What's wrong with the rotation of my lists?
up vote
-2
down vote
favorite
In that part of the code I only want to rotate one of the list, but both had been rotated.
for(int i = 0; i< 1000000000; i++)
Collections.rotate(newList, positions);
System.out.println("New list: "+newList);
System.out.println("Normal list: "+list);
if(dosListasIguales(list, newList))
movimientos = i;
break;
java arrays list rotation
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
add a comment |
up vote
-2
down vote
favorite
In that part of the code I only want to rotate one of the list, but both had been rotated.
for(int i = 0; i< 1000000000; i++)
Collections.rotate(newList, positions);
System.out.println("New list: "+newList);
System.out.println("Normal list: "+list);
if(dosListasIguales(list, newList))
movimientos = i;
break;
java arrays list rotation
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
2
How did you createnewList? If you did something likeList newList = listthen they are the sameList.
– KevinO
Nov 10 at 18:23
1
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
nothing can be said about aboutlistvariable.
– The Scientific Method
Nov 10 at 18:26
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
In that part of the code I only want to rotate one of the list, but both had been rotated.
for(int i = 0; i< 1000000000; i++)
Collections.rotate(newList, positions);
System.out.println("New list: "+newList);
System.out.println("Normal list: "+list);
if(dosListasIguales(list, newList))
movimientos = i;
break;
java arrays list rotation
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
In that part of the code I only want to rotate one of the list, but both had been rotated.
for(int i = 0; i< 1000000000; i++)
Collections.rotate(newList, positions);
System.out.println("New list: "+newList);
System.out.println("Normal list: "+list);
if(dosListasIguales(list, newList))
movimientos = i;
break;
java arrays list rotation
java arrays list rotation
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
asked Nov 10 at 18:21
Carlos Castaño del Castillo
61
61
2
How did you createnewList? If you did something likeList newList = listthen they are the sameList.
– KevinO
Nov 10 at 18:23
1
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
nothing can be said about aboutlistvariable.
– The Scientific Method
Nov 10 at 18:26
add a comment |
2
How did you createnewList? If you did something likeList newList = listthen they are the sameList.
– KevinO
Nov 10 at 18:23
1
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
nothing can be said about aboutlistvariable.
– The Scientific Method
Nov 10 at 18:26
2
2
How did you create
newList? If you did something like List newList = list then they are the same List.– KevinO
Nov 10 at 18:23
How did you create
newList? If you did something like List newList = list then they are the same List.– KevinO
Nov 10 at 18:23
1
1
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
nothing can be said about about
list variable.– The Scientific Method
Nov 10 at 18:26
nothing can be said about about
list variable.– The Scientific Method
Nov 10 at 18:26
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
It seems you have copied reference of list to newList somewhere. So any changes in the newList affects list.
Use this for copying:
List<Integer> newList = new ArrayList<Integer>(list);
instead of:
List<Integer> newList = list;
answered Nov 10 at 18:24
Majid
7,80085599
@CarlosCastañodelCastilloList<Integer> newList = list;is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);
– Majid
Nov 10 at 18:33
add a comment |
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1 Answer
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oldest
votes
up vote
0
down vote
It seems you have copied reference of list to newList somewhere. So any changes in the newList affects list.
Use this for copying:
List<Integer> newList = new ArrayList<Integer>(list);
instead of:
List<Integer> newList = list;
answered Nov 10 at 18:24
Majid
7,80085599
@CarlosCastañodelCastilloList<Integer> newList = list;is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);
– Majid
Nov 10 at 18:33
add a comment |
up vote
0
down vote
It seems you have copied reference of list to newList somewhere. So any changes in the newList affects list.
Use this for copying:
List<Integer> newList = new ArrayList<Integer>(list);
instead of:
List<Integer> newList = list;
answered Nov 10 at 18:24
Majid
7,80085599
@CarlosCastañodelCastilloList<Integer> newList = list;is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);
– Majid
Nov 10 at 18:33
add a comment |
up vote
0
down vote
up vote
0
down vote
It seems you have copied reference of list to newList somewhere. So any changes in the newList affects list.
Use this for copying:
List<Integer> newList = new ArrayList<Integer>(list);
instead of:
List<Integer> newList = list;
answered Nov 10 at 18:24
Majid
7,80085599
It seems you have copied reference of list to newList somewhere. So any changes in the newList affects list.
Use this for copying:
List<Integer> newList = new ArrayList<Integer>(list);
instead of:
List<Integer> newList = list;
answered Nov 10 at 18:24
Majid
7,80085599
edited Nov 10 at 18:34
answered Nov 10 at 18:24
Majid
7,80085599
answered Nov 10 at 18:24
Majid
7,80085599
answered Nov 10 at 18:24
Majid
7,80085599
7,80085599
@CarlosCastañodelCastilloList<Integer> newList = list;is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);
– Majid
Nov 10 at 18:33
add a comment |
@CarlosCastañodelCastilloList<Integer> newList = list;is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);
– Majid
Nov 10 at 18:33
@CarlosCastañodelCastillo
List<Integer> newList = list; is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);– Majid
Nov 10 at 18:33
@CarlosCastañodelCastillo
List<Integer> newList = list; is the reference copying point. You should useList<Integer> newList = new ArrayList<Integer>(list);– Majid
Nov 10 at 18:33
add a comment |
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2
How did you create
newList? If you did something likeList newList = listthen they are the sameList.– KevinO
Nov 10 at 18:23
1
We cannot tell from what you have presented, though it seems that the two lists in question must be aliased somehow. Present a Minimal, Complete, and Verifiable example demonstrating the problem if you want a confident answer.
– John Bollinger
Nov 10 at 18:23
nothing can be said about about
listvariable.– The Scientific Method
Nov 10 at 18:26