2D NSDictionary with NSArray









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The data set i'm trying to declare would look something like,



$results[@"Key1"][@"Key2"] = @[int, int, int, int];



How would one declare this combination of NSDictionary & NSArray?










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  • @@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
    – Larme
    Nov 10 at 17:47














up vote
-3
down vote

favorite












The data set i'm trying to declare would look something like,



$results[@"Key1"][@"Key2"] = @[int, int, int, int];



How would one declare this combination of NSDictionary & NSArray?










share|improve this question





















  • @@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
    – Larme
    Nov 10 at 17:47












up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











The data set i'm trying to declare would look something like,



$results[@"Key1"][@"Key2"] = @[int, int, int, int];



How would one declare this combination of NSDictionary & NSArray?










share|improve this question













The data set i'm trying to declare would look something like,



$results[@"Key1"][@"Key2"] = @[int, int, int, int];



How would one declare this combination of NSDictionary & NSArray?







objective-c






share|improve this question













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asked Nov 10 at 17:43









Simon.

88641640




88641640











  • @@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
    – Larme
    Nov 10 at 17:47
















  • @@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
    – Larme
    Nov 10 at 17:47















@@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
– Larme
Nov 10 at 17:47




@@"Key1": @@"key2: @[@(int1),@(int2),@(int3),@(int4) ]?
– Larme
Nov 10 at 17:47












1 Answer
1






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0
down vote













So as far as I understand it, you're looking for an array within a nested dictionary - so an array, within a dictionary, within another dictionary.



I would declare it like this:



NSMutableDictionary *firstDictionary = [[NSMutableDictionary alloc] init];
NSMutableDictionary *secondDictionary = [[NSMutableDictionary alloc] init];
NSArray *array = @[@1, @2, @3, @4];

[secondDictionary setObject:array forKey:@"key2"];
[firstDictionary setObject:secondDictionary forKey:@"key1"];


Then you can access the contents of your data structure like this:



NSArray *results = firstDictionary[@"key1"][@"key2"];

NSLog(@"results: %@", results);


And it will output:



results: (
1,
2,
3,
4
)


Hope this helps :)



Edit: just as an aside, if you're trying to create a 2d matrix, where you use 2 coordinates to access your data, then you should probably use a nested array, instead of a nested dictionary.






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    1 Answer
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    up vote
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    down vote













    So as far as I understand it, you're looking for an array within a nested dictionary - so an array, within a dictionary, within another dictionary.



    I would declare it like this:



    NSMutableDictionary *firstDictionary = [[NSMutableDictionary alloc] init];
    NSMutableDictionary *secondDictionary = [[NSMutableDictionary alloc] init];
    NSArray *array = @[@1, @2, @3, @4];

    [secondDictionary setObject:array forKey:@"key2"];
    [firstDictionary setObject:secondDictionary forKey:@"key1"];


    Then you can access the contents of your data structure like this:



    NSArray *results = firstDictionary[@"key1"][@"key2"];

    NSLog(@"results: %@", results);


    And it will output:



    results: (
    1,
    2,
    3,
    4
    )


    Hope this helps :)



    Edit: just as an aside, if you're trying to create a 2d matrix, where you use 2 coordinates to access your data, then you should probably use a nested array, instead of a nested dictionary.






    share|improve this answer


























      up vote
      0
      down vote













      So as far as I understand it, you're looking for an array within a nested dictionary - so an array, within a dictionary, within another dictionary.



      I would declare it like this:



      NSMutableDictionary *firstDictionary = [[NSMutableDictionary alloc] init];
      NSMutableDictionary *secondDictionary = [[NSMutableDictionary alloc] init];
      NSArray *array = @[@1, @2, @3, @4];

      [secondDictionary setObject:array forKey:@"key2"];
      [firstDictionary setObject:secondDictionary forKey:@"key1"];


      Then you can access the contents of your data structure like this:



      NSArray *results = firstDictionary[@"key1"][@"key2"];

      NSLog(@"results: %@", results);


      And it will output:



      results: (
      1,
      2,
      3,
      4
      )


      Hope this helps :)



      Edit: just as an aside, if you're trying to create a 2d matrix, where you use 2 coordinates to access your data, then you should probably use a nested array, instead of a nested dictionary.






      share|improve this answer
























        up vote
        0
        down vote










        up vote
        0
        down vote









        So as far as I understand it, you're looking for an array within a nested dictionary - so an array, within a dictionary, within another dictionary.



        I would declare it like this:



        NSMutableDictionary *firstDictionary = [[NSMutableDictionary alloc] init];
        NSMutableDictionary *secondDictionary = [[NSMutableDictionary alloc] init];
        NSArray *array = @[@1, @2, @3, @4];

        [secondDictionary setObject:array forKey:@"key2"];
        [firstDictionary setObject:secondDictionary forKey:@"key1"];


        Then you can access the contents of your data structure like this:



        NSArray *results = firstDictionary[@"key1"][@"key2"];

        NSLog(@"results: %@", results);


        And it will output:



        results: (
        1,
        2,
        3,
        4
        )


        Hope this helps :)



        Edit: just as an aside, if you're trying to create a 2d matrix, where you use 2 coordinates to access your data, then you should probably use a nested array, instead of a nested dictionary.






        share|improve this answer














        So as far as I understand it, you're looking for an array within a nested dictionary - so an array, within a dictionary, within another dictionary.



        I would declare it like this:



        NSMutableDictionary *firstDictionary = [[NSMutableDictionary alloc] init];
        NSMutableDictionary *secondDictionary = [[NSMutableDictionary alloc] init];
        NSArray *array = @[@1, @2, @3, @4];

        [secondDictionary setObject:array forKey:@"key2"];
        [firstDictionary setObject:secondDictionary forKey:@"key1"];


        Then you can access the contents of your data structure like this:



        NSArray *results = firstDictionary[@"key1"][@"key2"];

        NSLog(@"results: %@", results);


        And it will output:



        results: (
        1,
        2,
        3,
        4
        )


        Hope this helps :)



        Edit: just as an aside, if you're trying to create a 2d matrix, where you use 2 coordinates to access your data, then you should probably use a nested array, instead of a nested dictionary.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 10 at 20:13

























        answered Nov 10 at 20:03









        simsula

        277




        277



























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