changing password using pexpect and passwd non-interactivly?
I am trying to learn python to change users password non-interactively but nothing seems to be working.pexepect
module of python seems promising, so I am just trying to use it.
This tutorial is nice but it does not work.
There's lots of code on Internet regarding this but none of them seems to work.
And nor does my code:
#!/usr/bin/python
import pexpect
import time
def ChangePassword(user, pass):
passwd = pexpect.spawn("/usr/bin/passwd %s" % user)
for x in xrange(2):
# wait for password: to come out of passwd's stdout
passwd.expect("password: ")
# send pass to passwd's stdin
passwd.sendline(pass)
time.sleep(0.1)
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
Error:
bash-3.00# ./solpas7.py
File "./solpas7.py", line 4
def ChangePassword(user, pass):
^
SyntaxError: invalid syntax
EDIT : i changed pass to pa but not i am getting a lot and the password does not changes.
bash-3.00# ./solpas7.py
Traceback (most recent call last):
File "./solpas7.py", line 14, in ?
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
File "./solpas7.py", line 9, in ChangePassword
passwd.expect("password: ")
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1311, in expect
return self.expect_list(compiled_pattern_list, timeout, searchwindowsize)
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1325, in expect_list
return self.expect_loop(searcher_re(pattern_list), timeout, searchwindowsize )
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1409, in expect_loop
raise TIMEOUT (str(e) + 'n' + str(self))
pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().
<pexpect.spawn object at 0x80e306c>
version: 2.3 ($Revision: 399 $)
command: /usr/bin/passwd
args: ['/usr/bin/passwd', 'rajesh']
searcher: searcher_re:
0: re.compile("password: ")
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
after: pexpect.TIMEOUT
match: None
match_index: None
exitstatus: None
flag_eof: False
pid: 4683
child_fd: 3
closed: False
timeout: 30
delimiter: pexpect.EOF
logfile: None
logfile_read: None
logfile_send: None
maxread: 2000
ignorecase: False
searchwindowsize: None
delaybeforesend: 0.05
delayafterclose: 0.1
delayafterterminate: 0.1
python
add a comment |
I am trying to learn python to change users password non-interactively but nothing seems to be working.pexepect
module of python seems promising, so I am just trying to use it.
This tutorial is nice but it does not work.
There's lots of code on Internet regarding this but none of them seems to work.
And nor does my code:
#!/usr/bin/python
import pexpect
import time
def ChangePassword(user, pass):
passwd = pexpect.spawn("/usr/bin/passwd %s" % user)
for x in xrange(2):
# wait for password: to come out of passwd's stdout
passwd.expect("password: ")
# send pass to passwd's stdin
passwd.sendline(pass)
time.sleep(0.1)
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
Error:
bash-3.00# ./solpas7.py
File "./solpas7.py", line 4
def ChangePassword(user, pass):
^
SyntaxError: invalid syntax
EDIT : i changed pass to pa but not i am getting a lot and the password does not changes.
bash-3.00# ./solpas7.py
Traceback (most recent call last):
File "./solpas7.py", line 14, in ?
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
File "./solpas7.py", line 9, in ChangePassword
passwd.expect("password: ")
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1311, in expect
return self.expect_list(compiled_pattern_list, timeout, searchwindowsize)
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1325, in expect_list
return self.expect_loop(searcher_re(pattern_list), timeout, searchwindowsize )
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1409, in expect_loop
raise TIMEOUT (str(e) + 'n' + str(self))
pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().
<pexpect.spawn object at 0x80e306c>
version: 2.3 ($Revision: 399 $)
command: /usr/bin/passwd
args: ['/usr/bin/passwd', 'rajesh']
searcher: searcher_re:
0: re.compile("password: ")
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
after: pexpect.TIMEOUT
match: None
match_index: None
exitstatus: None
flag_eof: False
pid: 4683
child_fd: 3
closed: False
timeout: 30
delimiter: pexpect.EOF
logfile: None
logfile_read: None
logfile_send: None
maxread: 2000
ignorecase: False
searchwindowsize: None
delaybeforesend: 0.05
delayafterclose: 0.1
delayafterterminate: 0.1
python
pass
is a reserved keyword ;) Using something else will at least remove the syntax error.
– akaIDIOT
Jan 30 '13 at 11:41
add a comment |
I am trying to learn python to change users password non-interactively but nothing seems to be working.pexepect
module of python seems promising, so I am just trying to use it.
This tutorial is nice but it does not work.
There's lots of code on Internet regarding this but none of them seems to work.
And nor does my code:
#!/usr/bin/python
import pexpect
import time
def ChangePassword(user, pass):
passwd = pexpect.spawn("/usr/bin/passwd %s" % user)
for x in xrange(2):
# wait for password: to come out of passwd's stdout
passwd.expect("password: ")
# send pass to passwd's stdin
passwd.sendline(pass)
time.sleep(0.1)
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
Error:
bash-3.00# ./solpas7.py
File "./solpas7.py", line 4
def ChangePassword(user, pass):
^
SyntaxError: invalid syntax
EDIT : i changed pass to pa but not i am getting a lot and the password does not changes.
bash-3.00# ./solpas7.py
Traceback (most recent call last):
File "./solpas7.py", line 14, in ?
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
File "./solpas7.py", line 9, in ChangePassword
passwd.expect("password: ")
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1311, in expect
return self.expect_list(compiled_pattern_list, timeout, searchwindowsize)
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1325, in expect_list
return self.expect_loop(searcher_re(pattern_list), timeout, searchwindowsize )
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1409, in expect_loop
raise TIMEOUT (str(e) + 'n' + str(self))
pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().
<pexpect.spawn object at 0x80e306c>
version: 2.3 ($Revision: 399 $)
command: /usr/bin/passwd
args: ['/usr/bin/passwd', 'rajesh']
searcher: searcher_re:
0: re.compile("password: ")
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
after: pexpect.TIMEOUT
match: None
match_index: None
exitstatus: None
flag_eof: False
pid: 4683
child_fd: 3
closed: False
timeout: 30
delimiter: pexpect.EOF
logfile: None
logfile_read: None
logfile_send: None
maxread: 2000
ignorecase: False
searchwindowsize: None
delaybeforesend: 0.05
delayafterclose: 0.1
delayafterterminate: 0.1
python
I am trying to learn python to change users password non-interactively but nothing seems to be working.pexepect
module of python seems promising, so I am just trying to use it.
This tutorial is nice but it does not work.
There's lots of code on Internet regarding this but none of them seems to work.
And nor does my code:
#!/usr/bin/python
import pexpect
import time
def ChangePassword(user, pass):
passwd = pexpect.spawn("/usr/bin/passwd %s" % user)
for x in xrange(2):
# wait for password: to come out of passwd's stdout
passwd.expect("password: ")
# send pass to passwd's stdin
passwd.sendline(pass)
time.sleep(0.1)
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
Error:
bash-3.00# ./solpas7.py
File "./solpas7.py", line 4
def ChangePassword(user, pass):
^
SyntaxError: invalid syntax
EDIT : i changed pass to pa but not i am getting a lot and the password does not changes.
bash-3.00# ./solpas7.py
Traceback (most recent call last):
File "./solpas7.py", line 14, in ?
ChangePassword('rajesh', 'bar') # changes user "foo"'s password to "bar"
File "./solpas7.py", line 9, in ChangePassword
passwd.expect("password: ")
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1311, in expect
return self.expect_list(compiled_pattern_list, timeout, searchwindowsize)
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1325, in expect_list
return self.expect_loop(searcher_re(pattern_list), timeout, searchwindowsize )
File "/usr/lib/python2.4/site-packages/pexpect.py", line 1409, in expect_loop
raise TIMEOUT (str(e) + 'n' + str(self))
pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().
<pexpect.spawn object at 0x80e306c>
version: 2.3 ($Revision: 399 $)
command: /usr/bin/passwd
args: ['/usr/bin/passwd', 'rajesh']
searcher: searcher_re:
0: re.compile("password: ")
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
after: pexpect.TIMEOUT
match: None
match_index: None
exitstatus: None
flag_eof: False
pid: 4683
child_fd: 3
closed: False
timeout: 30
delimiter: pexpect.EOF
logfile: None
logfile_read: None
logfile_send: None
maxread: 2000
ignorecase: False
searchwindowsize: None
delaybeforesend: 0.05
delayafterclose: 0.1
delayafterterminate: 0.1
python
python
edited Jan 30 '13 at 11:50
munish
asked Jan 30 '13 at 11:38
munishmunish
1,578124171
1,578124171
pass
is a reserved keyword ;) Using something else will at least remove the syntax error.
– akaIDIOT
Jan 30 '13 at 11:41
add a comment |
pass
is a reserved keyword ;) Using something else will at least remove the syntax error.
– akaIDIOT
Jan 30 '13 at 11:41
pass
is a reserved keyword ;) Using something else will at least remove the syntax error.– akaIDIOT
Jan 30 '13 at 11:41
pass
is a reserved keyword ;) Using something else will at least remove the syntax error.– akaIDIOT
Jan 30 '13 at 11:41
add a comment |
2 Answers
2
active
oldest
votes
You can't use pass
as a variable name. It's a reserved keyword.
Edit:
pexpect is waiting for the string "password: "
but as you can tell from the error message passwd
outputs "New Password: "
(note the capital p) on your system.
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
Instead of passwd.expect("password: ")
you need to use passwd.expect("Password: ")
.
this is what i did just nowbash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the stringNew Password:
and Re-enter new Password:`
– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
add a comment |
You can also use this to make your search case insensitive:
passwd.expect('(?i)password:')
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't use pass
as a variable name. It's a reserved keyword.
Edit:
pexpect is waiting for the string "password: "
but as you can tell from the error message passwd
outputs "New Password: "
(note the capital p) on your system.
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
Instead of passwd.expect("password: ")
you need to use passwd.expect("Password: ")
.
this is what i did just nowbash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the stringNew Password:
and Re-enter new Password:`
– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
add a comment |
You can't use pass
as a variable name. It's a reserved keyword.
Edit:
pexpect is waiting for the string "password: "
but as you can tell from the error message passwd
outputs "New Password: "
(note the capital p) on your system.
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
Instead of passwd.expect("password: ")
you need to use passwd.expect("Password: ")
.
this is what i did just nowbash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the stringNew Password:
and Re-enter new Password:`
– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
add a comment |
You can't use pass
as a variable name. It's a reserved keyword.
Edit:
pexpect is waiting for the string "password: "
but as you can tell from the error message passwd
outputs "New Password: "
(note the capital p) on your system.
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
Instead of passwd.expect("password: ")
you need to use passwd.expect("Password: ")
.
You can't use pass
as a variable name. It's a reserved keyword.
Edit:
pexpect is waiting for the string "password: "
but as you can tell from the error message passwd
outputs "New Password: "
(note the capital p) on your system.
buffer (last 100 chars): New Password:
before (last 100 chars): New Password:
Instead of passwd.expect("password: ")
you need to use passwd.expect("Password: ")
.
edited Jan 30 '13 at 13:47
answered Jan 30 '13 at 11:43
lukadlukad
10.4k32944
10.4k32944
this is what i did just nowbash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the stringNew Password:
and Re-enter new Password:`
– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
add a comment |
this is what i did just nowbash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the stringNew Password:
and Re-enter new Password:`
– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
this is what i did just now
bash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
this is what i did just now
bash-3.00# passwd rajesh New Password: Re-enter new Password: passwd: password successfully changed for rajesh
– munish
Jan 30 '13 at 13:44
is it looking for the string
New Password:
and Re-enter new Password:`– munish
Jan 30 '13 at 13:45
is it looking for the string
New Password:
and Re-enter new Password:`– munish
Jan 30 '13 at 13:45
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
no i just used the usual passwd command on command line
– munish
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
See my answer. I just updated it.
– lukad
Jan 30 '13 at 13:46
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
,thanks a lot, it works. i need to learn a lot more
– munish
Jan 30 '13 at 13:49
add a comment |
You can also use this to make your search case insensitive:
passwd.expect('(?i)password:')
add a comment |
You can also use this to make your search case insensitive:
passwd.expect('(?i)password:')
add a comment |
You can also use this to make your search case insensitive:
passwd.expect('(?i)password:')
You can also use this to make your search case insensitive:
passwd.expect('(?i)password:')
answered Nov 13 '18 at 18:11
D.FitzD.Fitz
34
34
add a comment |
add a comment |
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pass
is a reserved keyword ;) Using something else will at least remove the syntax error.– akaIDIOT
Jan 30 '13 at 11:41