,100);










share|improve this question























  • myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
    – Quimby
    Nov 10 at 18:09







  • 1




    Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
    – Neil Butterworth
    Nov 10 at 18:10











  • I've used it in other programs and it worked. Do you have any suggestions? @Quimby
    – Alice
    Nov 10 at 18:10











  • @NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
    – Alice
    Nov 10 at 18:11










  • Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
    – Quimby
    Nov 10 at 18:12












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm trying to open a file and save the information there in an array of chars, however I'm not getting it. To save in a string use this:



int main()
string line1;
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(getline(myfile,line1))
ReadFile(myfile);





And It works.
When I use an array of chars, I code like this:



int main()
int size=100;
char line1[size];
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(myfile.peek()!EOF)
line1[size]->ReadFile();





The function ReadFile is this:



void ReadFile(ifstream &is)
char aux[100];
is.getline(aux,100);










share|improve this question















I'm trying to open a file and save the information there in an array of chars, however I'm not getting it. To save in a string use this:



int main()
string line1;
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(getline(myfile,line1))
ReadFile(myfile);





And It works.
When I use an array of chars, I code like this:



int main()
int size=100;
char line1[size];
ifstream myfile;
myfile.open("example.txt");

if(!myfile)
cout<<"Unable to open the file."<<endl;
exit(0);

while(myfile.peek()!EOF)
line1[size]->ReadFile();





The function ReadFile is this:



void ReadFile(ifstream &is)
char aux[100];
is.getline(aux,100);







c++ arrays char readfile ifstream






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 18:36

























asked Nov 10 at 18:08









Alice

97




97











  • myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
    – Quimby
    Nov 10 at 18:09







  • 1




    Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
    – Neil Butterworth
    Nov 10 at 18:10











  • I've used it in other programs and it worked. Do you have any suggestions? @Quimby
    – Alice
    Nov 10 at 18:10











  • @NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
    – Alice
    Nov 10 at 18:11










  • Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
    – Quimby
    Nov 10 at 18:12
















  • myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
    – Quimby
    Nov 10 at 18:09







  • 1




    Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
    – Neil Butterworth
    Nov 10 at 18:10











  • I've used it in other programs and it worked. Do you have any suggestions? @Quimby
    – Alice
    Nov 10 at 18:10











  • @NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
    – Alice
    Nov 10 at 18:11










  • Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
    – Quimby
    Nov 10 at 18:12















myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
– Quimby
Nov 10 at 18:09





myfile.peek()!EOF doesn't seem right. line1[size]->myfile; is also weird.
– Quimby
Nov 10 at 18:09





1




1




Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
– Neil Butterworth
Nov 10 at 18:10





Don't use an array of chars then - a string is the correct thing to use here. Also, char line1[size]; is not valid C++ code.
– Neil Butterworth
Nov 10 at 18:10













I've used it in other programs and it worked. Do you have any suggestions? @Quimby
– Alice
Nov 10 at 18:10





I've used it in other programs and it worked. Do you have any suggestions? @Quimby
– Alice
Nov 10 at 18:10













@NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
– Alice
Nov 10 at 18:11




@NeilButterworth I need to use chars to implement another function that counts the number of chars in the file
– Alice
Nov 10 at 18:11












Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
– Quimby
Nov 10 at 18:12




Use stringstreams to read whole files. stackoverflow.com/questions/2602013/…
– Quimby
Nov 10 at 18:12












1 Answer
1






active

oldest

votes

















up vote
0
down vote













To read in an array of characters, or text, you can use std::getline and std::string:



std::string text;
std::getline(myfile, text);


To process text lines in a file:



std::string text;
while (std::getline(myfile, text))

Process_Text(text);



Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '', otherwise the string functions will go beyond your array, not stopping until a nul is found.



Edit 1: Space separated

To read in text that is space separated, use:



std::string text;
myfile >> text;


Edit 2: Counting characters in a string

You can count characters in a string by using another array.



unsigned int frequency[128] = 0; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)

const char letter = text[index];
++frequency[letter];






share|improve this answer






















  • And then I can use the string text to count each char have the text?
    – Alice
    Nov 10 at 18:23










  • See my Edit 2.
    – Thomas Matthews
    Nov 10 at 19:04










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote













To read in an array of characters, or text, you can use std::getline and std::string:



std::string text;
std::getline(myfile, text);


To process text lines in a file:



std::string text;
while (std::getline(myfile, text))

Process_Text(text);



Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '', otherwise the string functions will go beyond your array, not stopping until a nul is found.



Edit 1: Space separated

To read in text that is space separated, use:



std::string text;
myfile >> text;


Edit 2: Counting characters in a string

You can count characters in a string by using another array.



unsigned int frequency[128] = 0; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)

const char letter = text[index];
++frequency[letter];






share|improve this answer






















  • And then I can use the string text to count each char have the text?
    – Alice
    Nov 10 at 18:23










  • See my Edit 2.
    – Thomas Matthews
    Nov 10 at 19:04














up vote
0
down vote













To read in an array of characters, or text, you can use std::getline and std::string:



std::string text;
std::getline(myfile, text);


To process text lines in a file:



std::string text;
while (std::getline(myfile, text))

Process_Text(text);



Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '', otherwise the string functions will go beyond your array, not stopping until a nul is found.



Edit 1: Space separated

To read in text that is space separated, use:



std::string text;
myfile >> text;


Edit 2: Counting characters in a string

You can count characters in a string by using another array.



unsigned int frequency[128] = 0; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)

const char letter = text[index];
++frequency[letter];






share|improve this answer






















  • And then I can use the string text to count each char have the text?
    – Alice
    Nov 10 at 18:23










  • See my Edit 2.
    – Thomas Matthews
    Nov 10 at 19:04












up vote
0
down vote










up vote
0
down vote









To read in an array of characters, or text, you can use std::getline and std::string:



std::string text;
std::getline(myfile, text);


To process text lines in a file:



std::string text;
while (std::getline(myfile, text))

Process_Text(text);



Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '', otherwise the string functions will go beyond your array, not stopping until a nul is found.



Edit 1: Space separated

To read in text that is space separated, use:



std::string text;
myfile >> text;


Edit 2: Counting characters in a string

You can count characters in a string by using another array.



unsigned int frequency[128] = 0; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)

const char letter = text[index];
++frequency[letter];






share|improve this answer














To read in an array of characters, or text, you can use std::getline and std::string:



std::string text;
std::getline(myfile, text);


To process text lines in a file:



std::string text;
while (std::getline(myfile, text))

Process_Text(text);



Don't use arrays of characters, as they can overflow. Also, instead of using == to compare, you'll have to use strcmp. Always verify that your array of characters is terminated by a nul character, '', otherwise the string functions will go beyond your array, not stopping until a nul is found.



Edit 1: Space separated

To read in text that is space separated, use:



std::string text;
myfile >> text;


Edit 2: Counting characters in a string

You can count characters in a string by using another array.



unsigned int frequency[128] = 0; // Let's assume ASCII, one slot for each character.
// ... read in string
const size_t length(text.length());
for (size_t index = 0; index < length; ++index)

const char letter = text[index];
++frequency[letter];







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 10 at 19:04

























answered Nov 10 at 18:20









Thomas Matthews

44k1171122




44k1171122











  • And then I can use the string text to count each char have the text?
    – Alice
    Nov 10 at 18:23










  • See my Edit 2.
    – Thomas Matthews
    Nov 10 at 19:04
















  • And then I can use the string text to count each char have the text?
    – Alice
    Nov 10 at 18:23










  • See my Edit 2.
    – Thomas Matthews
    Nov 10 at 19:04















And then I can use the string text to count each char have the text?
– Alice
Nov 10 at 18:23




And then I can use the string text to count each char have the text?
– Alice
Nov 10 at 18:23












See my Edit 2.
– Thomas Matthews
Nov 10 at 19:04




See my Edit 2.
– Thomas Matthews
Nov 10 at 19:04

















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