How can I count ids in splunk logs in one line with regex
I have log like:
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [512205885, 512112460, 512369891, 512316786, 58587803, 506882296]
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [514348564, 506722271, 513844106, 513725157]
Segment 5bbdfd69bbdd3c685a21129b : UserMap is [502062935]
I want the stats where I can see number of ids in userMap with respect to the segment. like:
5bbdf7b8bbdd3c685a2110bf - 6
5bbdf7b8bbdd3c685a2110bf - 4
5bbdfd69bbdd3c685a21129b - 1
splunk splunk-query
asked Nov 11 at 8:54
Gaurav Yadav
32
add a comment |
I have log like:
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [512205885, 512112460, 512369891, 512316786, 58587803, 506882296]
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [514348564, 506722271, 513844106, 513725157]
Segment 5bbdfd69bbdd3c685a21129b : UserMap is [502062935]
I want the stats where I can see number of ids in userMap with respect to the segment. like:
5bbdf7b8bbdd3c685a2110bf - 6
5bbdf7b8bbdd3c685a2110bf - 4
5bbdfd69bbdd3c685a21129b - 1
splunk splunk-query
asked Nov 11 at 8:54
Gaurav Yadav
32
add a comment |
I have log like:
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [512205885, 512112460, 512369891, 512316786, 58587803, 506882296]
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [514348564, 506722271, 513844106, 513725157]
Segment 5bbdfd69bbdd3c685a21129b : UserMap is [502062935]
I want the stats where I can see number of ids in userMap with respect to the segment. like:
5bbdf7b8bbdd3c685a2110bf - 6
5bbdf7b8bbdd3c685a2110bf - 4
5bbdfd69bbdd3c685a21129b - 1
splunk splunk-query
asked Nov 11 at 8:54
Gaurav Yadav
32
I have log like:
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [512205885, 512112460, 512369891, 512316786, 58587803, 506882296]
Segment 5bbdf7b8bbdd3c685a2110bf : UserMap is [514348564, 506722271, 513844106, 513725157]
Segment 5bbdfd69bbdd3c685a21129b : UserMap is [502062935]
I want the stats where I can see number of ids in userMap with respect to the segment. like:
5bbdf7b8bbdd3c685a2110bf - 6
5bbdf7b8bbdd3c685a2110bf - 4
5bbdfd69bbdd3c685a21129b - 1
splunk splunk-query
splunk splunk-query
asked Nov 11 at 8:54
Gaurav Yadav
32
asked Nov 11 at 8:54
Gaurav Yadav
32
asked Nov 11 at 8:54
Gaurav Yadav
32
asked Nov 11 at 8:54
Gaurav Yadav
32
asked Nov 11 at 8:54
Gaurav Yadav
32
32
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think you can't do it all with regex, but this search should get you goingin the right direction.
<your base search> | rex "Segment (?<Segment>[^:]+)"
| rex max_match=0 "UserMap is [(?<id>d+)"
| idCount=mvcount(id) | table Segment idCount
answered Nov 11 at 14:40
RichG
69148
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53247181%2fhow-can-i-count-ids-in-splunk-logs-in-one-line-with-regex%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think you can't do it all with regex, but this search should get you goingin the right direction.
<your base search> | rex "Segment (?<Segment>[^:]+)"
| rex max_match=0 "UserMap is [(?<id>d+)"
| idCount=mvcount(id) | table Segment idCount
answered Nov 11 at 14:40
RichG
69148
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
add a comment |
I think you can't do it all with regex, but this search should get you goingin the right direction.
<your base search> | rex "Segment (?<Segment>[^:]+)"
| rex max_match=0 "UserMap is [(?<id>d+)"
| idCount=mvcount(id) | table Segment idCount
answered Nov 11 at 14:40
RichG
69148
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
add a comment |
I think you can't do it all with regex, but this search should get you goingin the right direction.
<your base search> | rex "Segment (?<Segment>[^:]+)"
| rex max_match=0 "UserMap is [(?<id>d+)"
| idCount=mvcount(id) | table Segment idCount
answered Nov 11 at 14:40
RichG
69148
I think you can't do it all with regex, but this search should get you goingin the right direction.
<your base search> | rex "Segment (?<Segment>[^:]+)"
| rex max_match=0 "UserMap is [(?<id>d+)"
| idCount=mvcount(id) | table Segment idCount
answered Nov 11 at 14:40
RichG
69148
answered Nov 11 at 14:40
RichG
69148
answered Nov 11 at 14:40
RichG
69148
answered Nov 11 at 14:40
RichG
69148
69148
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
add a comment |
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
thank a lot @RichG
– Gaurav Yadav
Nov 13 at 6:43
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53247181%2fhow-can-i-count-ids-in-splunk-logs-in-one-line-with-regex%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
